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NotesPhysicsTopic 1.1The suvat equations
Back to Physics Topics
1.1.45 min read

The suvat equations

IB Physics • Unit 1

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Contents

  • What the suvat equations are
  • The four equations & choosing one
  • Exam-style question
The big idea: A car speeds up steadily — how fast, and how far, after 5 s?

Questions like this — anything speeding up or slowing at a steady rate — are your bread-and-butter exam problems, and the suvat formulas solve them. First, the five things they connect:

The five suvat letters

1

s — displacement

how far it goes (m)

2

u — start speed

the velocity at the start (m s⁻¹)

3

v — end speed

the velocity at the end (m s⁻¹)

4

a — acceleration

how fast the velocity changes (m s⁻²)

5

t — time

how long it takes (s)

s · u · v · a · t

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Spot it: Suvat only works while the acceleration stays constant (a straight v–t line). If the acceleration changes, split the motion into constant-a stages and do each one separately.

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All four are given in the data booklet — you don't memorise them, you choose one. Tap any to see its booklet badge:

No s — use it when displacement is not involved.
No v — use it to find displacement from time.
No t — use it when time is unknown (great for stopping distance).
No a — displacement from the average of the two speeds.
displacement (m)
initial velocity (m s⁻¹)
final velocity (m s⁻¹)
acceleration (m s⁻²)
time (s)
How to choose the right one: List your three knowns and the one unknown you want.

Then pick the equation that contains those four letters and leaves out the fifth.

Example: you know u, a, t and want s → the equation missing v is s = ut + ½at².
IB-style questionDetermine[4 marks]

A sled starts at 4.0 m s⁻¹ and accelerates uniformly at 2.0 m s⁻² for 5.0 s. (a) Find its final speed. (b) Find how far it travels in those 5.0 s.

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How this is tested — suvat is the go-to for motion calculations: pick the right equation and plug in.

Paper 1A

  • A quick one-marker.
  • Often a stopping distance.

Paper 2

  • A longer, multi-step problem.
  • e.g. find a time or a final speed.
Read the exam signals: No time given → use v² = u² + 2as.

'Comes to rest' / 'stops' → v = 0.

'Deceleration' → a is negative (e.g. −5 m s⁻²).

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IB-style questionCalculate[3 marks]

A car travelling at 20 m s⁻¹ brakes with a constant deceleration of 5.0 m s⁻². Find the distance it travels before stopping.

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A go-kart accelerates uniformly from rest at 3.0 m s⁻² for 4.0 s in a straight line.

its final speed.
[1 mark]

Related Physics Topics

Continue learning with these related topics from the same unit:

1.1.1Velocity and displacement
1.1.2Acceleration
1.1.3Displacement from a velocity–time graph
1.1.5Free fall
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