The big idea: You wouldn't price a single sweet in millions of dollars — the unit would be absurdly big for the job. In the same way the joule (J) is far too big for the energy of one particle, so physicists use a smaller unit: the electronvolt (eV).
One electronvolt is the energy gained by one electron (charge e) when it is pushed through a potential difference of one volt.
That works out to a fixed amount of energy:
1 eV = 1.60 × 10⁻¹⁹ J
Spot it: The eV is just a unit of energy, like the joule — not a new kind of energy.
The number 1.60 × 10⁻¹⁹ is the elementary charge e in coulombs. That is no coincidence: energy = charge × voltage, so e coulombs × 1 volt = 1.60 × 10⁻¹⁹ J.
Bigger eV units: Like metres → kilometres, the eV has bigger cousins:
- 1 keV (kilo-electronvolt) = 10³ eV - 1 MeV (mega-electronvolt) = 10⁶ eV
Atomic-transition energies are a few eV; nuclear (decay, binding) energies are a few MeV.
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Everything rests on one given number: 1 eV = 1.60 × 10⁻¹⁹ J. To go each way:
The two directions
- eV → J: multiply by 1.60 × 10⁻¹⁹ (you have many eV, each worth a tiny number of joules)
- J → eV: divide by 1.60 × 10⁻¹⁹ (you are counting how many eV fit into the energy)
- the energy expressed in joules (J)
- the same energy expressed in electronvolts (eV)
- the joules in one electronvolt — the elementary charge e in coulombs
E (J) on top, E (eV) and 1.60 × 10⁻¹⁹ below. Cover the one you want: two side by side → multiply; one above the other → divide.
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An electron in an atom drops between two energy levels and emits a photon of energy 2.5 eV. Express this energy in joules.
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A nuclear decay releases 8.0 × 10⁻¹³ J of energy. Express this in MeV.
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How this is tested — the electronvolt is rarely its own question; it is the unit you answer in across Theme E and the fields topics:
Paper 1A
- Photon and transition energies are quoted in eV — convert to joules before using E = hf or E = hc/λ.
Paper 2
- A part often asks you to state, in eV, the energy of a particle, or quotes a nuclear energy in MeV.
The classic trap: Multiplying when you should divide: eV → J multiply by 1.60 × 10⁻¹⁹; J → eV divide.
Convert first, then use the formula: Planck's equation E = hf gives the energy in joules. If the answer is wanted in eV, work in joules, then divide by 1.60 × 10⁻¹⁹ at the end.
- energy of the photon (J)
- Planck constant, 6.63×10⁻³⁴ J s (given)
- frequency of the light (Hz)
- speed of light, 3.00×10⁸ m s⁻¹ (given)
- wavelength of the light (m)
An atom emits a photon of light of wavelength 4.4 × 10⁻⁷ m (violet light). Find the energy of the photon in electronvolts. (h = 6.63 × 10⁻³⁴ J s, c = 3.00 × 10⁸ m s⁻¹.)
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