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Topic 5.19Math AA HL16 flashcards

Maclaurin series (HL only)

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Card 1 of 165.19.1
5.19.1
Question

What is the coefficient of xⁿ in a Maclaurin series?

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All Flashcards in Topic 5.19

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5.19.18 cards

Card 1formula
Question

What is the coefficient of xⁿ in a Maclaurin series?

Answer

f⁽ⁿ⁾(0) ÷ n! — the nth derivative evaluated at x = 0, divided by n!.

Card 2formula
Question

Write the general Maclaurin series of f(x).

Answer

f(x) = f(0) + f'(0)x + f''(0)x²/2! + f'''(0)x³/3! + …

Card 3concept
Question

Why does the Maclaurin formula divide by n!?

Answer

Differentiating xⁿ exactly n times gives n!; dividing by n! makes the nth term contribute exactly f⁽ⁿ⁾(0) to the nth derivative at 0.

Card 4formula
Question

Maclaurin series of eˣ?

Answer

eˣ = 1 + x + x²/2! + x³/3! + … (every power, denominator n!).

Card 5formula
Question

Maclaurin series of sin x?

Answer

sin x = x − x³/3! + x⁵/5! − … (odd powers only, alternating signs).

Card 6formula
Question

Maclaurin series of cos x?

Answer

cos x = 1 − x²/2! + x⁴/4! − … (even powers only, alternating signs).

Card 7formula
Question

Maclaurin series of ln(1 + x)?

Answer

ln(1 + x) = x − x²/2 + x³/3 − x⁴/4 + … (plain denominators, alternating signs).

Card 8concept
Question

Why does sin x contain only odd powers?

Answer

Every even derivative of sin x equals ±sin 0 = 0, so all even-power coefficients vanish.

5.19.28 cards

Card 9concept
Question

How do you find a Maclaurin series by substitution?

Answer

Take a known series (eˣ, sin x, …) and replace every x by the new expression, e.g. x² into eˣ gives e^{x²} = 1 + x² + x⁴/2! + ….

Card 10formula
Question

Maclaurin series of e^{x²}?

Answer

1 + x² + x⁴/2! + … = 1 + x² + x⁴/2 + … (substitute x² into eˣ).

Card 11formula
Question

Maclaurin series of sin(3x) (first two terms)?

Answer

3x − (3x)³/3! + … = 3x − (9/2)x³ + ….

Card 12concept
Question

How do you get the series of x·sin x?

Answer

Multiply the sin x series by x: x(x − x³/6 + …) = x² − x⁴/6 + ….

Card 13concept
Question

How do you use a Maclaurin series to find a 0/0 limit?

Answer

Replace the function with its series; the leading terms cancel, divide by the matching power, then let x → 0 (the constant term is the limit).

Card 14concept
Question

Evaluate lim(x→0) (sin x − x)/x³.

Answer

sin x − x = −x³/6 + …, so dividing by x³ gives −1/6 as x → 0.

Card 15concept
Question

Evaluate lim(x→0) (1 − cos x)/x².

Answer

1 − cos x = x²/2 − …, so the limit is 1/2.

Card 16concept
Question

When multiplying two series, which terms do you keep?

Answer

Only terms up to the highest power the question requires; discard anything higher to save work.

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IB Math AA HL Topic 5.19 Flashcards | Maclaurin series (HL only) | Aimnova | Aimnova