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NotesMath AI HLTopic 3.12Vectors in kinematics — position, velocity, speed
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3.12.11 min read

Vectors in kinematics — position, velocity, speed

IB Mathematics: Applications and Interpretation • Unit 3

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Contents

  • Position as a moving vector: r(t) = r₀ + t·v
  • Velocity vector and speed = |v|
Start where you are, then drift by v every second: Picture a drone hovering at a starting point, then gliding off at a steady velocity.

Its position after t seconds is

r(t) = r₀ + t·v

— the starting position r₀ plus the velocity vector v added on t times. Each second, the drone's coordinates shift by exactly the components of v. To find where it is at any time, just substitute the value of t.
Constant-velocity motion: position = start + time × velocity.

IB-style question — find a position from r(t)

A delivery drone starts at the point (2, 1) km and flies with constant velocity v = (3, 4) km/h, where t is in hours.

Write down its position vector r(t), then find where it is after 2 hours.

Step by step

  1. Position = start + t × velocity.
  2. Substitute t = 2.

Final answer

r(t) = (2 + 3t, 1 + 4t); after 2 hours the drone is at (8, 9) km.

Velocity is a vector; speed is its length: Velocity v is a vector — it carries both direction and rate. If the position is written as r(t) = r₀ + t·v, the velocity is simply the vector multiplying t (the coefficient of t in each coordinate).

Speed is a single number — how fast, ignoring direction. It is the magnitude (length) of the velocity vector:

speed = |v| = √(vₓ² + vy²) (Pythagoras on the components).
Speed is the length of the velocity vector.

IB-style question — read off velocity, find speed

An ice-skater's position (in metres) is r(t) = (4 + 6t, 12 − 8t), with t in seconds.

Find the skater's velocity vector and speed.

Step by step

  1. Velocity is the vector multiplying t (the coefficient of t in each coordinate).
  2. Speed = length of v, by Pythagoras on the components.
  3. Evaluate.

Final answer

Velocity v = (6, −8) m/s; speed = 10 m/s. (The skater moves right and downward at 10 m/s.)

IB-style question — integrate acceleration

A ball is launched from the origin with acceleration a(t) = (2, −10) m s⁻² and initial velocity v(0) = (8, 15) m s⁻¹.

Find its position vector r(t), and the horizontal distance travelled when it returns to ground level (y = 0).

Step by step

  1. Integrate acceleration for velocity; the constant of integration is v(0).
  2. Integrate again for position; the constant is r(0) = (0, 0).
  3. Ground level: set the y-component to 0 and solve.
  4. Horizontal distance is the x-component at t = 3.

Final answer

r(t) = (t² + 8t, −5t² + 15t); it lands after 3 s, 33 m horizontally from the start. (Integrate twice; initial velocity and position are the constants.)

Velocity vs speed — don't mix them up: Velocity = a vector like (6, −8) (it has components and a direction).

Speed = one number like 10 (always positive, no direction).

If a question asks 'how fast', it wants the speed (a magnitude); if it asks for 'velocity', leave it as a vector.

Try an IB Exam Question — Free AI Feedback

Test yourself on Vectors in kinematics — position, velocity, speed. Write your answer and get instant AI feedback — just like a real IB examiner.

A boat moves with constant velocity. Its position (km) is r(t) = (3 + 4t, −2 + 3t), with t in hours. Write down its velocity vector and find its speed. [2 marks]

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3.1.1Distance & midpoint in 2D
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3.10.1Vector definitions
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