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NotesMath AA SLTopic 2.4
Unit 2 · Functions · Topic 2.4

IB Math AA SL — Key features of graphs

Topic 2.4 of IB Mathematics: Analysis and Approaches covers Key features of graphs, which is part of Unit 2: Functions. Students explore key concepts including Key features, GDC intersections. A strong understanding of key features of graphs is essential for IB Math AA SL exams and builds the foundation for connected topics across the syllabus.

Exam technique guidePractice questions

Key concepts in Key features of graphs

Key Idea: Reading a graph means naming its landmarks — intercepts, turning points and asymptotes — and finding where two graphs meet. It runs through both papers: by hand on Paper 1, on the GDC for Paper 2.

🗺️ The key-features menu

Maximum value wants a y-coordinate; maximum point wants coordinates (x, y); where the maximum occurs wants the x-coordinate. The words zero, root and x-intercept all mean the same thing — set y = 0.
Where graphs cross, that point lies on both curves, so its x makes f(x) = g(x). On Paper 1, set f(x) = g(x), move everything to one side, solve, then substitute each x back for its y. On Paper 2, graph both and use intersect. Solving f(x) = k is just meeting the line y = k (k = 0 gives the x-intercepts).

✏️ IB-style worked examples

IB-style question — find the intercepts

Find the intercepts of f(x) = (x − 3)(x + 5).

Step by step:

  1. x-intercepts (zeros): set each factor to 0.

    x=3  and  x=−5x = 3 \;\text{and}\; x = -5x=3andx=−5
  2. y-intercept: set x = 0.

    f(0)=(−3)(5)=−15f(0) = (-3)(5) = -15f(0)=(−3)(5)=−15
Final answer:

Zeros at x = 3 and x = −5; y-intercept (0, −15).

IB-style question — state the minimum point and value

State the minimum point and minimum value of f(x) = (x − 4)² − 7.

Step by step:

  1. Vertex form a(x − h)² + k turns at (h, k).

    (h,k)=(4,−7)(h, k) = (4, -7)(h,k)=(4,−7)
  2. a = 1 > 0, so it opens up — it's a minimum.

    min point (4,−7)\text{min point } (4, -7)min point (4,−7)
Final answer:

Minimum point (4, −7); minimum value −7.

IB-style question — find where two graphs meet (Paper 1)

Find where y = x² + 2 meets y = 3x + 2, without a calculator.

Step by step:

  1. Set the two equal.

    x2+2=3x+2x^2 + 2 = 3x + 2x2+2=3x+2
  2. Bring everything to one side.

    x2−3x=0x^2 - 3x = 0x2−3x=0
  3. Factor and solve.

    x(x−3)=0  ⇒  x=0 or x=3x(x - 3) = 0 \;\Rightarrow\; x = 0 \text{ or } x = 3x(x−3)=0⇒x=0 or x=3
  4. Substitute each x back (use y = 3x + 2) for its y.

    (0,2) and (3,11)(0, 2) \text{ and } (3, 11)(0,2) and (3,11)
Final answer:

They meet at (0, 2) and (3, 11).

Important: Solving f(x) = g(x) (or f(x) = k) gives the x-values only. The question almost always wants points, so substitute each x back to get its y. And check for every crossing — a parabola meets a line at up to two points.

Tap each card to reveal the answer.

Exam Tips

  • Match the wording: value → y-coordinate, point → (x, y), where → x-coordinate.
  • Zero = root = x-intercept (set y = 0); y-intercept comes from x = 0.
  • Vertical asymptote: denominator = 0. Horizontal asymptote: what y levels off to as x → ±∞.
  • Intersections solve f(x) = g(x); f(x) = k meets the line y = k. Always finish with the y-coordinate.
  • Paper 2: CALC menu — 2:zero, 3:minimum, 4:maximum, 5:intersect — and check for more than one crossing.

What you'll learn in Topic 2.4

  • 2.4.1 Key features
  • 2.4.2 GDC intersections
Suggested study order: Read the notes for each sub-topic below → test yourself with flashcards → attempt practice questions → review exam technique.

Study resources — 2.4 Key features of graphs

2.4.1

Key features

Notes
2.4.2

GDC intersections

Notes

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Topic 2.4 Key features of graphs forms a core part of Unit 2: Functions in IB Math AA SL. Mastering these concepts will strengthen your understanding of connected topics across the syllabus and prepare you for exam questions that require analysis, evaluation, and real-world application.

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