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Topic 2.12Math AA HL24 flashcards

Factor & remainder (HL only)

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Card 1 of 242.12.1
2.12.1
Question

State the remainder theorem.

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All Flashcards in Topic 2.12

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2.12.18 cards

Card 1formula
Question

State the remainder theorem.

Answer

The remainder when P(x) is divided by (x − a) is P(a).

Card 2formula
Question

State the factor theorem.

Answer

(x − a) is a factor of P(x) if and only if P(a) = 0.

Card 3concept
Question

How do you find the remainder on dividing by (x − a)?

Answer

Substitute: the remainder is P(a) — no long division needed.

Card 4concept
Question

How does a given factor or remainder help find unknowns?

Answer

It gives an equation (P(value) = 0 for a factor, or = remainder); solve the equations together.

Card 5concept
Question

What does (x − a)² being a factor require?

Answer

Both P(a) = 0 and P′(a) = 0 (a is a repeated root).

Card 6concept
Question

Remainder when x³ − 2x² + 5x − 1 is divided by (x − 2)?

Answer

P(2) = 8 − 8 + 10 − 1 = 9.

Card 7concept
Question

Is (x − 1) a factor of x³ − 6x² + 11x − 6?

Answer

P(1) = 1 − 6 + 11 − 6 = 0, so yes.

Card 8concept
Question

Divide by (x + 2): which value do you substitute?

Answer

x = −2 (the root of x + 2).

2.12.28 cards

Card 9formula
Question

Sum and product of roots of ax² + bx + c = 0?

Answer

Sum = −b/a, product = c/a.

Card 10formula
Question

General sum and product of roots of a degree-n polynomial?

Answer

Sum = −aₙ₋₁/aₙ; product = (−1)ⁿ a₀/aₙ.

Card 11formula
Question

Cubic ax³ + bx² + cx + d: sum and product of roots?

Answer

Sum = −b/a; product = −d/a (the (−1)³ makes it negative).

Card 12concept
Question

Why use sum/product instead of solving?

Answer

It reads the symmetric functions of the roots straight off the coefficients — no need to find the roots.

Card 13concept
Question

Roots of 2x² − 6x + 1 = 0: sum and product?

Answer

Sum = 6/2 = 3, product = 1/2.

Card 14concept
Question

Roots of x³ − 4x² + x + 6 = 0: sum and product?

Answer

Sum = 4, product = −6.

Card 15concept
Question

Does the product of roots change sign with degree?

Answer

Yes — it's (−1)ⁿ a₀/aₙ, so + for even degree, − for odd.

Card 16concept
Question

Roots of x² − kx + (k+3) = 0 sum to 5 — find k.

Answer

Sum = k = 5.

2.12.38 cards

Card 17concept
Question

How do you factorise a cubic fully?

Answer

Find one root with the factor theorem, divide it out, then factorise/solve the resulting quadratic.

Card 18concept
Question

Which trial values do you try for a root?

Answer

Small integers — factors of the constant term (±1, ±2, …).

Card 19concept
Question

A real-coefficient polynomial has root a + bi. What else is a root?

Answer

The conjugate a − bi.

Card 20concept
Question

How do you find the last real root once you have a complex pair?

Answer

Use the sum of roots (−b/a): subtract the known roots from it.

Card 21concept
Question

Roots of x³ − 2x² − 5x + 6?

Answer

x = 1, 3, −2 (factorises as (x − 1)(x − 3)(x + 2)).

Card 22concept
Question

Given 1 + i is a root of x³ − 4x² + 6x − 4, find the others.

Answer

1 − i (conjugate) and 2 (from sum of roots = 4).

Card 23concept
Question

How does the leading term affect a polynomial sketch?

Answer

It sets the end behaviour: +xⁿ rises to the right; the parity of n sets the left end.

Card 24concept
Question

How many real roots can a cubic have?

Answer

1 or 3 (complex roots come in pairs, and degree 3 is odd).

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IB Math AA HL Topic 2.12 Flashcards | Factor & remainder (HL only) | Aimnova | Aimnova