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NotesMath AA HLTopic 1.15Proof by contradiction
Back to Math AA HL Topics
1.15.24 min read

Proof by contradiction (Math AA HL)

IB Mathematics: Analysis and Approaches · Unit 1

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Contents

  1. 1Suppose it is false, then watch it break
  2. 2Why the primes never run out
  3. 3There is no smallest positive fraction
  4. 4Exam-style question
Suppose it is false, then watch it break: Proof by contradiction has three moves: assume the statement is false, reason until you reach something impossible, then conclude the statement must be true after all.

Press play to watch the assumption break line by line.

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Begin with the opposite: Start from the negation, and write “assume” or “suppose”, never “let”. The proof must open by supposing the opposite is true.

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Why the primes never run out: A second flavour: instead of a parity clash, build a new object the assumption says cannot exist. This is Euclid's proof that the primes never run out.

Press play — the built number N is the object that breaks the assumption.

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Build the impossible object: When a parity or factor clash is hard to see, try constructing a number or object the assumption forbids.

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There is no smallest positive fraction: A third flavour: the contradiction is finding something smaller than the supposed smallest. Short and sharp — a contradiction need not be about parity.

Press play — halving r is all it takes to break the claim.

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Beat the extreme: To contradict a “smallest” or “largest” claim, produce one that is smaller (or larger) but still fits.

An exam-style question

Prove by contradiction that the equation has no integer solutions.

Step by step

  1. Assume the opposite. Suppose some integer is a solution.
  2. Move the 1 across. Take the to the other side.
  3. Factor the left side. . If is even this is even; if is odd then is even, so it is even again — the left side is always even.
  4. Spot the clash. The left side is even, but is odd. An even number can never equal an odd one.
  5. Conclude. The assumption leads to an impossibility, so has no integer solutions.

Final answer

No integer solutions (an even number cannot equal the odd ).

To get full marks

  • Start by assuming an integer solution exists, so .
  • Show the left side is always even, while is odd.
  • State the contradiction and conclude there is no integer solution.

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, in one or two lines, what makes a proof by contradiction valid. [2 marks]

Related Math AA HL Topics

Continue learning with these related topics from the same unit:

1.1.1Writing standard form1.1.2Standard form by hand1.10.1Arrangements (order matters)1.10.2Selections (order doesn't matter)
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Improve your exam techniqueCommand terms, paper structure, and mark-scheme tips for Math AA HL
Previous1.15.1Proof by inductionNextDisproving with a counterexample1.15.3

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