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Topic 2.16Math AA HL16 flashcards

Modulus functions (HL only)

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Card 1 of 162.16.1
2.16.1
Question

How do you draw y = |f(x)| from y = f(x)?

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All Flashcards in Topic 2.16

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2.16.18 cards

Card 1concept
Question

How do you draw y = |f(x)| from y = f(x)?

Answer

Reflect any part below the x-axis up above it; leave the rest unchanged.

Card 2concept
Question

How do you draw y = f(|x|) from y = f(x)?

Answer

Keep the graph for x ≥ 0 and reflect it across the y-axis (the left half is discarded).

Card 3concept
Question

How do you draw y = 1/f(x)?

Answer

Take reciprocals of the heights: zeros of f → vertical asymptotes; large f → near 0; max ↔ min; sign kept.

Card 4concept
Question

Where does y = 1/f(x) have a vertical asymptote?

Answer

Wherever f(x) = 0.

Card 5concept
Question

Is y = f(|x|) always symmetric?

Answer

Yes — it's symmetric in the y-axis (an even function).

Card 6concept
Question

y = |2x − 4|: shape and minimum?

Answer

A V with vertex (2, 0); minimum value 0.

Card 7concept
Question

What happens to a maximum of f under y = 1/f(x)?

Answer

It becomes a minimum of 1/f (with the same sign).

Card 8concept
Question

Difference between |f(x)| and f(|x|)?

Answer

|f(x)| reflects below-axis parts up; f(|x|) mirrors the right half across the y-axis.

2.16.28 cards

Card 9concept
Question

How do you solve |inside| = c?

Answer

Set inside = +c and inside = −c (provided c ≥ 0), and solve both.

Card 10formula
Question

What does |x| < a mean?

Answer

−a < x < a (a band around 0).

Card 11formula
Question

What does |x| > a mean?

Answer

x < −a or x > a (everything outside the band).

Card 12concept
Question

Can |something| equal a negative number?

Answer

No — a modulus is always ≥ 0, so |…| = (negative) has no solution.

Card 13concept
Question

Solve |2x − 1| = 5.

Answer

2x − 1 = ±5 ⇒ x = 3 or x = −2.

Card 14concept
Question

Solve |x − 2| < 3.

Answer

−3 < x − 2 < 3 ⇒ −1 < x < 5.

Card 15concept
Question

How do you solve |f(x)| = |g(x)|?

Answer

f = g or f = −g (or square both sides).

Card 16concept
Question

Solve |2x + 1| ≥ 4.

Answer

2x + 1 ≥ 4 or ≤ −4 ⇒ x ≥ 3/2 or x ≤ −5/2.

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IB Math AA HL Topic 2.16 Flashcards | Modulus functions (HL only) | Aimnova | Aimnova