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NotesMath AATopic 1.7
Unit 1 · Number & Algebra · Topic 1.7

IB Math AA — Exponent & log laws

Topic 1.7 of IB Mathematics: Analysis and Approaches covers Exponent & log laws, which is part of Unit 1: Number & Algebra. Students explore key concepts including Laws of exponents, Laws of logarithms, Exponential & log equations. A strong understanding of exponent & log laws is essential for IB Math AA exams and builds the foundation for connected topics across the syllabus.

Exam technique guidePractice questions

Key concepts in Exponent & log laws

Key Idea: These are your algebra cheat-sheets for powers and logs — used to simplify expressions and to solve exponential and log equations. Almost all of it is Paper 1 by hand; Paper 2 only adds a graphing shortcut.

⚡ Laws of exponents (Paper 1)

aman=am+n,aman=am−n,(am)n=amna^m a^n = a^{m+n}, \quad \frac{a^m}{a^n} = a^{m-n}, \quad (a^m)^n = a^{mn}aman=am+n,anam​=am−n,(am)n=amn
aaa
the common base — must be the same to combine
a−n=1ana^{-n} = \tfrac{1}{a^n}a−n=an1​
negative power = reciprocal
am/n=(an)ma^{m/n} = (\sqrt[n]{a})^{m}am/n=(na​)m
fractional power = nth root, then mth power
OperationRule (same base)Example
MultiplyAdd the exponentsx⁵ × x³ = x⁸
DivideSubtract the exponentsx⁸ ÷ x² = x⁶
Power of a powerMultiply the exponents(x²)³ = x⁶
Power 0Always 1a⁰ = 1
FractionalRoot (bottom), then power (top)27²/³ = (∛27)² = 9

🟰 Laws of logarithms (Paper 1)

log⁡axy=log⁡ax+log⁡ay,log⁡axy=log⁡ax−log⁡ay,log⁡axm=mlog⁡ax,log⁡ax=log⁡bxlog⁡ba\log_a xy = \log_a x + \log_a y, \quad \log_a \tfrac{x}{y} = \log_a x - \log_a y, \quad \log_a x^m = m\log_a x, \quad \log_a x = \frac{\log_b x}{\log_b a}loga​xy=loga​x+loga​y,loga​yx​=loga​x−loga​y,loga​xm=mloga​x,loga​x=logb​alogb​x​
log⁡a1=0\log_a 1 = 0loga​1=0
log of 1 is always 0
log⁡aa=1\log_a a = 1loga​a=1
log of the base is 1
log⁡bxlog⁡ba\frac{\log_b x}{\log_b a}logb​alogb​x​
change of base — swap to any base you can compute
LawCombine (→)Expand (←)
Productlog x + log y = log(xy)Split a product into a sum
Quotientlog x − log y = log(x/y)Split a quotient into a difference
Powerm log x = log xᵐBring an exponent down as a coefficient
Change of baselogₐ x = log x ÷ log aRewrite an awkward base
Equation typeMethodQuick example
aˣ = b, bases matchEquate the exponents4ˣ = 8 → 2²ˣ = 2³ → x = 3/2
aˣ = b, bases differTake logs (power law drops x)5ˣ = 20 → x = log 20 / log 5
logₐ(expr) = cConvert: expr = aᶜln(x²−16) = 0 → x² − 16 = 1
Two logs = cCombine to one log, then convertlog₂x + log₂(x−2) = 3 → x = 4

✏️ IB-style worked examples

IB-style question — simplify with the index laws

Simplify (p⁵ × p³) ÷ p², leaving your answer as a single power of p.

Step by step:

  1. Multiply — add the exponents.

    p5×p3=p5+3=p8p^5 \times p^3 = p^{5+3} = p^8p5×p3=p5+3=p8
  2. Divide — subtract the exponent.

    p8p2=p8−2=p6\frac{p^8}{p^2} = p^{8-2} = p^6p2p8​=p8−2=p6
Final answer:

p⁶

IB-style question — condense into a single logarithm

Write ln 5 + 2 ln 2 − ln 10 as a single logarithm.

Step by step:

  1. Coefficient first: the power law moves the 2 up.

    2ln⁡2=ln⁡22=ln⁡42\ln 2 = \ln 2^2 = \ln 42ln2=ln22=ln4
  2. Add → multiply on top, subtract → divide.

    ln⁡5+ln⁡4−ln⁡10=ln⁡5×410\ln 5 + \ln 4 - \ln 10 = \ln \frac{5 \times 4}{10}ln5+ln4−ln10=ln105×4​
  3. Simplify the inside.

    =ln⁡2= \ln 2=ln2
Final answer:

ln 2

IB-style question — solve an exponential by taking logs

Solve 7ˣ = 50, giving the exact value of x.

Step by step:

  1. Bases won't match, so take logs of both sides.

    log⁡7x=log⁡50\log 7^x = \log 50log7x=log50
  2. The power law brings x down.

    xlog⁡7=log⁡50x \log 7 = \log 50xlog7=log50
  3. Divide to isolate x.

    x=log⁡50log⁡7≈2.01x = \frac{\log 50}{\log 7} \approx 2.01x=log7log50​≈2.01
Final answer:

x = log 50 / log 7 (≈ 2.01)

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Important: log(x + y) ≠ log x + log y. The laws act only on a product, quotient or power — never on a sum or difference inside one log. And after solving a log equation, check every argument is positive: discard any root that makes a log's inside ≤ 0.

Tap each card to reveal the answer.

Simplify x⁷ ÷ x³ x⁴ — divide means subtract the exponents, 7 − 3.

Evaluate 16³/⁴ without a calculator 8 — fourth root of 16 is 2, then 2³ = 8.

Write 2 log x + log y as one logarithm log(x²y) — the 2 becomes a power, then add → multiply.

Solve 2ˣ = 16 x = 4 — write 16 = 2⁴, equal bases ⇒ equal exponents.

Solve ln x = 3, exact answer x = e³ — convert to exponential form: x = e³.

Exam Tips

  • Same base only: multiply → add exponents, divide → subtract, power of a power → multiply.
  • Negative power = reciprocal; fractional power m/n = nth root then mth power.
  • Logs: product → add, quotient → subtract, power → coefficient (read right-to-left to combine).
  • Bases match → equate exponents; otherwise take logs. A lone log = number → convert to expr = aᶜ.
  • Reject any solution that makes a log's argument ≤ 0, and use change of base for an awkward base.

What you'll learn in Topic 1.7

  • 1.7.1 Laws of exponents
  • 1.7.2 Laws of logarithms
  • 1.7.3 Exponential & log equations
Suggested study order: Read the notes for each sub-topic below → test yourself with flashcards → attempt practice questions → review exam technique.

Study resources — 1.7 Exponent & log laws

1.7.1

Laws of exponents

Notes
1.7.2

Laws of logarithms

Notes
1.7.3

Exponential & log equations

Notes

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Topic 1.7 Exponent & log laws forms a core part of Unit 1: Number & Algebra in IB Math AA. Mastering these concepts will strengthen your understanding of connected topics across the syllabus and prepare you for exam questions that require analysis, evaluation, and real-world application.

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