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NotesMath AA SLTopic 1.7Laws of exponents
Back to Math AA SL Topics
1.7.11 min read

Laws of exponents

IB Mathematics: Analysis and Approaches • Unit 1

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Contents

  • The index laws
  • Negative & rational exponents
  • Quadratic in aˣ
The big idea: When you multiply, divide or raise powers of the same base, you work with the exponents, not the big numbers.

For example, 2³ × 2⁴ = 2⁷ — just add the exponents.
Multiply → add exponents. Divide → subtract. Power of a power → multiply.

See it on numbers

Simplify (x⁵ × x³) ÷ x².

Step by step

  1. Multiply — add the exponents.
  2. Divide — subtract the exponent.

Final answer

x⁶.

Same base only: These laws only work when the base is the same — you cannot combine 2³ × 3² this way.

And anything to the power 0 is 1: a⁰ = 1.
Roots and reciprocals are powers too: A negative exponent means "one over"; a fractional exponent means a root — so you can turn roots and reciprocals into clean powers, and back.
Bottom of a fraction → negative exponent. Root → fractional exponent.

See it — evaluate a fractional power

Evaluate 272/3 without a calculator.

Step by step

  1. The denominator is the root: take the cube root first.
  2. The numerator is the power: square it.

Final answer

272/3 = 9.

IB-style question — write as a single power

Write each as a power of x: u = 1/x³ v = ∛x w = x²√x

Step by step

  1. Bottom of a fraction → negative exponent.
  2. Cube root → exponent 1/3.
  3. √x = x1/2; multiplying means adding exponents.

Final answer

x⁻³, x1/3, x5/2.

IB-style question — solve for the base

Given that a2/3 = 4, find a.

Step by step

  1. To undo the power 2/3, raise both sides to the reciprocal 3/2.
  2. Square root first, then cube.

Final answer

a = 8.

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A hidden quadratic: A neat exam twist: an equation with aˣ and a²ˣ is secretly a quadratic, because a²ˣ = (aˣ)². Substitute y = aˣ, solve, then solve back for x.

IB-style question — substitute and solve

Solve 4ˣ − 6(2ˣ) + 8 = 0.

Step by step

  1. Spot the hidden square: 4ˣ = (2²)ˣ = (2ˣ)². Let y = 2ˣ.
  2. Factorise the quadratic.
  3. Solve back for x (recall y = 2ˣ).

Final answer

x = 1 or x = 2.

Reject impossible values: A power like 2ˣ is always positive. If the quadratic gives a negative or zero value of y, reject it — keep only y > 0 before solving back for x.

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Simplify (a5/2 × a1/2) ÷ a, expressing your answer as a single power of a. [2 marks]

Related Math AA SL Topics

Continue learning with these related topics from the same unit:

1.1.1Writing standard form
1.1.2Standard form by hand
1.2.1nth term
1.2.2Sum of n terms
View all Math AA SL topics

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