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v0.1.1435
NotesChemistryTopic 1.1Separation techniques
Back to Chemistry Topics
1.1.33 min read

Separation techniques

IB Chemistry • Unit 1

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Contents

  • Choosing a separation technique
  • Matching the method to the property
  • Chromatography and the R_{f} value
  • Exam-style question
The big idea: Because the parts of a mixture are not chemically bonded, they can be separated by physical means.

The method you choose depends on a physical property in which the components differ — for example their particle size, their solubility, or their boiling point.

There is no single 'best' method — match the technique to the property that differs.

Solid + liquid

  • insoluble solid → filtration
  • dissolved solid → evaporation / crystallisation

Liquid + liquid

  • different boiling points → distillation
  • (immiscible liquids → separating funnel)

Mixture in solution

  • coloured / dissolved components → chromatography
  • separates by solubility
Soluble or insoluble?: The first thing to decide for a solid is whether it dissolves in the chosen solvent.

- Insoluble in the liquid → filter it out. - Soluble (dissolved) → evaporate / crystallise the solution to recover it.

Each technique works because the components differ in one physical property. Learn the technique together with the property it exploits — that is exactly what the exam tests.

TechniqueSeparatesPhysical property exploited
Filtrationan insoluble solid from a liquidparticle size (the solid is too big to pass through the filter paper)
Evaporation / crystallisationa dissolved solid from its solutionboiling point — the solvent boils off, leaving the solid behind
Distillationa liquid from a liquid (or a liquid from a dissolved solid)difference in boiling point
Chromatographythe components of a mixture in solution (e.g. coloured dyes)difference in solubility / attraction to the paper
Worked thinking — a mixture of liquid hydrocarbons: Petrol is a mixture of liquid hydrocarbons that do not react but have different boiling points.

The property that differs is boiling point, so the right technique is distillation (fractional distillation) — not filtration (nothing is an insoluble solid) and not chromatography.
Purifying a solid product: If a reaction makes a solid product that came out of solution, you purify it by crystallisation: dissolve it in hot solvent, let it cool so pure crystals form, then filter off the crystals and leave the impurities behind in the solution.

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Chromatography separates the dissolved components of a mixture. A spot of the mixture is placed on a start line; a solvent then rises up the paper (or TLC plate) and carries each component a different distance, because each has a different solubility / attraction to the paper. The component that is more soluble in the solvent travels further.

Each component is identified by its retardation factor, Rf — the distance its spot moved compared with how far the solvent moved.

Derived rule
The retardation (retention) factor — a ratio, so it has no units and is always between 0 and 1.
retardation factor (no units, 0 < R_{f} < 1)
from the start line to the centre of the spot (cm)
from the start line to the solvent front (cm)
Always less than 1: The spot can never travel further than the solvent front, so Rf is always between 0 and 1 and has no units. A larger Rf means the component is more soluble in the solvent (it moved further).

Worked example — calculating Rf

On a chromatogram, a spot of dye Y travels 3.6 cm from the start line while the solvent front travels 8.0 cm. Calculate the Rf value of dye Y.

Solution

  1. Formula first — write the relationship before the numbers:
  2. Substitute the two measured distances (both in cm, so the units cancel):
  3. Work it out — the answer is a ratio with no units:

Final answer

Rf = 0.45 (no units, as expected between 0 and 1).

How this is tested: S1.1.3 shows up two ways.

- Paper 1A (MCQ): identify the best technique for a given mixture, or determine an Rf value by reading distances off a chromatogram. - Paper 1B / Paper 2: a longer suggest / outline a sequence question — typically separating a multi-component solid mixture and recovering each part.
Scoring the sequence: For 'separate and recover X, Y and Z', name a technique and the property it uses for each part, in a sensible order. Use a unique property to pick one component off at a time (e.g. magnetism first, then solubility).

IB-style question — separating sand, salt and iron

A solid mixture contains sand (insoluble), table salt (soluble in water) and iron filings. Outline a sequence of steps to separate and recover all three components as pure solids. [4]

How to score the marks

  1. Mark 1 — remove the iron. Use a magnet to attract and remove the iron filings (iron is magnetic; sand and salt are not).
  2. Mark 2 — dissolve the salt. Add water and stir: the salt dissolves but the sand does not (difference in solubility).
  3. Mark 3 — filter. Filter the mixture: the insoluble sand stays as the residue on the filter paper; the salt solution passes through as the filtrate.
  4. Mark 4 — recover the salt. Evaporate / crystallise the filtrate to drive off the water and leave solid salt behind.

Final answer

Magnet → iron. Add water, dissolve salt. Filter → sand (residue). Evaporate the filtrate → salt.

Try an IB Exam Question — Free AI Feedback

Test yourself on Separation techniques. Write your answer and get instant AI feedback — just like a real IB examiner.

In a chromatography experiment, a spot of food colouring travels 5.4 cm from the start line while the solvent front travels 12.0 cm in the same time.

the Rf value of the food colouring. [2]
[2 marks]

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