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NotesPhysicsTopic 4.3Force on a current-carrying conductor
Back to Physics Topics
4.3.15 min read

Force on a current-carrying conductor

IB Physics · Unit 4

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Contents

  1. 1The motor effect
  2. 2The force equation F = BIL sin θ
  3. 3Exam-style question
The big idea: Switch on a fan or a cordless drill and something inside spins — a coil of wire carrying a current, sitting in a magnet's field, gets shoved sideways.

The motor effect

  • That sideways push on a current-carrying wire is the motor effect.
  • The push is strongest when the current flows at right angles to the field.
  • There is no push when the current runs along the field.

Why the wire is pushed

A current-carrying wire between magnet poles pushed towards the weaker field, a wire at angle θ to a field, and a current loop pushed outwards
Stronger field on one side, weaker on the other: F = BIL sin θ, at right angles to B and I.
Spot it: Three things meet at the wire and they are all at right angles to each other: the field B, the current I, and the force F.

Reverse the current or reverse the field and the force flips the other way.

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The size of the force on the wire depends on the field strength B, the current I, the length of wire in the field L, and the angle between the current and the field:

Force on a current-carrying wire. F in newtons, B in tesla (T), I in amps, L in metres. θ is the angle between the current and the field.
force on the wire (N)
magnetic field strength / flux density (T, tesla)
current in the wire (A)
length of wire in the field (m)
angle between the current and the magnetic field
The most common case: Most questions set the wire at right angles to the field, so θ = 90° and sin θ = 1.

The equation then becomes the simpler F = BIL — that is the form you usually use.

When the wire is perpendicular to the field (sin θ = 1): F = B × I × L. Cover the one you want — letters side by side → multiply (F = B I L); one above the others → divide (e.g. B = F ÷ (I L)).

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B from a graph: At right angles to the field, F = BIL: a graph of F against I is a straight line through the origin with gradient BL.

So B = gradient ÷ L, or B = ΔF/(LΔI) from two readings.
IB-style questionCalculate[2 marks]

A straight wire of length 0.25 m carries a current of 4.0 A at right angles to a magnetic field of strength 0.30 T. Find the force on the wire.

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How this is tested — the motor effect shows up two ways in exams:

Paper 1A

  • Size: F = BIL — often rearranged to find B from how the force changes with the current.
  • Direction: Fleming's left-hand rule for the force on a wire, rod or coil in a field.

Paper 2

  • Extended F = BIL calculations — finding B, the current, or the length of wire in the field.
The classic trap: If the current runs parallel to the field (θ = 0°, sin 0° = 0) the force is zero — not maximum.
Fleming's left-hand rule: Hold the left hand with thumb and first two fingers at right angles:

- First finger → Field (B), from north to south. - SeCond finger → Current (I). - ThuMb → Motion / force (F).

Reverse the current or the field, and the force reverses.
IB-style questionDetermine[4 marks]

A horizontal rod lies across two rails and carries a current flowing from left to right, with a magnetic field pointing straight out of the page toward you. (a) Use the left-hand rule to state the direction of the force on the rod. (b) A 0.20 m length of the same rod carries 5.0 A at right angles to the field and feels a force of 0.60 N. Find the magnetic field strength B.

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A 0.30 m length of wire lies at right angles to a 0.50 T field, and the force on it is 0.045 N.

Show that the current is about 0.3 A.
[1 mark]

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