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v0.1.899
NotesMath AI HLTopic 3.4Area of Sector
Back to Math AI HL Topics
3.4.21 min read

Area of Sector

IB Mathematics: Applications and Interpretation • Unit 3

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Contents

  • Area of sector formula
  • Finding radius or angle from area
  • Arc length + area together
  • IB context problems — sector area
A sector is a fraction of the full circle area: A sector with angle θ covers a fraction θ/360 of the full circle area (πr²).

[Diagram: math-arc-sector] - Available in full study mode

Worked example — sector area

Find the area of a sector with radius 10 cm and angle 108°.

Step by step

  1. Substitute.
  2. Evaluate.

Final answer

Area = 30π ≈ 94.2 cm².

Worked example — find the angle

A sector of radius 8 cm has area 32π cm².

Find its angle.

Step by step

  1. Substitute into the area formula.
  2. Cancel π and rearrange.
  3. Solve for θ.

Final answer

Angle = 180° (a semicircle).

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Worked example — find both arc and area

A sector has radius 6 cm and angle 150°.

Find:

(a) the arc length,

(b) the area.

Step by step

  1. (a) Arc length.
  2. (b) Sector area.

Final answer

Arc length ≈ 15.7 cm; Area ≈ 47.1 cm².

IB-style question — an annular sector (a ring)

A metal washer is shaped like an annular sector: a sector of a large circle with a smaller sector removed. The outer radius is 8 cm, the inner radius is 5 cm, and the central angle is 120°.

Find the area of the annular sector.

Step by step

  1. Take the big sector and subtract the small sector — both share the 120° angle, so subtract the radii squared.
  2. Substitute R = 8, r = 5, θ = 120°.
  3. Evaluate.

Final answer

A = 13π ≈ 40.8 cm².

[Diagram: math-sector] - Available in full study mode

Worked example — pizza slice

A circular pizza has diameter 30 cm.

It is cut into 8 equal slices.

Find the area of one slice.

Step by step

  1. Each slice has angle θ = 360/8 = 45°. Radius = 15 cm (half of diameter).
  2. Area of one slice.

Final answer

Area of one slice ≈ 88.4 cm².

IB-style question — a curved track (area → volume)

A curved section of running track is an annular sector with outer radius 30 m, inner radius 24 m and central angle 100°.

(a) Find the area of the track surface.

(b) The surface is covered with rubber 0.05 m deep. Find the volume of rubber needed.

Step by step

  1. (a) Annular-sector area = (θ/360) × π(R² − r²) with R = 30, r = 24, θ = 100°.
  2. Evaluate the area.
  3. (b) The rubber is a thin layer: volume = surface area × depth.

Final answer

(a) ≈ 283 m². (b) ≈ 14.1 m³.

[Diagram: math-sector] - Available in full study mode

IB Exam Questions on Area of Sector

Practice with IB-style questions filtered to Topic 3.4.2. Get instant AI feedback on every answer.

Practice Topic 3.4.2 QuestionsBrowse All Math AI HL Topics

How Area of Sector Appears in IB Exams

Examiners use specific command terms when asking about this topic. Here's what to expect:

Define

Give the precise meaning of key terms related to Area of Sector.

AO1
Describe

Give a detailed account of processes or features in Area of Sector.

AO2
Explain

Give reasons WHY — cause and effect within Area of Sector.

AO3
Evaluate

Weigh strengths AND limitations of approaches in Area of Sector.

AO3
Discuss

Present arguments FOR and AGAINST with a balanced conclusion.

AO3

See the full IB Command Terms guide →

Related Math AI HL Topics

Continue learning with these related topics from the same unit:

3.1.1Distance & midpoint in 2D
3.1.2Distance & midpoint in 3D
3.1.3Volume and Surface Area of 3D Solids
3.10.1Vector definitions
View all Math AI HL topics

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