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NotesMath AA SLTopic 2.1Perpendicular bisector
Back to Math AA SL Topics
2.1.42 min read

Perpendicular bisector

IB Mathematics: Analysis and Approaches • Unit 2

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Contents

  • What a perpendicular bisector is
  • Building the perpendicular bisector
  • Putting it together — a full exam question
  • Another exam shape — midpoint, then a line through two points
Bisector = midpoint + perpendicular: A perpendicular bisector of a segment cuts it exactly in half at a right angle. So it does two things at once: it passes through the midpoint of the two endpoints, and it has the negative-reciprocal gradient of the segment.

[Diagram: math-perp-bisector-steps] - Available in full study mode

Average the x-coordinates and the y-coordinates.
Every point on it is equidistant: A neat way to picture it: the perpendicular bisector of AB is the set of all points the same distance from A as from B. That's why it appears in 'equally far from two places' problems.

The three-step recipe

  • 1. Midpoint of the two endpoints — average the coordinates.
  • 2. Gradient of the segment, then its negative reciprocal (flip and change the sign).
  • 3. Put that gradient and the midpoint into y = mx + c, then solve for c.
Three steps, in order: Midpoint → negative-reciprocal gradient → line through the midpoint. One small rule per step.

IB-style question — perpendicular bisector of two points

Find the equation of the perpendicular bisector of A(1, 2) and B(5, 8).

Step by step

  1. Midpoint formula, then substitute A and B.
  2. Gradient formula, then substitute.
  3. Bisector gradient = negative reciprocal.
  4. Substitute the midpoint (3, 5) into y = mx + c.

Final answer

y = −⅔x + 7.

IB-style question — give the answer in general form

Find the perpendicular bisector of P(−2, 1) and Q(4, 5), giving your answer as ax + by + d = 0.

Step by step

  1. Midpoint formula, then substitute P and Q.
  2. Gradient formula, then negate-and-flip.
  3. Through M(1, 3): 3 = −3⁄2(1) + c ⇒ c = 9⁄2.
  4. Clear fractions and move to one side.

Final answer

3x + 2y − 9 = 0.

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Spot this shape — the 3-part bisector question: Two points, then 'the line perpendicular to the segment through its midpoint' — the perpendicular bisector, asked in three quick parts. Same three moves every time:

(a) Midpoint

  • average the two points
  • → the point M

(b) Gradient

  • gradient of the segment
  • → negative reciprocal

(c) Equation

  • that gradient through M
  • → y = mx + c

[Diagram: math-perp-bisector-steps] - Available in full study mode

Part (a) — find the midpoint M

Point A has coordinates (1, 2) and point B has coordinates (7, 6). Point M is the midpoint of [AB]. Find the coordinates of M.

Step by step

  1. Midpoint formula — average each coordinate.
  2. Substitute A(1, 2) and B(7, 6).

Final answer

M = (4, 4).

Part (b) — find the gradient of L

Line L is perpendicular to [AB] and passes through M. Find the gradient of L.

Step by step

  1. Gradient formula for the segment [AB].
  2. Substitute A(1, 2) and B(7, 6).
  3. Perpendicular ⇒ negative reciprocal (flip and change the sign).

Final answer

gradient of L = −3/2.

Part (c) — write down the equation of L

Hence, write down the equation of L.

Step by step

  1. Put the gradient −3/2 through the midpoint M(4, 4) into point–gradient form.
  2. Tidy to y = mx + c.

Final answer

y = −3/2 x + 10 (or leave it as y − 4 = −3/2(x − 4)).

See how every part is linked: (a) midpoint → (b) perpendicular gradient → (c) line through M. Part (c) just drops the gradient from (b) and the point from (a) into point–gradient form — so three marks come quickly if you go in order.
Two marks people throw away: 1. The bisector passes through the midpoint M — not through A or B. 2. Use the negative reciprocal (flip and change the sign); point–gradient form like y − 4 = −3/2(x − 4) is accepted, but not 'L = …'.
Same midpoint skill, a different finish: Coordinate-geometry questions often open with a midpoint, then ask for the equation of a line through two points (here, not perpendicular). Two linked moves:

(a) Midpoint

  • average the two points
  • → the point M

(b) The line

  • gradient between two points
  • → y = mx + c through one of them

Part (a) — find the midpoint M

Points A(8, 0) and C(2, 6) are two corners of a shape. M is the midpoint of [AC]. Find the coordinates of M.

Step by step

  1. Midpoint formula — average each coordinate.
  2. Substitute A(8, 0) and C(2, 6).

Final answer

M = (5, 3).

Part (b) — the line through O and M

Hence find the equation of the line through the origin O(0, 0) and M.

Step by step

  1. Gradient formula between the two points.
  2. Substitute O(0, 0) and M(5, 3).
  3. Through the origin the y-intercept is 0, so y = mx.

Final answer

y = (3/5)x.

See how the parts link: Part (a) hands you a point; part (b) uses that point with the origin to get a gradient, then the line. A line through the origin always has the tidy form y = mx (c = 0).

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Find the perpendicular bisector of P(−3, 2) and Q(5, 2). [2 marks]

Related Math AA SL Topics

Continue learning with these related topics from the same unit:

2.1.1Equations of lines
2.1.2Parallel lines
2.1.3Perpendicular lines
2.2.1Function notation
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