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NotesMath AA HLTopic 5.13Repeated L'Hopital & rewriting forms
Back to Math AA HL Topics
5.13.21 min read

Repeated L'Hopital & rewriting forms

IB Mathematics: Analysis and Approaches • Unit 5

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Contents

  • Apply the rule again (and again)
  • Rewrite other forms as a fraction first
Still 0/0? Differentiate again: After one round of L'Hopital, substitute again.

If you get a number, stop — that's the limit. If you're back at 0/0 (or ∞/∞), the rule still applies: differentiate top and bottom a second time, and repeat as needed.

Each pass peels off one layer of the vanishing.

Stop the instant substitution gives a finite value — applying the rule when it's no longer 0/0 gives a wrong answer.

IB-style question — apply twice

Find the limit of (1 − cos x)/x² as x approaches 0.

Step by step

  1. Substitution: (1 − cos 0)/0 = 0/0, so use L'Hopital.
  2. First pass — top derivative sin x, bottom derivative 2x.
  3. Substitute again: sin 0 / 0 = 0/0 — STILL indeterminate, so apply again.
  4. Second pass — top derivative cos x, bottom derivative 2.
  5. Now substitution gives a number — stop.

Final answer

The limit is 1/2.

IB-style question — x sin x over (1 − cos x)

Find the limit of (x sin x)/(1 − cos x) as x approaches 0.

Step by step

  1. Substitution: (0·0)/(1 − 1) = 0/0, so L'Hopital applies.
  2. Top derivative (product rule): sin x + x cos x. Bottom derivative: sin x.
  3. Substitute again: (0 + 0)/0 = 0/0 — apply once more.
  4. Differentiate again. Top: cos x + (cos x − x sin x) = 2cos x − x sin x. Bottom: cos x.
  5. Substitute x = 0.

Final answer

The limit is 2.

L'Hopital only eats fractions: The rule needs a quotient that is 0/0 or ∞/∞. A product like 0·∞ isn't a fraction yet.

The fix: turn the product into a fraction. Write one factor over the reciprocal of the other:

f · g = f / (1/g).

Choose whichever way lands you in 0/0 (or ∞/∞). Then L'Hopital takes over.

IB-style question — a 0·∞ form

Find the limit of x ln x as x approaches 0 from the positive side.

Step by step

  1. As x → 0⁺: x → 0 and ln x → −∞, so this is the form 0·(−∞) — not yet a fraction.
  2. Rewrite as a fraction by putting ln x over 1/x.
  3. Now it's −∞/∞, so L'Hopital applies. Top derivative 1/x; bottom derivative −1/x².
  4. Simplify the complex fraction: (1/x)·(−x²) = −x.

Final answer

The limit is 0 — so x ln x → 0 as x → 0⁺.

Why simplify before re-substituting: After L'Hopital you often get a messy stacked fraction. Tidy it first (cancel, combine) before substituting — it's easier and avoids dividing-by-zero panics that the algebra would have cancelled anyway.

IB Exam Questions on Repeated L'Hopital & rewriting forms

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Practice Topic 5.13.2 QuestionsBrowse All Math AA HL Topics

How Repeated L'Hopital & rewriting forms Appears in IB Exams

Examiners use specific command terms when asking about this topic. Here's what to expect:

Define

Give the precise meaning of key terms related to Repeated L'Hopital & rewriting forms.

AO1
Describe

Give a detailed account of processes or features in Repeated L'Hopital & rewriting forms.

AO2
Explain

Give reasons WHY — cause and effect within Repeated L'Hopital & rewriting forms.

AO3
Evaluate

Weigh strengths AND limitations of approaches in Repeated L'Hopital & rewriting forms.

AO3
Discuss

Present arguments FOR and AGAINST with a balanced conclusion.

AO3

See the full IB Command Terms guide →

Related Math AA HL Topics

Continue learning with these related topics from the same unit:

5.1.1Derivative as gradient
5.10.1Reverse chain rule
5.10.2Substitution
5.11.1Definite integrals
View all Math AA HL topics

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5.13.1L'Hopital's rule: the 0/0 form
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Implicit differentiation5.14.1

11 practice questions on Repeated L'Hopital & rewriting forms

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