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NotesPhysics HLTopic 1.5Lorentz transformations
Back to Physics HL Topics
1.5.39 min read

Lorentz transformations (Physics HL)

IB Physics · Unit 1

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Contents

  1. 1Why we need a new factor
  2. 2The Lorentz factor γ
  3. 3Time dilation — moving clocks run slow
  4. 4Length contraction — moving objects shrink
  5. 5Adding velocities — and the exam
The big idea: To keep the speed of light c the same for everyone, time and length stretch and shrink with motion. Everything below is built from one number: the Lorentz factor γ (gamma).
Clocks on airliners: In 1971 atomic clocks were flown round the world on airliners and compared with identical clocks left on the ground. They came back out of step by tens to hundreds of nanoseconds: part of the difference is gravity, and part is time dilation, because moving clocks run slow.
Lorentz transformations: The Lorentz transformations are the rules that link what one observer measures to what a moving observer measures.
Given in the data booklet. For two events use the differences: Δx′ = γ(Δx − vΔt) and Δt′ = γ(Δt − vΔx/c²).
position and time of the event in frame S′ (m, s)
position and time of the event in frame S (m, s)
velocity of S′ relative to S, along x (m s⁻¹)
Lorentz factor for v
Reading the Lorentz equations: At low speed γ ≈ 1 and vx/c² ≈ 0, so they become the Galilean x′ = x − vt and t′ = t.

The vx/c² term is new: two events at different places that are simultaneous in S (Δt = 0) are not simultaneous in S′.
IB-style questionDetermine[5 marks]

A spacecraft passes a space station at 0.60c (γ = 1.25). Lamps at the rear R and the front F of the station, 1500 m apart, flash at the same instant in the station frame. The spacecraft moves from R towards F. Determine, for the spacecraft frame, (a) the distance between the flashes, (b) the time between them and (c) which flash comes first.

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Two pieces of jargon: Proper time Δt₀ — the time between two events measured by a clock that is present at both events (it is the shortest possible time).

Proper length L₀ — the length of an object measured in the frame where it is at rest (it is the longest possible length).

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Every relativistic effect is scaled by the Lorentz factor γ. It depends only on the speed v as a fraction of c. At everyday speeds γ ≈ 1 (relativity hides itself); as v approaches c, γ shoots up toward infinity.

Given in the data booklet. Notice γ is always greater than or equal to 1 — it can never be less than 1.
Lorentz factor (no unit, ≥ 1)
speed of the moving frame (m s⁻¹)
speed of light in a vacuum (3.0 × 10⁸ m s⁻¹)
IB-style questionCalculate[2 marks]

A spaceship moves past Earth at v = 0.80c. Find its Lorentz factor γ.

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Common slip: Keep speeds as a fraction of c. Writing v = 0.80c means v/c = 0.80, so the term is 0.80², not (0.80 × 3 × 10⁸)². Working in units of c keeps the numbers clean.

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Moving clocks tick slowly: A clock that is moving relative to you ticks slower than your own. The proper time Δt₀ (measured on the moving clock) is stretched by γ to give the longer time Δt that you measure.
Given in the data booklet. Since γ ≥ 1, the measured time Δt is always ≥ the proper time Δt₀.
time measured by the observer who sees the clock moving (s)
proper time — measured on the moving clock itself (s)
Lorentz factor (no unit)
Where Δt = γΔt₀ comes from: Put a clock at rest in S′, so its two ticks are at the same place there: Δx′ = 0, and the time between them is the proper time Δt₀ = Δt′.

The Lorentz equations run the other way too (swap the frames, v becomes −v): Δt = γ(Δt′ + vΔx′/c²) = γΔt₀.
IB-style questionDetermine[2 marks]

The spaceship above (v = 0.80c, γ = 1.67) carries a clock that measures a proper time Δt₀ = 2.0 s for an event on board. What time does an Earth observer measure for that same event?

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Lengths squeeze along the motion: An object that moves past you is measured to be shorter along its direction of motion than its proper length.

What changes

  • Only the dimension along the motion contracts.
  • Width and height are unchanged.
  • The proper length L₀ is divided by γ.
Given in the data booklet. Since γ ≥ 1, the measured length L is always ≤ the proper length L₀.
length measured by the observer who sees it moving (m)
proper length — measured in the object's rest frame (m)
Lorentz factor (no unit)
IB-style questionDetermine[2 marks]

The spaceship (v = 0.80c, γ = 1.67) has a proper length L₀ = 100 m. What length does an Earth observer measure as it flies past?

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The evidence: muons

Muons made 10 km up reach the ground: in the Earth frame their clocks run slow; in the muon frame the atmosphere is contracted
The muon experiment: evidence for time dilation and length contraction.
One experiment, two explanations: The Earth observer explains the muons with time dilation (their clocks run slow); the muon explains them with length contraction (the atmosphere is thinner). Both use the same γ and agree on how many muons reach the ground.

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You cannot just add speeds: At low speeds you simply add velocities (0.5 + 0.5 = 1.0). Near c that breaks the cosmic speed limit, so relativity uses a velocity-addition rule.
Always below c: The denominator keeps every result below c: you can never reach the speed of light by adding speeds.
Given in the data booklet. u and v are measured in one frame; u′ is the velocity seen in the frame moving at v.
velocity of the object in the second frame (m s⁻¹)
velocity of the object in the first frame (m s⁻¹)
velocity of the second frame relative to the first (m s⁻¹)
speed of light in a vacuum
IB-style questionDetermine[2 marks]

As seen from Earth, two spacecraft head straight toward each other, each moving at 0.50c. How fast does one ship measure the other to approach?

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How this is tested — Lorentz transformations are HL only (A.5):

Paper 1A

  • A one-step 'find γ' or 'which is the proper time?'
  • 'Is the result above or below c?'

Paper 2

  • Determine a dilated time, a contracted length, or a relative speed.
  • Often set for a muon or a fast spacecraft.
The classic trap: Always find γ first, then decide: multiply by γ for time (Δt = γΔt₀), divide by γ for length (L = L₀/γ). The proper quantity is the one measured in the rest frame.
Three easy marks: (1) Always find γ first. (2) Identify the proper quantity: proper time is on the moving clock, proper length is in the rest frame. (3) Multiply by γ for time (Δt = γΔt₀); divide by γ for length (L = L₀/γ).
IB-style questionDetermine[4 marks]

A probe travels past a space station at v = 0.60c. A signal lamp on the probe flashes with a proper period of 5.0 s. Determine (a) the Lorentz factor and (b) the period of the flashes as measured by the station.

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what is meant by proper time. [1 mark]

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