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NotesMath AA HLTopic 1.15Disproving with a counterexample
Back to Math AA HL Topics
1.15.33 min read

Disproving with a counterexample (Math AA HL)

IB Mathematics: Analysis and Approaches · Unit 1

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Contents

  1. 1What a counterexample is
  2. 2Choosing a good counterexample
  3. 3Exam-style question
What a counterexample is: A claim that something holds for all values is destroyed by one value where it fails — that single value is a counterexample. One is enough to disprove a “for all” statement.

One example is enough

Disprove the claim: “every prime number is odd.”

Step by step

  1. One case is enough. The claim says all primes are odd, so a single even prime would break it.
  2. Test . Its only factors are 1 and 2, so it is prime — but is even, not odd.

Final answer

is a prime that is not odd, so the claim is false.

Always explain why: It is not enough to name the value — you must explain why it is a counterexample: show it fits the claim's condition and breaks its conclusion.

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Choosing a good counterexample: Hunt where a claim quietly assumes things away: the value , , , negative numbers, fractions between and , and boundary cases. The awkward values are where claims break.

Try the awkward values

Disprove: “for every real number , .”

Step by step

  1. Whole numbers obey it, so try a fraction. Take .
  2. Check it breaks the claim. , and , so here.

Final answer

gives , so the claim is false.

Where to look: If whole numbers all obey a claim, the counterexample often hides among fractions or negative numbers.

Negatives break it

Disprove: “if then .”

Step by step

  1. Try a negative . Take and , so is true.
  2. Check the conclusion. and , so is false ().

Final answer

, fit but give , so the claim is false.

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An exam-style question

A student claims: “for all real numbers , if then .” Show that this statement is not always true.

Step by step

  1. Look for the awkward case. The claim feels right for large positive , so test a negative value.
  2. Check it fits the “if” part. Take : then , which is greater than 9.
  3. Check it breaks the “then” part. But is not greater than 3.
  4. Say why this disproves the claim. satisfies yet fails , so the statement is not always true.

Final answer

satisfies but is false, so the statement is not always true.

To get full marks

  • Give one clear value, here — a vague “some negative number” is not enough.
  • Show it fits the condition: , which is greater than 9.
  • Explain it breaks the result: is not greater than 3, so the claim fails for this .
  • The value alone, with no check of both parts, can cost marks — the reason is what does the disproving.

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Disprove: 'For all real numbers x, √(x2) = x.' [2 marks]

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