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NotesMath AI HLTopic 4.16Confidence intervals for a mean
Back to Math AI HL Topics
4.16.13 min read

Confidence intervals for a mean

IB Mathematics: Applications and Interpretation • Unit 4

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Contents

  • From one sample mean to a confidence interval
  • Interpreting the interval, and what changes its width
One sample is never the whole truth: Suppose a factory wants the true mean lifetime of all the millions of bulbs it makes. It can't test every bulb, so it tests a small sample and gets a sample mean, say 1180 hours.

If it tested a different sample it would get a slightly different mean — 1175, 1192, … The sample mean wobbles around the real value but rarely hits it exactly.

A confidence interval turns that single wobbly number into an honest range of believable values for the true mean, like "between 1136 and 1224 hours".

So how wide should that range be, and how do we build it?
What '95% confidence' actually means: A 95% confidence interval is built by a method that, used over and over on fresh samples, captures the true mean about 95% of the time.

We write a single interval like (a, b) and say: "we are 95% confident the true population mean lies between a and b."

The interval is centred on the sample mean x̄ and reaches out a margin of error on each side.
CI for a mean (population variance unknown): centre x̄, margin t*·s_{n-1}/√n. The t-value uses df = n − 1.
Why t and not z, and why s_{n-1}: We almost never know the true population standard deviation, so we estimate it from the sample. The unbiased estimate is sn-1 — the GDC's 'sample standard deviation' that divides by n − 1, not n.

Because we're estimating the spread too, the right distribution is the t-distribution with n − 1 degrees of freedom (slightly wider than the normal to allow for that extra uncertainty). On the GDC you never look t up by hand — the t-interval menu does it all.

IB-style question — build a 95% interval from summary stats

A botanist measures the heights of a random sample of 8 seedlings of a new variety. The sample mean is x̄ = 24.5 cm with unbiased standard deviation sn-1 = 2.8 cm.

Find a 95% confidence interval for the mean height of all seedlings of this variety.

Step by step

  1. Write the formula. The centre is the sample mean; the margin uses t with df = n − 1.
  2. On the GDC choose the t-interval and enter summary stats: x̄ = 24.5, sn-1 = 2.8, n = 8, C-Level = 0.95.
  3. Margin of error = t* × sn-1/√n.
  4. Interval = centre ± margin.

Final answer

The 95% confidence interval is (22.2 cm, 26.8 cm) (3 s.f.). We are 95% confident the true mean seedling height is between about 22.2 and 26.8 cm.

A wider net is safer but vaguer: An interval is only useful if you can read it. Picture two coffee machines.

Machine A gives a 95% interval of (245 mL, 251 mL) for its mean fill — tight and informative.

Machine B gives (230 mL, 266 mL) — so wide it barely says anything useful.

A narrow interval is a precise estimate; a wide one is vague. Two things control the width: how big your sample is and how confident you insist on being.

Which way does each one push the width?
The two levers on width: Look at the margin t·s_{n-1}/√n:[[LINEBREAK]]Bigger sample n → you divide by a larger √n, so the margin SHRINKS → narrower interval (more data = more precision).[[LINEBREAK]]Higher confidence (90% → 95% → 99%) → t gets bigger, so the margin GROWS → wider interval (to be more certain of trapping μ, you must cast a wider net).

The sample mean x̄ stays the centre; only the reach on each side changes.

IB-style question — quadruple the sample

A drinks company estimates the mean fill volume of its cans. From a sample, x̄ = 500 mL with sn-1 = 20 mL.

(a) Find the 95% interval when n = 16. (b) Find the 95% interval when n = 64, and comment on the effect of the larger sample.

Step by step

  1. (a) df = 16 − 1 = 15. GDC t-interval with x̄ = 500, s = 20, n = 16, 95%.
  2. So the n = 16 interval, to 3 s.f.
  3. (b) df = 64 − 1 = 63. Same x̄ and s, but n = 64.
  4. So the n = 64 interval.

Final answer

(a) (489, 511) mL. (b) (495, 505) mL. Quadrupling n (16 → 64) roughly halves the margin (because √n doubled), so the interval is about half as wide — the larger sample gives a more precise estimate of the true mean fill.

IB-style question — raise the confidence level

A teacher takes a random sample of n = 25 test scores: x̄ = 72 marks, sn-1 = 10 marks.

Find the 90% and the 99% confidence intervals for the mean score, and state which is wider and why.

Step by step

  1. df = 25 − 1 = 24 for both. 90% first (GDC t-interval, C-Level 0.90).
  2. So the 90% interval.
  3. Now 99% (C-Level 0.99): the t-value is larger, so the margin grows.
  4. So the 99% interval.

Final answer

90%: (68.6, 75.4); 99%: (66.4, 77.6). The 99% interval is wider — demanding more confidence (a 99% capture rate) forces a larger t*, so the net must reach further to be that sure of containing the true mean.

IB Exam Questions on Confidence intervals for a mean

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How Confidence intervals for a mean Appears in IB Exams

Examiners use specific command terms when asking about this topic. Here's what to expect:

Define

Give the precise meaning of key terms related to Confidence intervals for a mean.

AO1
Describe

Give a detailed account of processes or features in Confidence intervals for a mean.

AO2
Explain

Give reasons WHY — cause and effect within Confidence intervals for a mean.

AO3
Evaluate

Weigh strengths AND limitations of approaches in Confidence intervals for a mean.

AO3
Discuss

Present arguments FOR and AGAINST with a balanced conclusion.

AO3

See the full IB Command Terms guide →

Related Math AI HL Topics

Continue learning with these related topics from the same unit:

4.1.1Population and Samples
4.1.2Data Classification
4.1.3Sampling Techniques
4.1.4Data Reliability and Outliers
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