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NotesPhysics HLTopic 5.2Wave–particle duality
Back to Physics HL Topics
5.2.17 min read

Wave–particle duality (Physics HL)

IB Physics · Unit 5

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Contents

  1. 1Light comes in packets
  2. 2The photoelectric effect
  3. 3The photoelectric equation
  4. 4Wave AND particle
  5. 5Compton scattering: photons have momentum
  6. 6In the exam
The big idea: Point a laser pointer at a screen and the light lands as a stream of tiny energy packets — photons — not a smooth flow.
Energy set by frequency: Each photon carries an energy fixed only by the light's frequency f, through E = hf.
Given in the data booklet — the energy of one photon (h is the Planck constant).
photon energy (J)
Planck constant, 6.63×10⁻³⁴ J s
frequency of the light (Hz)
IB-style questionCalculate[2 marks]

Find the energy of a photon of light with frequency 5.0 × 10¹⁴ Hz.

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Light knocks electrons out of metal: Shine light on a metal and it can eject electrons. Four surprising results prove light is particle-like.

The surprising bits

  • There is a threshold frequency — below it, no electrons come out, however bright the light.
  • The electrons' maximum kinetic energy depends on the frequency, not the brightness.
  • Brighter light (more photons) ejects more electrons, but not faster ones.
  • Emission is instant.
Why this needs photons: One electron absorbs one photon. If that photon's energy hf is too small, the electron can't escape — no matter how many photons arrive. A smooth wave couldn't explain a sharp threshold.

Wave model predicts

  • Any frequency works if the light is bright enough
  • Brighter light gives faster electrons
  • Dim light: a delay while energy builds up

What is observed

  • Below f₀ nothing, however bright
  • Emax depends on f only, not brightness
  • Emission is instant, even in dim light

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Some of the photon's energy is used just to free the electron from the metal — the work function Φ. Whatever is left becomes the electron's maximum kinetic energy.

Given in the data booklet — the photoelectric equation.
maximum kinetic energy of an ejected electron (J)
energy of the incoming photon (J)
work function — energy to free an electron (J)
IB-style questionCalculate[2 marks]

Light of frequency 8.0 × 10¹⁴ Hz hits a metal whose work function is 3.0 × 10⁻¹⁹ J. Find the maximum kinetic energy of the ejected electrons.

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The photoelectric effect, step by step

A photon freeing an electron from a metal, the maximum kinetic energy against frequency graph for two metals, and the stopping voltage
E_max = hf − Φ: a straight line of gradient h from the threshold frequency.
Stopping voltage: Make the collector negative and raise the pd until the current just stops: that stopping voltage Vs halts even the fastest electrons, so eVs = Emax = hf − Φ. On a Vs–f graph the gradient is h/e.
Intensity counts photons: Intensity = (photons per second × hf) ÷ area. Double the wavelength and each photon carries half the energy; double the photon rate as well and the intensity is unchanged.
Two faces of light: Light shows both natures, depending on the experiment:

- wave behaviour — diffraction and interference (the double slit) - particle behaviour — the photoelectric effect (photons)

This is wave–particle duality. Neither picture alone is the whole story.

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A photon bounces off an electron: Fire X-rays at a target: the scattered X-rays have a longer wavelength. A photon has hit a free electron like one ball hitting another, handing it some energy and momentum.
The Compton shift. h/(mₑc) = 2.43 × 10⁻¹² m, the Compton wavelength. Its derivation is not required.
wavelength before and after scattering (m)
angle the photon is scattered through
electron mass, 9.11 × 10⁻³¹ kg
An X-ray photon scattering off an electron at rest through angle θ with a longer wavelength while the electron recoils
Δλ = (h/mₑc)(1 − cos θ): the photon behaves as a particle with momentum.
Why it is stronger evidence than the photoelectric effect: In the photoelectric effect the photon is simply absorbed. In Compton scattering it behaves as a particle in a collision, with momentum p = h/λ shared between photon and electron. The wave model predicts no change of wavelength at all.
Photons push: radiation pressure: Each photon carries momentum h/λ. A photon reflected straight back changes its momentum by 2h/λ (absorbed: h/λ). Force on a surface = photons per second × momentum change, and pressure = force ÷ area.

Worked example — X-rays scattered through 90°

X-rays of wavelength 7.10 × 10⁻¹¹ m are scattered by free electrons through 90°. Find the scattered wavelength and the kinetic energy given to the electron.

Solution

  1. At 90°, cos θ = 0:
  2. Scattered wavelength:
  3. Energy lost by the photon goes to the electron:

Final answer

λf = 7.34 × 10⁻¹¹ m; the electron gains about 9.3 × 10⁻¹⁷ J (about 580 eV).

How this is tested — quantum physics is HL only (E.2) and splits cleanly by paper:

Paper 1A

  • A quick E = hf.
  • Or 'what happens if you increase the intensity / frequency?'

Paper 2

  • Use Emax = hf − Φ for a maximum kinetic energy.
  • Or a threshold frequency (f₀ = Φ/h), or a stopping voltage.
The classic trap: Brightness changes the number of electrons; frequency changes their energy. Below the threshold frequency, nothing happens however bright the light.
Three easy marks: (1) Brightness changes the number of electrons; frequency changes their energy. (2) Below the threshold frequency, nothing happens. (3) Keep energies in joules (or convert eV with 1 eV = 1.60×10⁻¹⁹ J).
IB-style questionDetermine[2 marks]

A metal has a work function of 4.0 × 10⁻¹⁹ J. Determine the lowest frequency of light that will eject electrons from it.

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For two metal surfaces, the voltage needed to stop the fastest photoelectrons is measured at several frequencies and plotted.

one feature the two lines share and one that differs.
[2 marks]

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