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c059741
NotesPhysicsTopic 1.3Gravitational PE & conservation of energy
Back to Physics Topics
1.3.32 min read

Gravitational PE & conservation of energy

IB Physics • Unit 1

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Contents

  • Energy of position, energy of motion
  • Working out PE and KE
  • Exam-style question
The big idea: Lift something up and it stores gravitational potential energy (PE) — energy because of its height.

Let it fall and that PE turns into kinetic energy (KE) — energy because of its motion.

No energy is lost: the PE the object loses becomes the KE it gains.

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Spot it: Top of a fall = all PE, no KE. Bottom = all KE, no PE. At any height in between, PE + KE adds up to the same total — that total is the mechanical energy, and it stays constant.

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The change in gravitational PE when an object moves up or down a height Δh is given in the data booklet:

Given in the data booklet — change in gravitational PE.
change in gravitational PE (J)
mass (kg)
gravitational field strength (≈ 9.8 N kg⁻¹ on Earth)
change in height (m)
What 'conservation of energy' means here: For a falling body with no air resistance, the mechanical energy (PE + KE) is conserved — it stays the same.

So the PE lost = the KE gained: mgΔh = ½mv².

The kinetic energy of a moving object is also given in the booklet:

Given in the data booklet — kinetic energy.
kinetic energy (J)
mass (kg)
speed (m s⁻¹)
IB-style questionCalculate[2 marks]

A 2.0 kg ball is lifted 5.0 m above the ground (g = 9.8 N kg⁻¹). Find the gravitational PE it gains.

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How this is tested — falling-body energy comes up in two predictable forms:

Paper 1A

  • A quick MCQ — often a ratio of KE part-way down to the PE at the top.
  • Or 'where is PE = KE?'

Paper 2

  • A short calculation setting PE lost = KE gained (mgΔh = ½mv²).
  • …to find a landing speed.
The classic trap: The mass cancels — speed at the bottom doesn't depend on m. And falling half the height means only half the energy is KE so far, not all of it.
The ratio shortcut: Because KE gained = PE lost, an object that has fallen a fraction f of its total height has turned a fraction f of its starting PE into KE. Fall half the height → KE = ½ of the starting PE.

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IB-style questionDetermine[2 marks]

A stone is released from rest at the top of a cliff (air resistance negligible). When it has fallen one-quarter of the way down, find the ratio (KE there) : (PE at the release point).

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Try an IB Exam Question — Free AI Feedback

Test yourself on Gravitational PE & conservation of energy. Write your answer and get instant AI feedback — just like a real IB examiner.

A 1.5 kg watering can is lifted from the ground onto a shelf 1.2 m high.

Taking g = 9.8 N kg⁻¹,
calculate the gravitational potential energy it gains.
[2 marks]

Related Physics Topics

Continue learning with these related topics from the same unit:

1.1.1Velocity and displacement
1.1.2Acceleration
1.1.3Displacement from a velocity–time graph
1.1.4The suvat equations
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