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NotesMath AA SLTopic 2.7
Unit 2 · Functions · Topic 2.7

IB Math AA SL — Quadratic equations & discriminant

Topic 2.7 of IB Mathematics: Analysis and Approaches covers Quadratic equations & discriminant, which is part of Unit 2: Functions. Students explore key concepts including Solving quadratics, The discriminant, Quadratic inequalities. A strong understanding of quadratic equations & discriminant is essential for IB Math AA SL exams and builds the foundation for connected topics across the syllabus.

Exam technique guidePractice questions

Key concepts in Quadratic equations & discriminant

Key Idea: Quadratics turn up everywhere in Unit 2 — you'll solve them, count their real roots with the discriminant, and read off where they're positive or negative. It's mostly Paper 1 (by hand), with the GDC as a Paper-2 shortcut.

🔢 First: set it to = 0, then choose a method

x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}x=2a−b±b2−4ac​​
a,b,ca, b, ca,b,c
read off ax² + bx + c = 0 — equation set to zero first
±\pm±
the two roots — keep both signs
b2−4acb^2 - 4acb2−4ac
the bit under the root: the discriminant Δ

🔎 The discriminant: Δ = b² − 4ac

Δ=b2−4ac\Delta = b^2 - 4acΔ=b2−4ac
Δ\DeltaΔ
the discriminant — the sign counts the real roots
a,b,ca, b, ca,b,c
from ax² + bx + c = 0 (set to zero first)
'Equal roots' → Δ = 0 (an equation); 'two distinct roots' → Δ > 0; 'no real roots' → Δ < 0. A line is tangent to a parabola when they meet once — set them equal, form a quadratic, use Δ = 0. To solve a quadratic inequality: get one side to = 0, find the roots, then let the parabola decide. Upward (a > 0): negative BETWEEN the roots, positive OUTSIDE. Write 'between' as one chain (p ≤ x ≤ q), 'outside' as two pieces joined by or.

✏️ IB-style worked examples

IB-style question — solve with the quadratic formula (Paper 1)

Solve 3x² + 5x − 1 = 0, giving your answers to 3 s.f.

Step by step:

  1. Read off a, b, c and substitute into the formula.

    a=3,  b=5,  c=−1  ⇒  x=−5±52−4(3)(−1)2(3)a = 3,\; b = 5,\; c = -1 \;\Rightarrow\; x = \frac{-5 \pm \sqrt{5^2 - 4(3)(-1)}}{2(3)}a=3,b=5,c=−1⇒x=2(3)−5±52−4(3)(−1)​​
  2. Simplify under the root — the −4ac becomes +12.

    x=−5±376x = \frac{-5 \pm \sqrt{37}}{6}x=6−5±37​​
  3. Take each sign separately.

    x=0.180…  or  x=−1.85…x = 0.180\ldots \;\text{or}\; x = -1.85\ldotsx=0.180…orx=−1.85…
Final answer:

x = 0.180 or x = −1.85 (3 s.f.).

IB-style question — find k for equal roots, Δ = 0 (Paper 1)

The equation x² + (k+1)x + 4 = 0 has equal roots. Find the possible values of k.

Step by step:

  1. Equal roots ⇒ Δ = 0. Here a = 1, b = k + 1, c = 4.

    (k+1)2−4(1)(4)=0(k+1)^2 - 4(1)(4) = 0(k+1)2−4(1)(4)=0
  2. Expand and tidy to a quadratic in k.

    k2+2k+1−16=0  ⇒  k2+2k−15=0k^2 + 2k + 1 - 16 = 0 \;\Rightarrow\; k^2 + 2k - 15 = 0k2+2k+1−16=0⇒k2+2k−15=0
  3. Factorise and solve.

    (k+5)(k−3)=0  ⇒  k=−5  or  k=3(k+5)(k-3) = 0 \;\Rightarrow\; k = -5 \;\text{or}\; k = 3(k+5)(k−3)=0⇒k=−5ork=3
Final answer:

k = −5 or k = 3 (either value gives a repeated root).

IB-style question — solve a quadratic inequality (Paper 1)

Solve x² − 2x − 8 > 0.

Step by step:

  1. Find the roots: solve x² − 2x − 8 = 0.

    (x−4)(x+2)=0  ⇒  x=−2,  4(x-4)(x+2) = 0 \;\Rightarrow\; x = -2,\; 4(x−4)(x+2)=0⇒x=−2,4
  2. a = 1 > 0 (upward U); '> 0' means the OUTSIDE regions.

    x<−2  or  x>4x < -2 \;\text{or}\; x > 4x<−2orx>4
Final answer:

x < −2 or x > 4 (two pieces, joined by 'or').

Important: Quadratics almost always have two answers. Keep the ± in the formula and when square-rooting (√9 = 3, but (x−4)² = 9 needs ±3). Watch the signs in −4ac: a negative c makes it positive. And for an inequality, decide between vs outside from the parabola — don't just write the roots.

Tap each card to reveal the answer.

Exam Tips

  • Always rearrange to = 0 first, then pick: factorise (clean), formula (always works), complete the square (when asked), GDC (Paper 2).
  • Quadratic formula is in the booklet — bracket every substitution and watch that −4ac flips sign with a negative c.
  • Δ = b² − 4ac counts roots: > 0 two, = 0 one (touching/tangent), < 0 none — no need to solve.
  • Root-condition → equation/inequality in the unknown: equal roots ⇒ Δ = 0; tangent line ⇒ Δ = 0.
  • Inequalities: find the roots, then read off the parabola — negative between, positive outside (upward); 'outside' uses 'or'.

What you'll learn in Topic 2.7

  • 2.7.1 Solving quadratics
  • 2.7.2 The discriminant
  • 2.7.3 Quadratic inequalities
Suggested study order: Read the notes for each sub-topic below → test yourself with flashcards → attempt practice questions → review exam technique.

Study resources — 2.7 Quadratic equations & discriminant

2.7.1

Solving quadratics

Notes
2.7.2

The discriminant

Notes
2.7.3

Quadratic inequalities

Notes

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Topic 2.7 Quadratic equations & discriminant forms a core part of Unit 2: Functions in IB Math AA SL. Mastering these concepts will strengthen your understanding of connected topics across the syllabus and prepare you for exam questions that require analysis, evaluation, and real-world application.

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