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What is a nucleophile?
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All Flashcards in Topic 6.4
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6.4.112 cards
What is a nucleophile?
An **electron-pair donor** — it has a lone pair and is attracted to a δ+ (electron-poor) carbon. Examples: OH⁻, CN⁻, NH_{3}.
Why is the carbon in a halogenoalkane δ+?
The C–halogen bond is **polar**: the more electronegative halogen pulls the bonding electrons, leaving carbon slightly positive (**δ+**).
What does a curly arrow show?
The movement of a **pair of electrons** — the tail is at the electrons that move, the head is where the pair ends up.
Describe the two curly arrows in nucleophilic substitution.
Arrow 1: the nucleophile's **lone pair → δ+ carbon** (new bond). Arrow 2: the **C–X bond → halogen**, which leaves as X⁻.
What is the leaving group?
The atom/ion that departs **with the bonding pair** — here the **halide ion, X⁻** (e.g. Br⁻, Cl⁻).
Product of a halogenoalkane + warm aqueous NaOH?
An **alcohol** (the –halogen is replaced by –OH), plus a halide ion.
Conditions for OH⁻ substitution?
**Warm** (gentle heat) and **aqueous** sodium or potassium hydroxide.
What is substitution?
A reaction in which **one group replaces another** on the carbon skeleton, which is otherwise unchanged.
Nucleophile vs electrophile?
Nucleophile = electron-pair **donor** (attacks δ+); electrophile = electron-pair **acceptor** (attacks δ−). Opposites.
Which C–halogen bond reacts fastest, and why?
**C–I** — it is the **weakest** bond, so it breaks most easily. C–F is strongest, so the fluoroalkane is slowest.
Product with cyanide, CN⁻?
A **nitrile** (–CN) — and the chain gains one carbon atom.
Product with ammonia, NH_{3}?
An **amine** (–NH_{2}), using excess ammonia.
6.4.212 cards
What is an electrophile?
An **electron-pair acceptor** — an electron-poor (often positive) species attracted to an electron-rich centre such as a C=C. Examples: Br_{2}, HBr, H⁺.
Why is the C=C double bond reactive?
It is **electron-rich** (two shared pairs / exposed π electrons), so it readily donates electrons and attacks electrophiles.
What is an addition reaction?
Two molecules join to form **one** product; the C=C opens to a single bond and the reactant adds across it. **Nothing leaves**.
Saturated vs unsaturated?
Saturated = only **single** bonds (alkane); unsaturated = has a **C=C** (alkene) so more atoms can be **added**.
Describe the two curly arrows in electrophilic addition (Br_{2}).
Arrow 1: the **C=C π electrons → a bromine** (new bond). Arrow 2: the **Br–Br bond → the other bromine**, which leaves as Br⁻.
Product of ethene + Br_{2}?
**1,2-dibromoethane, CH_{2}BrCH_{2}Br** — one bromine adds to each carbon.
Product of ethene + HBr?
**Bromoethane, CH_{3}CH_{2}Br** — H and Br add across the C=C.
Product of ethene + steam (H_{2}O)?
**Ethanol, CH_{3}CH_{2}OH** — water adds across the C=C with an H_{3}PO_{4} catalyst at high T and P.
Product of ethene + H_{2}?
**Ethane, CH_{3}CH_{3}** (saturated) — hydrogen adds across the C=C with a Ni catalyst.
What is the test for unsaturation?
Add **bromine water**: an **alkene decolourises** it (orange → colourless); an **alkane** gives **no change**.
What is Markovnikov's rule?
For an unsymmetrical alkene + HX, the **H adds to the carbon that already has more hydrogens**, giving the **major** product.
Major product of propene + HBr?
**2-bromopropane, CH_{3}CHBrCH_{3}** — H goes to the CH_{2} end, Br to the middle carbon (Markovnikov).
Topic 6.4 study notes
Full notes & explanations for Electron-pair sharing reactions
Chemistry exam skills
Paper structures, command terms & tips
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