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Topic 6.4Chemistry45 flashcards

Electron-pair sharing reactions

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Card 1 of 456.4.1
6.4.1
Question

What is a nucleophile?

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All Flashcards in Topic 6.4

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6.4.112 cards

Card 1definition
Question

What is a nucleophile?

Answer

An **electron-pair donor** — it has a lone pair and is attracted to a δ+ (electron-poor) carbon. Examples: OH⁻, CN⁻, NH_{3}.

Card 2concept
Question

Why is the carbon in a halogenoalkane δ+?

Answer

The C–halogen bond is **polar**: the more electronegative halogen pulls the bonding electrons, leaving carbon slightly positive (**δ+**).

Card 3definition
Question

What does a curly arrow show?

Answer

The movement of a **pair of electrons** — the tail is at the electrons that move, the head is where the pair ends up.

Card 4process
Question

Describe the two curly arrows in nucleophilic substitution.

Answer

Arrow 1: the nucleophile's **lone pair → δ+ carbon** (new bond). Arrow 2: the **C–X bond → halogen**, which leaves as X⁻.

Card 5definition
Question

What is the leaving group?

Answer

The atom/ion that departs **with the bonding pair** — here the **halide ion, X⁻** (e.g. Br⁻, Cl⁻).

Card 6concept
Question

Product of a halogenoalkane + warm aqueous NaOH?

Answer

An **alcohol** (the –halogen is replaced by –OH), plus a halide ion.

Card 7concept
Question

Conditions for OH⁻ substitution?

Answer

**Warm** (gentle heat) and **aqueous** sodium or potassium hydroxide.

Card 8definition
Question

What is substitution?

Answer

A reaction in which **one group replaces another** on the carbon skeleton, which is otherwise unchanged.

Card 9comparison
Question

Nucleophile vs electrophile?

Answer

Nucleophile = electron-pair **donor** (attacks δ+); electrophile = electron-pair **acceptor** (attacks δ−). Opposites.

Card 10concept
Question

Which C–halogen bond reacts fastest, and why?

Answer

**C–I** — it is the **weakest** bond, so it breaks most easily. C–F is strongest, so the fluoroalkane is slowest.

Card 11example
Question

Product with cyanide, CN⁻?

Answer

A **nitrile** (–CN) — and the chain gains one carbon atom.

Card 12example
Question

Product with ammonia, NH_{3}?

Answer

An **amine** (–NH_{2}), using excess ammonia.

6.4.222 cards

Card 13definition
Question

What is an electrophile?

Answer

An **electron-pair acceptor** — an electron-poor (often positive) species attracted to an electron-rich centre such as a C=C. Examples: Br_{2}, HBr, H⁺.

Card 14concept
Question

Why are alkenes reactive?

Answer

The **C=C double bond** has a **π bond** of high electron density that is easily attacked by **electrophiles**.

Card 15concept
Question

Why is the C=C double bond reactive?

Answer

It is **electron-rich** (two shared pairs / exposed π electrons), so it readily donates electrons and attacks electrophiles.

Card 16definition
Question

What is an addition reaction?

Answer

Two molecules join to form **one** product; the C=C opens to a single bond and the reactant adds across it. **Nothing leaves**.

Card 17comparison
Question

Saturated vs unsaturated?

Answer

Saturated = only **single** bonds (alkane); unsaturated = has a **C=C** (alkene) so more atoms can be **added**.

Card 18definition
Question

What does 'unsaturated' mean?

Answer

The molecule contains a **C=C (or C≡C)** and can undergo **addition**; a saturated molecule has only single bonds.

Card 19process
Question

Describe the two curly arrows in electrophilic addition.

Answer

Arrow 1: the **C=C π bond → the electrophile** (new bond). Arrow 2: the **X–X / H–X bond → the leaving atom**, which breaks heterolytically (e.g. as Br⁻).

Card 20process
Question

Describe the two curly arrows in electrophilic addition (Br_{2}).

Answer

Arrow 1: the **C=C π electrons → a bromine** (new bond). Arrow 2: the **Br–Br bond → the other bromine**, which leaves as Br⁻.

Card 21concept
Question

Product of ethene + bromine?

Answer

**1,2-dibromoethane, CH_{2}BrCH_{2}Br** — a bromine atom adds to each carbon as the C=C opens.

Card 22example
Question

Product of ethene + Br_{2}?

Answer

**1,2-dibromoethane, CH_{2}BrCH_{2}Br** — one bromine adds to each carbon.

Card 23concept
Question

Product of an alkene + a hydrogen halide (e.g. HBr)?

