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NotesMath AA SLTopic 2.3Sketching graphs
Back to Math AA SL Topics
2.3.12 min read

Sketching graphs

IB Mathematics: Analysis and Approaches • Unit 2

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Contents

  • What a sketch needs
  • Intercepts first
  • Turning points & shape
  • Asymptotes & end behaviour
  • Paper 2: screen to paper (GDC)
A sketch shows features, not every point: A sketch isn't a precise plot — it shows the right shape with the key features labelled. Mark each of: axis intercepts, turning points (max/min), asymptotes, and the correct end-behaviour.
The sketch checklist: Every sketch marks the same four things:

• Intercepts — where it crosses each axis (label coordinates). • Turning points — any maximum or minimum (label coordinates). • Asymptotes — dashed guide lines the curve approaches (label equations). • Shape & ends — does it open up / down, rise / fall, level off?
Label everything you find: Marks come from labelled features. A correctly-shaped curve with no values gets few marks — write the coordinates and asymptote equations on the sketch.
Start where it crosses the axes: Find the y-intercept by setting x = 0, and the x-intercepts (the zeros/roots) by setting y = 0 and solving.

IB-style question — intercepts of a parabola

Find the intercepts of y = (x − 1)(x + 3) for a sketch.

Step by step

  1. x-intercepts: set y = 0 — each bracket gives a root.
  2. y-intercept: set x = 0.

Final answer

Crosses the x-axis at (1, 0) and (−3, 0), the y-axis at (0, −3).

Factored form gives the roots free: If a quadratic is written as (x − a)(x − b), the x-intercepts are simply x = a and x = b — no solving needed.

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Mark the turn, fix the direction: Mark any maximum or minimum (for a quadratic, the vertex). The leading term sets the direction: a quadratic with a > 0 opens up (a minimum), a < 0 opens down (a maximum).

IB-style question — a downward parabola

Sketch information for y = −x² + 4x: opening direction, vertex and intercepts.

Step by step

  1. Leading coefficient is −1 < 0, so it opens downward (a maximum).
  2. Axis of symmetry x = −b/(2a) = −4/(−2) = 2; vertex y = −(2)² + 4(2) = 4.
  3. x-intercepts: −x² + 4x = 0 ⇒ x(4 − x) = 0.

Final answer

Downward parabola, maximum at (2, 4), through (0, 0) and (4, 0).

End-behaviour from the leading term: For any polynomial, the highest-power term controls the ends: e.g. a positive x³ falls on the left and rises on the right.
Draw asymptotes as dashed guides: For rational and exponential graphs, draw each asymptote as a dashed line the curve approaches but doesn't cross. A vertical asymptote is where a denominator = 0; a horizontal asymptote is the value the curve levels off to.

IB-style question — a reciprocal-type graph

State the asymptotes for a sketch of y = 1/(x − 2) + 1.

Step by step

  1. Vertical asymptote: denominator zero.
  2. Horizontal asymptote: the +1 is the level it approaches.

Final answer

Dashed lines x = 2 and y = 1; the curve has two branches approaching them.

Exponentials have one asymptote: y = aˣ approaches the x-axis (y = 0) on one side but never touches it — draw that as the dashed horizontal asymptote.

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Graph it, then transfer it: On Paper 2 a function may be too awkward to sketch by hand. Graph it on the GDC, then transfer the picture to paper: keep the shape, and label the same intercepts, turning points and asymptotes — reading their values off the GDC.
A sketch still needs labels: Copying the GDC's curve shape isn't enough — the marks are for the labelled features. Always transfer the numbers, not just the shape.

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the y-intercept of the graph of y = x² − 5x + 6. [1 mark]

Related Math AA SL Topics

Continue learning with these related topics from the same unit:

2.1.1Equations of lines
2.1.2Parallel & perpendicular
2.2.1Function notation
2.2.2Domain & range
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