Back to Topic 4.3 — Motion in electromagnetic fields
4.3.1Physics SL11 flashcards

Force on a current-carrying conductor

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Card 1 of 114.3.1
4.3.1
Question

What is the motor effect?

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All 11 Flashcards — Force on a current-carrying conductor

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Card 1definition

Question

What is the motor effect?

Answer

A wire carrying a **current** in a **magnetic field** feels a **force** (a sideways push) — the principle behind electric motors.

Card 2formula

Question

State the equation for the force on a current-carrying wire.

Answer

$F = BIL\sin\theta$ — force = field strength × current × length × sin(angle between current and field). Given in the data booklet.

Card 3definition

Question

In F = BIL sin θ, what is θ?

Answer

The **angle between the current and the magnetic field**. When the wire is perpendicular to the field, θ = 90° and sin θ = 1, so F = BIL.

Card 4definition

Question

What is the unit of magnetic field strength B?

Answer

The **tesla (T)**.

Card 5concept

Question

When is the force on a current-carrying wire the largest?

Answer

When the current is **at right angles** to the field (θ = 90°, sin θ = 1).

Card 6concept

Question

When is the force on a current-carrying wire zero?

Answer

When the current runs **along (parallel to)** the field (θ = 0°, sin 0° = 0).

Card 7concept

Question

State Fleming's left-hand rule.

Answer

On the **left** hand at right angles: **F**irst finger = **F**ield, se**C**ond finger = **C**urrent, thu**M**b = force/**M**otion.

Card 8concept

Question

How are field B, current I and force F arranged?

Answer

All three are **mutually perpendicular** (at right angles to one another).

Card 9concept

Question

What happens to the force if you reverse the current?

Answer

The **force reverses** direction. (Reversing the field does the same.)

Card 10concept

Question

Double the current in a wire (field and length fixed) — what happens to the force?

Answer

The force **doubles** — F = BIL, so F is proportional to I.

Card 11example

Question

A 0.10 m wire carries 2.0 A at right angles to a 0.50 T field. Force?

Answer

F = BIL = 0.50 × 2.0 × 0.10 = 0.10 N.

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