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Topic 6.4Chemistry SL24 flashcards

Electron-pair sharing reactions

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Card 1 of 246.4.1
6.4.1
Question

What is a nucleophile?

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All Flashcards in Topic 6.4

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6.4.112 cards

Card 1definition
Question

What is a nucleophile?

Answer

An **electron-pair donor** — it has a lone pair and is attracted to a δ+ (electron-poor) carbon. Examples: OH⁻, CN⁻, NH_{3}.

Card 2concept
Question

Why is the carbon in a halogenoalkane δ+?

Answer

The C–halogen bond is **polar**: the more electronegative halogen pulls the bonding electrons, leaving carbon slightly positive (**δ+**).

Card 3definition
Question

What does a curly arrow show?

Answer

The movement of a **pair of electrons** — the tail is at the electrons that move, the head is where the pair ends up.

Card 4process
Question

Describe the two curly arrows in nucleophilic substitution.

Answer

Arrow 1: the nucleophile's **lone pair → δ+ carbon** (new bond). Arrow 2: the **C–X bond → halogen**, which leaves as X⁻.

Card 5definition
Question

What is the leaving group?

Answer

The atom/ion that departs **with the bonding pair** — here the **halide ion, X⁻** (e.g. Br⁻, Cl⁻).

Card 6concept
Question

Product of a halogenoalkane + warm aqueous NaOH?

Answer

An **alcohol** (the –halogen is replaced by –OH), plus a halide ion.

Card 7concept
Question

Conditions for OH⁻ substitution?

Answer

**Warm** (gentle heat) and **aqueous** sodium or potassium hydroxide.

Card 8definition
Question

What is substitution?

Answer

A reaction in which **one group replaces another** on the carbon skeleton, which is otherwise unchanged.

Card 9comparison
Question

Nucleophile vs electrophile?

Answer

Nucleophile = electron-pair **donor** (attacks δ+); electrophile = electron-pair **acceptor** (attacks δ−). Opposites.

Card 10concept
Question

Which C–halogen bond reacts fastest, and why?

Answer

**C–I** — it is the **weakest** bond, so it breaks most easily. C–F is strongest, so the fluoroalkane is slowest.

Card 11example
Question

Product with cyanide, CN⁻?

Answer

A **nitrile** (–CN) — and the chain gains one carbon atom.

Card 12example
Question

Product with ammonia, NH_{3}?

Answer

An **amine** (–NH_{2}), using excess ammonia.

6.4.212 cards

Card 13definition
Question

What is an electrophile?

Answer

An **electron-pair acceptor** — an electron-poor (often positive) species attracted to an electron-rich centre such as a C=C. Examples: Br_{2}, HBr, H⁺.

Card 14concept
Question

Why is the C=C double bond reactive?

Answer

It is **electron-rich** (two shared pairs / exposed π electrons), so it readily donates electrons and attacks electrophiles.

Card 15definition
Question

What is an addition reaction?

Answer

Two molecules join to form **one** product; the C=C opens to a single bond and the reactant adds across it. **Nothing leaves**.

Card 16comparison
Question

Saturated vs unsaturated?

Answer

Saturated = only **single** bonds (alkane); unsaturated = has a **C=C** (alkene) so more atoms can be **added**.

Card 17process
Question

Describe the two curly arrows in electrophilic addition (Br_{2}).

Answer

Arrow 1: the **C=C π electrons → a bromine** (new bond). Arrow 2: the **Br–Br bond → the other bromine**, which leaves as Br⁻.

Card 18example
Question

Product of ethene + Br_{2}?

Answer

**1,2-dibromoethane, CH_{2}BrCH_{2}Br** — one bromine adds to each carbon.

Card 19example
Question

Product of ethene + HBr?

Answer

**Bromoethane, CH_{3}CH_{2}Br** — H and Br add across the C=C.

Card 20example
Question

Product of ethene + steam (H_{2}O)?

Answer

**Ethanol, CH_{3}CH_{2}OH** — water adds across the C=C with an H_{3}PO_{4} catalyst at high T and P.

Card 21example
Question

Product of ethene + H_{2}?

Answer

**Ethane, CH_{3}CH_{3}** (saturated) — hydrogen adds across the C=C with a Ni catalyst.

Card 22concept
Question

What is the test for unsaturation?

Answer

Add **bromine water**: an **alkene decolourises** it (orange → colourless); an **alkane** gives **no change**.

Card 23concept
Question

What is Markovnikov's rule?

Answer

For an unsymmetrical alkene + HX, the **H adds to the carbon that already has more hydrogens**, giving the **major** product.

Card 24example
Question

Major product of propene + HBr?

Answer

**2-bromopropane, CH_{3}CHBrCH_{3}** — H goes to the CH_{2} end, Br to the middle carbon (Markovnikov).

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