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NotesPhysicsTopic 1.1Motion graphs: s–t, v–t and a–t
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1.1.82 min read

Motion graphs: s–t, v–t and a–t

IB Physics • Unit 1

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Contents

  • The three motion graphs
  • Reading each graph
  • Exam-style question
The big idea: Watch a car pull away from the lights. That one journey can be drawn three different ways — how far it has gone, how fast it is going, and how hard it is accelerating.
The three graphs: s–t (displacement–time) — how far from the start.

v–t (velocity–time) — how fast, and which way.

a–t (acceleration–time) — how quickly the velocity is changing.

One journey — a car pulling away from the lights at 5 m s⁻² for 4 s — drawn three ways. Same motion, three completely different shapes.

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The one rule that links them: Gradient takes you DOWN the list (s → v → a).

Area takes you back UP (a → v → s).

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Every motion-graph question is really one of two moves: take a gradient, or take an area. Which one depends on the graph you're looking at.

GraphIts gradient givesThe area under it gives
s–t (displacement–time)velocitynothing useful
v–t (velocity–time)accelerationdisplacement
a–t (acceleration–time)(not required)change in velocity

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Read the shape first: Before you calculate anything, look at the shape — it tells you the story of the motion.

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Now the same for a v–t graph: On a velocity–time graph the vertical axis is the velocity itself — so above the axis means forwards, below means backwards, and the area is the displacement.

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IB-style questionDetermine[3 marks]

A runner's displacement–time graph is a straight line passing through (0 s, 0 m) and (5.0 s, 40 m). Determine her velocity, and state what a horizontal section of the graph would mean.

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How this is tested — graph questions are everywhere in physics. They come in two flavours:

Paper 1A

  • 'Which graph shows the same motion?'
  • Match an s–t to its v–t (or a–t).

Paper 2

  • Calculate from a gradient or an area.
  • Describe the motion in words.
The classic traps: Flat s–t means STOPPED — it's a flat v–t that means steady speed. Students mix these two up constantly.

The gradient of an s–t graph is the velocity, not the acceleration.

There is no useful area under an s–t graph.

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IB-style questionDescribe[4 marks]

A cyclist's displacement–time graph is horizontal for the first 10 s, then a straight slope for the next 20 s, then a curve that gets steeper for the final 10 s. Describe the motion in each stage.

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Test yourself on Motion graphs: s–t, v–t and a–t. Write your answer and get instant AI feedback — just like a real IB examiner.

An object moves with a constant acceleration of 3.0 m s⁻² for 5.0 s.

Its acceleration–time graph is therefore a horizontal line at 3.0 m s⁻².

the change in the object's velocity during this time, and how this is found from the graph.
[2 marks]

Related Physics Topics

Continue learning with these related topics from the same unit:

1.1.1Velocity and displacement
1.1.2Acceleration
1.1.3Displacement from a velocity–time graph
1.1.4The suvat equations
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