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NotesMath AA HLTopic 3.1Volume & surface area
Back to Math AA HL Topics
3.1.22 min read

Volume & surface area

IB Mathematics: Analysis and Approaches • Unit 3

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Contents

  • The solids and their formulas
  • Finding a volume
  • Surface area (curved & slant)
  • Composite solids
  • Hollow solids — a pipe
  • Working backwards to a dimension
Know the booklet formulas: Volume and surface-area formulas for the standard solids are in the formula booklet — but you must know which to use and read the right radius/height.

[Diagram: math-solid-volume] - Available in full study mode

What's given vs what you memorise: ✓ in the booklet — you can look it up in the exam.

★ not given — memorise it, or build it from the given parts (add a base circle, halve a sphere, sum the faces…).
SolidVolumeSurface area
Cuboid ✓ ★
Cylinder ✓curved ✓; closed adds ★
Cone ✓curved ✓; total adds base ★
Sphere ✓ ✓
Hemisphere ★ ★ (½ sphere + flat base)
Pyramid ✓ (A = base area) ★
Prism ✓sum of all faces ★

[Diagram: math-base-areas] - Available in full study mode

ShapeArea — also givenWhere you use it
Parallelogramcross-section of a slanted prism
Trianglethe base A of a triangular prism / a pyramid
Trapezoidcross-section of a trough / trapezoidal prism
Circlea cylinder or cone base, or a hemisphere's flat face
Circle — rimthe distance around the edge (e.g. how far a wheel rolls in one turn)

[Diagram: math-prism-cross-section] - Available in full study mode

Pick the formula, substitute, evaluate: Identify the solid, read off the radius and height, then substitute. Keep π exact unless told to round.

IB-style question — volume of a cone

Find the volume of a cone with base radius 3 and height 4.

Step by step

  1. Write the general volume formula for a cone, where r is the base radius and h is the perpendicular height.
  2. Substitute the question's numbers: r = 3 and h = 4.
  3. Evaluate (only r is squared).

Final answer

V = 12π ≈ 37.7.

[Diagram: math-solid-volume] - Available in full study mode

Square the radius, not the height: In V = ⅓πr²h, only r is squared. A common slip is squaring h too.

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Add up every face: Total surface area adds all the surfaces. A cone's slant uses l = √(r² + h²); a closed cylinder is 2 circles + the curved wrap (2πr² + 2πrh).

IB-style question — cone surface area

A cone has base radius 6 and height 8. Find its total surface area.

Step by step

  1. The slant height l is the sloping distance from the rim to the apex. Find it with the general formula.
  2. Substitute r = 6 and h = 8.
  3. Write the general total surface area of a cone: the circular base plus the curved (lateral) surface.
  4. Substitute r = 6 and l = 10.
  5. Evaluate.

Final answer

A = 96π ≈ 302.

[Diagram: math-solid-volume] - Available in full study mode

IB-style question — surface area of a solid hemisphere

A solid hemisphere has radius 6. Find its total surface area.

Step by step

  1. Build it from what the booklet gives. The booklet has the whole sphere's surface (4πr²) and the area of a circle (πr²) — a solid hemisphere is the curved HALF of the sphere plus one flat circular lid.
  2. Add the two given pieces.
  3. Substitute r = 6.

Final answer

A = 108π ≈ 339 (curved ½-sphere 2πr², given, + flat circle πr², given).

[Diagram: math-solid-volume] - Available in full study mode

Open or closed?: Read whether a surface is included — an open cylinder (no lid) drops one circle; a hemisphere's flat face is one extra circle.
Add the pieces (or subtract a hole): For a solid made of parts (e.g. a cylinder topped by a hemisphere), add the volumes. For surface area, add only the exposed faces (a shared join is not counted twice).

[Diagram: math-composite-solid] - Available in full study mode

IB-style question — cylinder + hemisphere

A solid is a cylinder (r = 3, h = 10) with a hemisphere (r = 3) on top. Find its volume.

Step by step

  1. The total volume is the cylinder plus the hemisphere. State both general formulas (a hemisphere is half a sphere).
  2. Substitute the cylinder's r = 3, h = 10 and the hemisphere's r = 3.
  3. Evaluate each piece and add.

Final answer

V = 90π + 18π = 108π ≈ 339.

IB-style question — surface area of a capsule (cylinder + 2 hemispheres)

A capsule is a cylinder of radius r and height h with a hemisphere on each end.

Find a formula for its total surface area S.

Step by step

  1. The curved side of the cylinder is 2πrh. The two hemispheres are domes only — their flat faces sit against the cylinder, so they aren't exposed.
  2. Two hemisphere domes = one whole sphere's surface.
  3. Add the exposed surfaces (no flat circles — they're internal joins).

Final answer

S = 2πrh + 4πr².

[Diagram: math-capsule] - Available in full study mode

Don't double-count the join: When adding surface areas, the circle where two pieces meet is internal — leave it out.

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Hollow cylinder (a pipe): A pipe is a cylinder with a smaller cylinder removed (the hole). Picture the ring-shaped end: outer radius R, inner radius r.

Volume of metal = big cylinder − hole = .

Surface area = — the outer curved wall, the inner curved wall, and the two ring-shaped ends.

[Diagram: math-hollow-cylinder] - Available in full study mode

IB-style question — volume of metal in a pipe

A metal pipe is a hollow cylinder with outer radius 5 cm, inner radius 3 cm and length 20 cm.

Find the volume of metal in the pipe.

Step by step

  1. The metal is the outer cylinder with the inner cylinder (the hole) taken out — so subtract the two volumes. Both share the same length h, so factorise.
  2. Substitute R = 5, r = 3 and h = 20.
  3. Evaluate.

Final answer

V = 320π ≈ 1005 cm³ of metal.

Factorise before you substitute: π(R² − r²)h with the numbers put in last is much quicker than working out πR²h and πr²h separately. The two cylinders share the same length h, so factor it out — and remember it's R² − r², not (R − r)².
Given the volume, solve for r or h: Set the formula equal to the given volume (or area) and solve for the unknown dimension — often a cube root or a square root.

[Diagram: math-solid-volume] - Available in full study mode

IB-style question — find the radius

A sphere has volume 36π. Find its radius.

Step by step

  1. State the general volume formula for a sphere.
  2. Set it equal to the given volume 36π.
  3. Divide both sides by π (it cancels), then multiply by ¾ to isolate r³.
  4. Cube-root both sides.

Final answer

r = 3.

Cancel the π: If π appears on both sides, divide it out first — the numbers get much friendlier.

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Find the volume of a cylinder with base radius 5 and height 12. [2 marks]

Related Math AA HL Topics

Continue learning with these related topics from the same unit:

3.1.1Distance & midpoint (3D)
3.1.3Angles in 3D
3.1.4Solids in 3D coordinates
3.10.1Compound angle identities
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