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NotesMath AA HLTopic 3.18Planes meeting & angles
Back to Math AA HL Topics
3.18.21 min read

Planes meeting & angles

IB Mathematics: Analysis and Approaches • Unit 3

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Contents

  • The line where two planes meet
  • Angles: planes use cosine, line-to-plane uses sine
Two walls meeting make a corner line: Two non-parallel planes share a whole line — think of two walls of a room meeting in a vertical edge.

To find that line you need a point on it and a direction.

Direction: the line lies in BOTH planes, so it's perpendicular to BOTH normals — that's exactly the cross product d = n₁ × n₂.

Point: pick a convenient value for one coordinate (often z = 0), then solve the two plane equations as a simple 2×2 system for the other two.
Direction = cross product of the two normals; point = solve the system with one variable fixed.

IB-style question — find the line of intersection

Two planes have equations Π₁: x + y + z = 6 and Π₂: x − y + 2z = 5.

Find a vector equation of their line of intersection.

Step by step

  1. Read off the normals from the coefficients.
  2. Direction = n₁ × n₂. Compute each component (i, j, k).
  3. Simplify the three components.
  4. Find one point: set z = 0, giving x + y = 6 and x − y = 5.
  5. Add the two equations: 2x = 11 ⇒ x = 5.5, then y = 0.5.
  6. Write the line with that point and the direction.

Final answer

r = (11/2, 1/2, 0) + λ(3, −1, −2). (Any point on the line and any nonzero multiple of (3, −1, −2) is acceptable.)

Watch what the angle is measured FROM: Angle between two planes = angle between their normals:

cos θ = |n₁·n₂| / (|n₁||n₂|). We take the absolute value so we report the acute angle.

Angle between a line and a plane is the angle to the flat surface, not to the normal. The normal sticks up at 90° to the surface, so the line-to-surface angle and the line-to-normal angle add to 90° — that swaps cosine for sine:

sin θ = |d·n| / (|d||n|). Use the line's direction d and the plane's normal n.
Plane–plane: cosine of the normals. Line–plane: sine (because the surface is 90° from the normal).

IB-style question — angle between two planes

Find the acute angle between the planes Π₁: x + 2y + 2z = 1 and Π₂: 2x − 2y + z = 3.

Step by step

  1. Read off the normals.
  2. Dot product n₁·n₂.
  3. The dot product is 0, so the normals are perpendicular.
  4. cos θ = 0 means θ = 90°.

Final answer

The planes are perpendicular: the angle is 90°. (Here |n₁| = |n₂| = 3.)

IB-style question — angle between a line and a plane

Find the acute angle between the line r = (1, 0, 2) + λ(2, 1, 2) and the plane x + 2y + 2z = 7.

Step by step

  1. Direction of the line, and normal of the plane.
  2. Use SINE (line-to-surface). First d·n.
  3. Magnitudes: |d| = √(4+1+4) = 3, |n| = √(1+4+4) = 3.
  4. Apply the formula.
  5. Take the inverse sine.

Final answer

θ ≈ 62.7° (sin θ = 8/9). Using sine — not cosine — because the angle is to the surface.

IB Exam Questions on Planes meeting & angles

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How Planes meeting & angles Appears in IB Exams

Examiners use specific command terms when asking about this topic. Here's what to expect:

Define

Give the precise meaning of key terms related to Planes meeting & angles.

AO1
Describe

Give a detailed account of processes or features in Planes meeting & angles.

AO2
Explain

Give reasons WHY — cause and effect within Planes meeting & angles.

AO3
Evaluate

Weigh strengths AND limitations of approaches in Planes meeting & angles.

AO3
Discuss

Present arguments FOR and AGAINST with a balanced conclusion.

AO3

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Related Math AA HL Topics

Continue learning with these related topics from the same unit:

3.1.1Distance & midpoint (3D)
3.1.2Volume & surface area
3.1.3Angles in 3D
3.1.4Solids in 3D coordinates
View all Math AA HL topics

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3.18.1Where a line meets a plane
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Populations & samples4.1.1

11 practice questions on Planes meeting & angles

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