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Topic 1.15Math AA HL24 flashcards

Proof by induction (HL only)

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Card 1 of 241.15.1
1.15.1
Question

What are the four steps of proof by induction?

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All Flashcards in Topic 1.15

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1.15.18 cards

Card 1concept
Question

What are the four steps of proof by induction?

Answer

Base case (n = 1), assume true for n = k, prove true for n = k + 1, conclude true for all n.

Card 2concept
Question

What's the domino analogy for induction?

Answer

Knock the first domino (base case) and show each knocks the next (k ⇒ k + 1), so they all fall (all n).

Card 3concept
Question

What must the inductive step USE?

Answer

The assumption (the result for n = k) — that's the link that proves n = k + 1.

Card 4concept
Question

How do you finish an induction proof?

Answer

State the conclusion: true for n = 1 and 'true for k ⇒ true for k + 1', so true for all n ∈ ℤ⁺.

Card 5concept
Question

Base case for 1 + 2 + … + n = n(n+1)/2?

Answer

n = 1: LHS = 1, RHS = 1(2)/2 = 1 ✓.

Card 6concept
Question

In a divisibility induction, the key move in the step?

Answer

Rewrite the (k+1) expression so the assumption (e.g. 6ᵏ − 1 = 5m) appears, then factor out the divisor.

Card 7concept
Question

Why is the base case essential?

Answer

Without a true starting case, the chain k ⇒ k + 1 never gets going — nothing is ever shown true.

Card 8concept
Question

What does 'assume true for n = k' mean?

Answer

Take the statement as given for one (unspecified) value k, so you can use it to prove the next case.

1.15.28 cards

Card 9concept
Question

How does proof by contradiction work?

Answer

Assume the statement is false, derive something impossible (a contradiction), so the assumption is wrong and the statement is true.

Card 10concept
Question

What do you assume at the start of a contradiction proof?

Answer

The negation (opposite) of what you want to prove.

Card 11concept
Question

What does reaching a contradiction prove?

Answer

That the assumption (the opposite) is false — so the original statement is true.

Card 12concept
Question

Outline the proof that √2 is irrational.

Answer

Assume √2 = p/q in lowest terms; show p² = 2q² makes both p and q even, contradicting 'no common factor'.

Card 13concept
Question

How do you prove 'if n² is even then n is even' by contradiction?

Answer

Assume n is odd (n = 2k+1); then n² = 2(2k²+2k)+1 is odd, contradicting n² even.

Card 14concept
Question

Prove the sum of a rational and an irrational is irrational — the contradiction?

Answer

Assuming r + x is rational forces x = (r + x) − r to be rational, contradicting x irrational.

Card 15concept
Question

How should you open a contradiction proof in an exam?

Answer

'Assume, for contradiction, that … [the negation].'

Card 16concept
Question

Is a contradiction a mistake?

Answer

No — it's the goal; it shows the assumption can't hold.

1.15.38 cards

Card 17concept
Question

What is a counterexample?

Answer

A single case where a 'for all' statement fails — enough to prove the statement false.

Card 18concept
Question

How many counterexamples disprove a universal statement?

Answer

Just one.

Card 19concept
Question

Where should you look for counterexamples?

Answer

Small numbers (0, 1), negatives, fractions, and edge cases.

Card 20concept
Question

Counterexample to 'all primes are odd'?

Answer

2 — it's prime and even.

Card 21concept
Question

Counterexample to 'a² = b² ⇒ a = b'?

Answer

a = 2, b = −2: 4 = 4 but 2 ≠ −2.

Card 22concept
Question

Counterexample to 'x² ≥ x for all real x'?

Answer

x = ½: ¼ < ½.

Card 23concept
Question

Counterexample to 'the sum of two irrationals is irrational'?

Answer

√2 + (−√2) = 0, which is rational.

Card 24concept
Question

What must you check about a counterexample?

Answer

That it meets the statement's condition (hypothesis) but breaks the conclusion.

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