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NotesMath AA HLTopic 5.1Derivative as gradient
Back to Math AA HL Topics
5.1.13 min read

Derivative as gradient (Math AA HL)

IB Mathematics: Analysis and Approaches • Unit 5

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Contents

  • The gradient of a curve at a point
  • The derivative as a rate of change
  • Notation & the gradient function
  • Sign of the gradient
A curve's gradient is the gradient of its tangent: A straight line has one gradient everywhere.

A curve is different — its steepness changes.

The gradient at a point is defined as the gradient of the tangent (the line that just touches the curve there).

The derivative gives that gradient.

The tangent to y = x² at a point — its gradient is the derivative there. As the point moves, the tangent's gradient changes.

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IB-style question — the gradient changes

On the curve y = x², the gradient at (1, 1) is 2 and at (3, 9) it is 6.

Explain why a curve does not have a single gradient.

Step by step

  1. Compare the two gradients.
  2. So the steepness depends on where you are.

Final answer

Because the gradients differ (2 vs 6), the curve gets steeper as x increases — there is no single gradient, only a gradient at each point.

Tangent, not chord: The gradient at a point uses the tangent there — not a chord joining two separate points.

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How fast y changes as x changes: The derivative is also a rate of change: how fast y changes per unit of x, at an instant.

If y depends on time, the derivative is the instantaneous rate (e.g. speed = rate of change of distance).

IB-style question — interpret a rate

The volume V (litres) of water in a tank after t minutes has dV/dt = 12 at t = 5.

Interpret this value.

Step by step

  1. dV/dt is the rate V changes per minute.
  2. At t = 5 specifically.

Final answer

At t = 5 minutes, the water volume is increasing at 12 litres per minute.

Carry the units: A rate of change has units of (y-units) per (x-unit) — e.g. litres per minute, metres per second.

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f'(x) and dy/dx mean the gradient function: The derivative is written f'(x) ("f prime of x") or dy/dx.

It is itself a function — feed in an x and it returns the gradient there.

(How to find it is the next topic; here we just use it.)

IB-style question — gradient at a point

The gradient function of y = x² is f'(x) = 2x.

Find the gradient of the curve at x = 3.

Step by step

  1. Substitute x = 3 into the gradient function.
  2. Evaluate.

Final answer

The gradient at x = 3 is 6.

Gradient at a point = substitute into f'(x): To get a number, substitute the x-value into the gradient function f'(x).
Positive up, negative down, zero flat: The sign of f'(x) tells you the shape: f'(x) > 0 → the curve is increasing (going up); f'(x) < 0 → decreasing (going down); f'(x) = 0 → a stationary point (momentarily flat).

IB-style question — read the sign

For a function f, f'(2) = 5 and f'(−1) = −3.

State whether f is increasing or decreasing at each point.

Step by step

  1. At x = 2 the derivative is positive.
  2. At x = −1 the derivative is negative.

Final answer

Increasing at x = 2; decreasing at x = −1.

f'(x) = 0 → flat: A zero gradient means a stationary point — a peak, trough or a flat spot (explored in 5.8).

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The gradient function of a curve is f'(x) = 4x − 1. Find the gradient of the curve at x = 2. [2 marks]

Related Math AA HL Topics

Continue learning with these related topics from the same unit:

5.10.1Reverse chain rule
5.10.2Substitution
5.11.1Definite integrals
5.11.2Area between curves
View all Math AA HL topics

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