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NotesESS HLTopic 2.2Ecological efficiency
Back to ESS HL Topics
2.2.285 min read

Ecological efficiency (ESS HL)

IB Environmental Systems and Societies • Unit 2

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Contents

  • Ecological efficiency at Higher Level
  • What ecological efficiency is
  • Working it out from data
  • Why 10% is not a rule
  • Exam-style question
Ecological efficiency at Higher Level: An HL-only statement: the percentage of energy passed from one trophic level to the next, worked out from real data, and why the famous 10% is only a rough guide.

Practise this as you read

  • Calculate ecological efficiency from a food chain, formula first.
  • Explain why efficiency differs between species, levels and ecosystems.

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How much energy is passed on: Ecological efficiency tells you how much of a level's energy reaches the level above it.

It is always worked out between two neighbouring levels, from the energy each one receives.

The formula: Ecological efficiency (%) = (energy passed on to the next level ÷ energy received by this level) × 100

The points to remember

  • Ecological efficiency = the percentage of the energy received by one trophic level that is passed on to the next.
  • Formula: (energy passed to the next level ÷ energy received by this level) × 100.
  • It is always low, because energy is lost at every step: heat from respiration, parts not eaten, faeces (2.2.12).
  • Energy not passed on is not destroyed: it leaves as heat or goes to the decomposers.
  • Low efficiency is why food chains have only 4 or 5 levels (2.2.14).
Remember it as: Up the chain: top over bottom, times 100.

Example: if zooplankton receive 1,000 kJ and pass 60 kJ on to the fish that eat them, the ecological efficiency is (60 ÷ 1,000) × 100 = 6%.

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Questions give a food chain with the energy at each level, often beside a column you do not need. Four steps work every time.

Working it out from data

  • Find the two levels the question names, and read their energy values.
  • Divide the higher level by the lower level: the one that receives by the one that gives.
  • Multiply by 100 and add the % sign.
  • Both values must be in the same units; ignore any other column, such as a pollutant.
  • The answer is always below 100%; above 100% means the division is the wrong way round.
Four trophic levels at Silver Springs, Florida, in kJ per m² per year: producers 87,100; herbivores 14,100; carnivores 1,600; top carnivores 90.
Real data from a classic energy study of a river.
Worked example: Silver Springs: Producers to herbivores = (14,100 ÷ 87,100) × 100 = 16%.

Herbivores to carnivores = (1,600 ÷ 14,100) × 100 = 11%.

Carnivores to top carnivores = (90 ÷ 1,600) × 100 = 6%.

Three steps in one river give three different percentages, and none of them is exactly 10%.

Common slips: Dividing the lower level by the higher one gives an answer over 100%, which is impossible. Subtracting the two values gives the energy lost, not the efficiency.

The '10% rule' is often taught as a law, but it is not: the real percentage changes from place to place and from step to step.

Why 10% is not a rule

  • Efficiency varies between ecosystems, between trophic levels and between species.
  • Values of about 5-20% are common.
  • 10% is neither a fixed amount nor a true average: it is only a rough rule of thumb.
  • Always work out the percentage from the data; never assume 10%.
It varies betweenHigher efficiencyLower efficiency
SpeciesInsects, fish: they do not keep warm, so less is lost as heatBirds, mammals: they burn most of their food keeping warm
Trophic levelsCarnivores: meat is easy to digestHerbivores: tough plant fibre leaves as faeces
EcosystemsOceans: phytoplankton are eaten wholeForests, grasslands: wood and roots are left uneaten

Real example: at Silver Springs the efficiency falls from 16% to 6% up the chain. The top carnivores are large, active fish that hunt, so they use more of their food in respiration.

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How this comes up: Paper 2, Section A: a food chain with energy values. Calculate the efficiency of one transfer [1], sometimes followed by why it differs from another transfer [2].
Table of a sea-loch food chain in kJ per m² per year: phytoplankton 15,000; zooplankton 1,350; herring 81; harbour seal 3.
Figure 1
IB-style questionCalculate[1 mark]

Figure 1 shows the energy in each trophic level of a food chain in a Scottish sea loch.

Calculate, as a percentage, the ecological efficiency of the transfer from zooplankton to herring.

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The transfer from herring to harbour seals is only (3 ÷ 81) × 100 = 3.7%. A follow-up part may ask why.

IB-style questionExplain[2 marks]

Figure 1 shows the energy in each trophic level of a food chain in a Scottish sea loch.

Explain why the ecological efficiency from herring to harbour seals is lower than from phytoplankton to zooplankton.

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A textbook shows a food chain in the Serengeti: grass → zebra → lion.

the approximate percentage of the energy in one trophic level that is passed on to the next.
[1 mark]

Related ESS HL Topics

Continue learning with these related topics from the same unit:

2.1.1The biosphere
2.1.2Organisms and species
2.1.3Classification
2.1.4Identification of organisms
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2.2.27Sustainable yields and trophic levels
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Entropy in ecosystems2.2.29

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