Back to all Math AA topics
Topic 1.12Math AA HL24 flashcards

Complex numbers: Cartesian (HL only)

Practice Flashcards

Flip cards to reveal answers
Card 1 of 241.12.1
1.12.1
Question

What is i?

Click to reveal answer

Track your progress — Sign up free to save your progress and get smart review reminders based on spaced repetition.

All Flashcards in Topic 1.12

Below are all 24 flashcards for this topic. Sign up free to track your progress and get personalized review schedules.

1.12.18 cards

Card 1concept
Question

What is i?

Answer

The imaginary unit, defined by i² = −1 (so i = √(−1)).

Card 2formula
Question

What is the Cartesian form of a complex number?

Answer

z = a + bi, where a is the real part and b is the imaginary part.

Card 3concept
Question

How do you add or subtract complex numbers?

Answer

Combine the real parts together and the imaginary parts together — they don't mix.

Card 4concept
Question

How do you multiply complex numbers?

Answer

Expand like two brackets (FOIL), then replace every i² with −1 and collect terms.

Card 5concept
Question

(3 + 2i) + (1 − 5i) = ?

Answer

4 − 3i.

Card 6concept
Question

(3 + 2i)(1 − 4i) = ?

Answer

3 − 12i + 2i − 8i² = 3 − 10i + 8 = 11 − 10i.

Card 7formula
Question

Powers of i: i, i², i³, i⁴?

Answer

i, −1, −i, 1 — then the cycle repeats.

Card 8concept
Question

What does i² equal, and why does it matter?

Answer

i² = −1; it's the step that turns a multiplication of complex numbers back into a + bi form.

1.12.28 cards

Card 9formula
Question

What is the conjugate of z = a + bi?

Answer

z* = a − bi — flip the sign of the imaginary part (real part unchanged).

Card 10formula
Question

What is z × z*?

Answer

a² + b², which is always a real number (= |z|²).

Card 11concept
Question

How do you divide complex numbers?

Answer

Multiply top and bottom by the conjugate of the bottom, making the denominator real, then write as a + bi.

Card 12concept
Question

Conjugate of 4 − 7i?

Answer

4 + 7i.

Card 13concept
Question

Why multiply by the conjugate when dividing?

Answer

Because z × z* = a² + b² is real, so it clears the i from the denominator.

Card 14concept
Question

Express (5 + i)/(2 − 3i) as a + bi.

Answer

Multiply by (2 + 3i)/(2 + 3i): (7 + 17i)/13 = 7/13 + (17/13)i.

Card 15concept
Question

On an Argand diagram, where is z*?

Answer

The mirror image of z in the real axis (same real part, opposite imaginary part).

Card 16concept
Question

z × z* for z = 2 + 5i?

Answer

4 + 25 = 29.

1.12.38 cards

Card 17concept
Question

What is an Argand diagram?

Answer

The plane for complex numbers: real part across (horizontal), imaginary part up (vertical).

Card 18concept
Question

Where does z = a + bi sit on an Argand diagram?

Answer

At the point (a, b).

Card 19formula
Question

What is the modulus |z|?

Answer

The distance from the origin to z; |z| = √(a² + b²).

Card 20concept
Question

Why is |z| = √(a² + b²)?

Answer

It's Pythagoras — the point (a, b) is at horizontal distance a and vertical distance b from the origin.

Card 21concept
Question

|3 + 4i| = ?

Answer

√(9 + 16) = √25 = 5.

Card 22concept
Question

|5 − 12i| = ?

Answer

√(25 + 144) = √169 = 13.

Card 23concept
Question

Can the modulus be negative?

Answer

No — it's a distance, so |z| ≥ 0.

Card 24concept
Question

How does the sign of b affect the plot and the modulus?

Answer

It decides up (b > 0) or down (b < 0) on the diagram; the modulus is unaffected because b is squared.

Want smart review reminders?

Sign up free to track your progress. Our spaced repetition algorithm will tell you exactly which cards to review and when.

Start Free
IB Math AA HL Topic 1.12 Flashcards | Complex numbers: Cartesian (HL only) | Aimnova | Aimnova