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NotesMath AATopic 5.6Product rule
Back to Math AA Topics
5.6.21 min read

Product rule

IB Mathematics: Analysis and Approaches • Unit 5

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Contents

  • The product rule
  • Working through a product
  • Product with the chain rule
Differentiate one, keep the other — both ways, then add: To differentiate a product y = u·v: (uv)' = u'v + uv' — differentiate the first times the second, plus the first times the derivative of the second.
The product rule — in the formula booklet.

IB-style question — a product

Differentiate y = (2x + 1)(x² − 3).

Step by step

  1. Let u = 2x+1 (u' = 2), v = x²−3 (v' = 2x). Apply u'v + uv'.
  2. Expand and collect.

Final answer

dy/dx = 6x² + 2x − 6.

Label u, v, u', v' first: Write out u, v, u', v' before substituting — it stops you mixing up the four pieces.

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Substitute carefully, then simplify: Identify u and v, find u' and v', substitute into u'v + uv', and simplify.

Leaving the answer factorised is often neatest.

IB-style question — product with a power

Differentiate y = x²(2x − 5).

Step by step

  1. u = x² (u' = 2x), v = 2x − 5 (v' = 2).
  2. Expand and collect.

Final answer

dy/dx = 6x² − 10x.

Check by expanding first: For simple products you can expand then differentiate to check (here x²(2x−5) = 2x³−5x² → 6x²−10x).

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One factor may need the chain rule: When a factor is itself a composite (e.g. e2x or sin x), differentiate that factor with the chain rule while applying the product rule.

IB-style question — product needing the chain rule

Differentiate y = x·e2x.

Step by step

  1. u = x (u' = 1), v = e2x (v' = 2e2x by the chain rule).
  2. Factorise.

Final answer

dy/dx = e2x(1 + 2x).

Factor out the common term: Products with eˣ or a bracket usually factorise neatly — pull out the common factor for a tidy answer.

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Differentiate y = (x + 3)(2x − 1) using the product rule. [2 marks]

Related Math AA Topics

Continue learning with these related topics from the same unit:

5.1.1Derivative as gradient
5.2.1Increasing & decreasing
5.3.1Differentiating powers
5.3.2Gradient at a point
View all Math AA topics

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