Back to Topic 1.3 — Work, energy and power
1.3.4Physics SL11 flashcards

Elastic potential energy

Practice Flashcards

Flip to reveal answers
Card 1 of 111.3.4
1.3.4
Question

Define elastic potential energy.

Click to reveal answer

Track your progress — Sign up free to save your progress and get smart review reminders based on spaced repetition.

All 11 Flashcards — Elastic potential energy

Sign up free to track progress and get spaced-repetition review schedules.

Card 1definition

Question

Define elastic potential energy.

Answer

The energy **stored in a spring** (or springy material) when it is **stretched or squashed**. Unit: the joule (J).

Card 2formula

Question

Formula for elastic potential energy?

Answer

$E_H = \tfrac{1}{2}k\,\Delta x^{2}$ — half × spring constant × extension squared. (Also written E_p = ½kx².)

Card 3definition

Question

What is the spring constant k?

Answer

How **stiff** a spring is — the force needed per metre of stretch. Unit: N m⁻¹ (newtons per metre).

Card 4definition

Question

What does Δx mean in E_H = ½kΔx²?

Answer

The **extension or compression** — how far the spring is stretched or squashed from its natural length, in metres.

Card 5concept

Question

You double a spring's extension — what happens to the stored energy?

Answer

It becomes **four times** as big, because the extension is squared (2² = 4).

Card 6process

Question

How do you find the energy stored in a spring-coupled collision?

Answer

By conservation of energy: **E_H = kinetic energy before − kinetic energy of the combined motion**.

Card 7process

Question

How do you find the carts' common speed in a spring collision?

Answer

From **conservation of momentum**: total momentum before = (combined mass) × common speed.

Card 8definition

Question

What is the unit of elastic potential energy?

Answer

The **joule (J)** — the same unit as all other forms of energy.

Card 9example

Question

Find the energy stored: k = 300 N m⁻¹, Δx = 0.020 m.

Answer

E_H = ½ × 300 × 0.020² = ½ × 300 × 0.0004 = 0.060 J.

Card 10example

Question

A spring releases 0.60 J in 0.015 s. Find the average power.

Answer

Power = energy ÷ time = 0.60 ÷ 0.015 = 40 W.

Card 11comparison

Question

Elastic PE vs gravitational PE — what's the difference?

Answer

Elastic PE (½kΔx²) is stored by **stretching/squashing** a spring; gravitational PE (mgΔh) is stored by **lifting** a mass to a height. Both are in joules.

Track your progress with spaced repetition

Sign up free — Aimnova tells you exactly which cards to review and when, so you remember everything before your IB exam.

Start Free