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Topic 2.1Math AA HL26 flashcards

Straight lines

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Card 1 of 262.1.1
2.1.1
Question

What is the gradient formula?

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All Flashcards in Topic 2.1

Below are all 26 flashcards for this topic. Sign up free to track your progress and get personalized review schedules.

2.1.110 cards

Card 1formula
Question

What is the gradient formula?

Answer

m = (y₂ − y₁)/(x₂ − x₁) = rise ÷ run. Subtract the coordinates in the same order top and bottom.

Card 2concept
Question

What does the sign of the gradient tell you?

Answer

m > 0 uphill, m < 0 downhill, m = 0 horizontal (y = c), vertical lines (x = a) have no gradient.

Card 3formula
Question

State the three forms of a straight line.

Answer

Gradient–intercept y = mx + c; point–gradient y − y₁ = m(x − x₁); general ax + by + d = 0.

Card 4concept
Question

In y = mx + c, what are m and c?

Answer

m is the gradient; c is the y-intercept (where the line crosses the y-axis).

Card 5concept
Question

How do you get the gradient from ax + by + d = 0?

Answer

Rearrange to y = mx + c — the gradient is m = −a/b.

Card 6concept
Question

How do you find a line from a gradient m and a point (x₁, y₁)?

Answer

Put m into y = mx + c, then substitute the point to find c. (Or use point–gradient form y − y₁ = m(x − x₁).)

Card 7concept
Question

How do you find a line through two points?

Answer

Find the gradient m = (y₂ − y₁)/(x₂ − x₁) first, then substitute one point into y = mx + c to find c.

Card 8concept
Question

How do you find the y-intercept of a line?

Answer

Set x = 0 (or, in y = mx + c, read off c).

Card 9concept
Question

How do you find the x-intercept of a line?

Answer

Set y = 0 and solve for x.

Card 10concept
Question

What are the equations of vertical and horizontal lines?

Answer

Vertical: x = a (gradient undefined). Horizontal: y = b (gradient 0).

2.1.22 cards

Card 11concept
Question

When are two lines parallel?

Answer

When they have the same gradient: m₁ = m₂ (with different y-intercepts).

Card 12concept
Question

How do you find a line through a point parallel to a given line?

Answer

Use the SAME gradient, put it into y = mx + c, then substitute the point to find c.

2.1.36 cards

Card 13concept
Question

When are two lines perpendicular?

Answer

When their gradients multiply to −1: m₁m₂ = −1, i.e. m₂ = −1/m₁.

Card 14concept
Question

How do you get the perpendicular gradient?

Answer

Take the negative reciprocal — flip the fraction and change the sign. E.g. ⅔ → −3/2.

Card 15concept
Question

Perpendicular gradient of 5?

Answer

Write 5 as 5/1; the perpendicular gradient is −1/5.

Card 16concept
Question

How do you find a line through a point perpendicular to a given line?

Answer

Use the negative-reciprocal gradient, put it into y = mx + c, then substitute the point to find c.

Card 17concept
Question

What is a normal to a curve?

Answer

The line perpendicular to the tangent at a point; its gradient is −1/(tangent gradient). Used in calculus.

Card 18concept
Question

Why doesn't m₁m₂ = −1 work for horizontal & vertical lines?

Answer

They are perpendicular, but a vertical line (x = a) has no gradient, so the product rule can't be applied — state it separately.

2.1.48 cards

Card 19concept
Question

What is a perpendicular bisector?

Answer

The line through the midpoint of a segment, perpendicular to it (negative-reciprocal gradient).

Card 20concept
Question

State the three steps to find a perpendicular bisector.

Answer

1) Midpoint of the endpoints. 2) Gradient of the segment, then its negative reciprocal. 3) Substitute the midpoint into y = mx + c.

Card 21formula
Question

Midpoint of (x₁, y₁) and (x₂, y₂)?

Answer

((x₁ + x₂)/2, (y₁ + y₂)/2) — average each coordinate.

Card 22concept
Question

Which gradient does the bisector use?

Answer

The negative reciprocal of the segment's gradient (flip the fraction and change the sign).

Card 23concept
Question

Which point does the bisector pass through?

Answer

The midpoint of the two endpoints — not either endpoint.

Card 24concept
Question

What is special about every point on the perpendicular bisector?

Answer

It is equidistant from the two endpoints (the same distance from A as from B).

Card 25concept
Question

Perpendicular bisector of A(1, 2) and B(5, 8)?

Answer

Midpoint (3, 5); m_AB = 3/2 → bisector gradient −2/3; y = −2/3 x + 7.

Card 26concept
Question

Bisector answer needs general form — what do you do?

Answer

Build y = mx + c first, then clear fractions and move everything to one side: ax + by + d = 0.

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IB Math AA HL Topic 2.1 Flashcards | Straight lines | Aimnova | Aimnova