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NotesMath AATopic 3.2Right-angled trig
Back to Math AA Topics
3.2.11 min read

Right-angled trig

IB Mathematics: Analysis and Approaches • Unit 3

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Contents

  • SOH-CAH-TOA
  • Finding a side
  • Finding an angle
  • Combining with Pythagoras
Three ratios, one mnemonic: In a right-angled triangle, label the sides relative to the angle θ: opposite, adjacent, hypotenuse (the longest, opposite the right angle). Then SOH-CAH-TOA.

Interactive: tap sin θ, cos θ or tan θ to highlight which two sides (opp / adj / hyp) each ratio uses.

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SOH-CAH-TOA — only for right-angled triangles.
Label first: Mark the hypotenuse (opposite the right angle), then opposite and adjacent relative to your angle — the labels change if the angle does.

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Pick the ratio with your two sides: Choose the ratio (sin/cos/tan) that links the angle, the side you want, and a side you know. Then rearrange to make the unknown the subject.

IB-style question — find a side

A right triangle has hypotenuse 10 and an angle of 30°. Find the side opposite the 30° angle.

Step by step

  1. Opposite and hypotenuse → use sin.
  2. Rearrange.

Final answer

The opposite side is 5.

The opposite side x and the hypotenuse 10 sit either side of the 30° angle — that pair is sin. sin 30° = x ÷ 10, so x = 10 sin 30° = 5.

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Unknown on the bottom?: If the unknown is the denominator (e.g. cos θ = 4/x), multiply up and divide: x = 4/cos θ.

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Use the inverse trig button: If you know two sides, form the right ratio, then take the inverse (sin⁻¹, cos⁻¹, tan⁻¹) to get the angle.

IB-style question — find an angle

A right triangle has opposite side 3 and adjacent side 4. Find θ.

Step by step

  1. Opposite and adjacent → use tan.
  2. Inverse tangent.

Final answer

θ ≈ 36.9°.

We know the two legs — opposite 3 and adjacent 4 — and want the angle, so use tan: tan θ = 3 ÷ 4, θ = tan⁻¹(3/4) ≈ 36.9°.

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Calculator mode: Make sure your GDC is in degrees (or radians) to match the question — a mode mismatch is a classic lost mark.
Sides only? Use Pythagoras: If a problem gives two sides and wants the third (no angle), use Pythagoras a² + b² = c². Trig is for when an angle is involved.

IB-style question — two-step

A right triangle has legs 5 and 12. Find the hypotenuse, then the angle opposite the side of length 5.

Step by step

  1. Hypotenuse by Pythagoras.
  2. Angle: opposite 5, hypotenuse 13.

Final answer

Hypotenuse 13; angle ≈ 22.6°.

Pythagoras first gives the hypotenuse √(5² + 12²) = 13. Then the angle uses the opposite (5) and that hypotenuse (13): sin θ = 5 ÷ 13 → θ ≈ 22.6°.

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Pythagoras = no angle: Three sides, no angle → Pythagoras. Need or have an angle → SOH-CAH-TOA.

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A right-angled triangle has hypotenuse 20 and an angle of 35°. Find the length of the side opposite the 35° angle, to 3 s.f. [2 marks]

Related Math AA Topics

Continue learning with these related topics from the same unit:

3.1.1Distance & midpoint (3D)
3.1.2Volume & surface area
3.1.3Angles in 3D
3.1.4Solids in 3D coordinates
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