Answer

A **halogenoalkane** — H adds to one carbon and the halogen to the other (e.g. ethene + HBr → bromoethane).

Card 24example
Question

Product of ethene + HBr?

Answer

**Bromoethane, CH_{3}CH_{2}Br** — H and Br add across the C=C.

Card 25example
Question

Product of an alkene + steam (H_{2}O)?

Answer

An **alcohol** — using **steam with an H_{3}PO_{4} catalyst** (heat & pressure); –H and –OH add across the C=C.

Card 26example
Question

Product of ethene + steam (H_{2}O)?

Answer

**Ethanol, CH_{3}CH_{2}OH** — water adds across the C=C with an H_{3}PO_{4} catalyst at high T and P.

Card 27example
Question

Product of ethene + H_{2}?

Answer

**Ethane, CH_{3}CH_{3}** (saturated) — hydrogen adds across the C=C with a Ni catalyst.

Card 28concept
Question

What is the test for a C=C double bond?

Answer

Add **bromine water**: an alkene **decolourises** the orange bromine (it adds across the C=C).

Card 29concept
Question

What is the test for unsaturation?

Answer

Add **bromine water**: an **alkene decolourises** it (orange → colourless); an **alkane** gives **no change**.

Card 30comparison
Question

Electrophile vs nucleophile?

Answer

Electrophile = electron-pair **acceptor** (electron-poor); nucleophile = electron-pair **donor** (electron-rich). Opposites.

Card 31concept
Question

What is Markovnikov's rule?

Answer

For an unsymmetrical alkene + HX, the **H adds to the carbon that already has more hydrogens**, giving the **major** product.

Card 32comparison
Question

Addition vs substitution — which for alkenes?

Answer

Alkenes (unsaturated) react by **addition** (C=C opens, nothing left over); alkanes (saturated) by **substitution** (an atom is replaced).

Card 33example
Question

Major product of propene + HBr?

Answer

**2-bromopropane, CH_{3}CHBrCH_{3}** — H goes to the CH_{2} end, Br to the middle carbon (Markovnikov).

Card 34concept
Question

Why does the Br–Br bond break heterolytically here?

Answer

As Br_{2} meets the electron-rich C=C it becomes polarised (δ+/δ−); the far bromine leaves with **both** electrons as **Br⁻**.

6.4.311 cards

Card 35concept
Question

Why is an alkene's C=C reactive in electrophilic addition?

Answer

It is **electron-rich** — the exposed **π electrons** make it an electron-pair **donor** that attacks an electrophile.

Card 36definition
Question

What is a carbocation?

Answer

A carbon atom bearing a **positive charge** (only 3 bonds / 6 electrons) — the reactive **intermediate** in electrophilic addition.

Card 37process
Question

Describe step 1 of HBr adding to an alkene.

Answer

The **C=C π electrons → the δ+ H** of HBr (arrow 1); the **H–Br bond → Br** (arrow 2), which leaves as **Br⁻**. A **carbocation** forms.

Card 38process
Question

Describe step 2 of HBr adding to an alkene.

Answer

The **bromide ion (Br⁻) attacks the positive carbon** of the carbocation, forming the final C–Br bond — the reagent has now **added across** the C=C.

Card 39concept
Question

What is Markovnikov's rule (HL explanation)?

Answer

The major product forms via the **more stable carbocation**; equivalently, the **H of HX adds to the C with more H's**.

Card 40comparison
Question

Order of carbocation stability?

Answer

**tertiary (3°) > secondary (2°) > primary (1°)** — more alkyl groups donate electron density and spread the positive charge.

Card 41example
Question

Major product of propene + HBr, and why?

Answer

**2-bromopropane, CH_{3}CHBrCH_{3}** — via the more stable **secondary** carbocation (Markovnikov).

Card 42example
Question

Major product of 2-methylpropene + HBr?

Answer

**2-bromo-2-methylpropane, (CH_{3})_{3}CBr** — via the most stable **tertiary** carbocation.

Card 43concept
Question

Why does benzene substitute rather than add?

Answer

Its **delocalised** ring is very **stable**; addition would destroy the delocalisation, while **substitution restores** the aromatic ring.

Card 44example
Question

Electrophile, catalyst and product in benzene nitration?

Answer

Electrophile = **nitronium ion, NO_{2}⁺**; catalyst = conc. **H_{2}SO_{4}**; product = **nitrobenzene, C_{6}H_{5}NO_{2}** (plus H⁺ lost).

Card 45comparison
Question

Addition vs substitution — the key difference?

Answer

**Addition**: reagent adds across C=C, nothing leaves (alkenes). **Substitution**: one group replaces a ring H, ring restored (benzene).

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