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Topic 4.5Math AA SL SL18 flashcards

Probability basics

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Card 1 of 184.5.1
4.5.1
Question

How do you find the probability of an event with equally likely outcomes?

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All Flashcards in Topic 4.5

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4.5.19 cards

Card 1formula
Question

How do you find the probability of an event with equally likely outcomes?

Answer

Favourable outcomes ÷ total outcomes: P(A) = n(A)/n(U).

Card 2concept
Question

What range must a probability lie in?

Answer

Between 0 and 1 inclusive.

Card 3formula
Question

What is the complement rule?

Answer

P(A′) = 1 − P(A).

Card 4concept
Question

How do you find P(at least one)?

Answer

Use the complement: 1 − P(none).

Card 5concept
Question

How many outcomes are in the sample space for two dice?

Answer

36 (6 × 6 ordered outcomes).

Card 6concept
Question

In a sample-space grid, do (2,5) and (5,2) count separately?

Answer

Yes — they are different ordered outcomes.

Card 7concept
Question

How do you find the probability of a sequence of events?

Answer

Multiply the probabilities along the chain.

Card 8concept
Question

What changes for 'without replacement'?

Answer

After each draw the totals reduce — one fewer item and one fewer of the drawn type.

Card 9concept
Question

With replacement vs without — what's the difference?

Answer

With replacement the probabilities stay the same each draw; without, they change.

4.5.29 cards

Card 10formula
Question

What is the expected number of occurrences in n trials?

Answer

n × P, where P is the probability of the event each trial.

Card 11concept
Question

Can an expected number be a decimal?

Answer

Yes — it is a long-run average, not a single count.

Card 12concept
Question

What do you do if the probability isn't given directly?

Answer

Find P first (from a sample space, proportion or table), then multiply by n.

Card 13concept
Question

What does the expected number actually represent?

Answer

The average number of occurrences you'd expect over many repeats.

Card 14concept
Question

How do you find an expected total amount?

Answer

Multiply the average per trial (expected value) by the number of trials n.

Card 15concept
Question

Expected number of sixes in 60 rolls of a fair die?

Answer

60 × 1/6 = 10.

Card 16concept
Question

If P(win) = 0.25 over 40 games, expected wins?

Answer

40 × 0.25 = 10.

Card 17concept
Question

Is the expected value guaranteed in one run?

Answer

No — it is a long-run average, so a single run may differ.

Card 18concept
Question

Expected number of heads in 100 fair coin tosses?

Answer

100 × 1/2 = 50.

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