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Topic 6.4Chemistry HL24 flashcards

Electron-pair sharing reactions

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Card 1 of 246.4.1
6.4.1
Question

What is a nucleophile?

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All Flashcards in Topic 6.4

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6.4.112 cards

Card 1definition
Question

What is a nucleophile?

Answer

An **electron-pair donor** — it has a lone pair and is attracted to a δ+ (electron-poor) carbon. Examples: OH⁻, CN⁻, NH_{3}.

Card 2concept
Question

Why is the carbon in a halogenoalkane δ+?

Answer

The C–halogen bond is **polar**: the more electronegative halogen pulls the bonding electrons, leaving carbon slightly positive (**δ+**).

Card 3definition
Question

What does a curly arrow show?

Answer

The movement of a **pair of electrons** — the tail is at the electrons that move, the head is where the pair ends up.

Card 4process
Question

Describe the two curly arrows in nucleophilic substitution.

Answer

Arrow 1: the nucleophile's **lone pair → δ+ carbon** (new bond). Arrow 2: the **C–X bond → halogen**, which leaves as X⁻.

Card 5definition
Question

What is the leaving group?

Answer

The atom/ion that departs **with the bonding pair** — here the **halide ion, X⁻** (e.g. Br⁻, Cl⁻).

Card 6concept
Question

Product of a halogenoalkane + warm aqueous NaOH?

Answer

An **alcohol** (the –halogen is replaced by –OH), plus a halide ion.

Card 7concept
Question

Conditions for OH⁻ substitution?

Answer

**Warm** (gentle heat) and **aqueous** sodium or potassium hydroxide.

Card 8definition
Question

What is substitution?

Answer

A reaction in which **one group replaces another** on the carbon skeleton, which is otherwise unchanged.

Card 9comparison
Question

Nucleophile vs electrophile?

Answer

Nucleophile = electron-pair **donor** (attacks δ+); electrophile = electron-pair **acceptor** (attacks δ−). Opposites.

Card 10concept
Question

Which C–halogen bond reacts fastest, and why?

Answer

**C–I** — it is the **weakest** bond, so it breaks most easily. C–F is strongest, so the fluoroalkane is slowest.

Card 11example
Question

Product with cyanide, CN⁻?

Answer

A **nitrile** (–CN) — and the chain gains one carbon atom.

Card 12example
Question

Product with ammonia, NH_{3}?

Answer

An **amine** (–NH_{2}), using excess ammonia.

6.4.212 cards

Card 13definition
Question

What is an electrophile?

Answer

An **electron-pair acceptor** — an electron-poor species (often δ+ or positive) attracted to electron-rich regions. Examples: Br_{2}, HBr, H⁺.

Card 14concept
Question

Why are alkenes reactive?

Answer

The **C=C double bond** has a **π bond** of high electron density that is easily attacked by **electrophiles**.

Card 15definition
Question

What is an addition reaction?

Answer

Two molecules combine into **one**: a group adds to **each** carbon and the **double bond becomes single** (nothing is left over).

Card 16definition
Question

What does 'unsaturated' mean?

Answer

The molecule contains a **C=C (or C≡C)** and can undergo **addition**; a saturated molecule has only single bonds.

Card 17process
Question

Describe the two curly arrows in electrophilic addition.

Answer

Arrow 1: the **C=C π bond → the electrophile** (new bond). Arrow 2: the **X–X / H–X bond → the leaving atom**, which breaks heterolytically (e.g. as Br⁻).

Card 18concept
Question

Product of ethene + bromine?

Answer

**1,2-dibromoethane, CH_{2}BrCH_{2}Br** — a bromine atom adds to each carbon as the C=C opens.

Card 19concept
Question

Product of an alkene + a hydrogen halide (e.g. HBr)?

Answer

A **halogenoalkane** — H adds to one carbon and the halogen to the other (e.g. ethene + HBr → bromoethane).

Card 20example
Question

Product of an alkene + steam (H_{2}O)?

Answer

An **alcohol** — using **steam with an H_{3}PO_{4} catalyst** (heat & pressure); –H and –OH add across the C=C.

Card 21concept
Question

What is the test for a C=C double bond?

Answer

Add **bromine water**: an alkene **decolourises** the orange bromine (it adds across the C=C).

Card 22comparison
Question

Electrophile vs nucleophile?

Answer

Electrophile = electron-pair **acceptor** (electron-poor); nucleophile = electron-pair **donor** (electron-rich). Opposites.

Card 23comparison
Question

Addition vs substitution — which for alkenes?

Answer

Alkenes (unsaturated) react by **addition** (C=C opens, nothing left over); alkanes (saturated) by **substitution** (an atom is replaced).

Card 24concept
Question

Why does the Br–Br bond break heterolytically here?

Answer

As Br_{2} meets the electron-rich C=C it becomes polarised (δ+/δ−); the far bromine leaves with **both** electrons as **Br⁻**.

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