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NotesMath AA HLTopic 5.19Building a Maclaurin series
Back to Math AA HL Topics
5.19.14 min read

Building a Maclaurin series (Math AA HL)

IB Mathematics: Analysis and Approaches · Unit 5

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Contents

  1. 1The Maclaurin formula
  2. 2The standard series: eˣ, sin x, cos x, ln(1 + x)
A function written as a polynomial: A Maclaurin series copies a function near x = 0 by building an endless polynomial that agrees with the curve.

How it copies the curve

  • Imagine zooming in on a curve near x = 0.
  • The series matches its height, slope, bend, and every higher derivative at x = 0.
The coefficient of xⁿ: The coefficient of xⁿ is f⁽ⁿ⁾(0) ÷ n!: the nth derivative measured at 0, then shared out by n! so each new term doesn't disturb the lower ones.
The Maclaurin series: each coefficient is a derivative at 0 divided by a factorial.
Why divide by n!?: Differentiate xⁿ exactly n times and you get n! (a constant). Dividing the coefficient by n! cancels that, so when you set x = 0 the nth term contributes exactly f⁽ⁿ⁾(0) to the nth derivative — and nothing to the lower ones. That is what makes every derivative match at x = 0.

IB-style question — find the series from scratch

Let f(x) = e2x.

Find the Maclaurin series of f up to and including the term in x³.

Step by step

  1. List the derivatives, then read each one at x = 0.
  2. Evaluate every derivative at 0 (e⁰ = 1).
  3. Drop them into the formula, dividing by the factorials.
  4. Simplify 4/2! = 2 and 8/3! = 4/3.

Final answer

e2x = 1 + 2x + 2x² + (4/3)x³ + … (the same as eˣ with x replaced by 2x).

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Four series worth knowing cold: These four come up again and again. Learn them — then most exam questions are just substitution or multiplication, not differentiating from scratch.

How to tell them apart

  • eˣ uses every term.
  • sin x keeps only odd powers.
  • cos x keeps only even powers.
  • ln(1 + x) has alternating signs and plain whole-number denominators (no factorials).
eˣ: every power, denominator n!.
sin x: odd powers only, alternating signs.
cos x: even powers only, alternating signs.
ln(1 + x): plain denominators 1, 2, 3, 4, … and alternating signs.

IB-style question — derive sin x to confirm the pattern

Let f(x) = sin x.

Use the Maclaurin formula to find the first three non-zero terms, and explain why all the even powers vanish.

Step by step

  1. The derivatives of sin x cycle in fours.
  2. Read each at x = 0 (sin 0 = 0, cos 0 = 1).
  3. Every EVEN derivative gives 0, so all even powers drop out — that's why only odd powers survive.
  4. Use the surviving (odd) terms.

Final answer

sin x = x − x³/3! + x⁵/5! − … ; even powers vanish because every even derivative is ±sin 0 = 0.

IB-style question — derive ln(1 + x)

Find the Maclaurin series of f(x) = ln(1 + x) up to the term in x³.

Step by step

  1. Differentiate repeatedly.
  2. Read each at x = 0 (and f(0) = ln 1 = 0).
  3. Apply the formula, dividing by factorials.
  4. Simplify 1/2! = 1/2 and 2/3! = 1/3 — the factorials cancel to plain denominators.

Final answer

ln(1 + x) = x − x²/2 + x³/3 − … (plain denominators 1, 2, 3, …).

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