The big idea: A buffer is a solution that resists a change in pH when a small amount of acid or alkali is added.
It is made from a conjugate acid–base pair held together in solution:
- a weak acid + its conjugate base (e.g. ethanoic acid + sodium ethanoate) → an acidic buffer - a weak base + its conjugate acid (e.g. ammonia + ammonium chloride) → a basic (alkaline) buffer
Both members must be present in appreciable amounts, so there is a large reservoir of each.
Two equilibria mop up added H⁺ and OH⁻: Take the acidic buffer HA / A⁻. The added ions are removed by the two members of the pair:
- add H⁺ → it is mopped up by the conjugate base: A⁻ + H⁺ → HA - add OH⁻ → it is mopped up by the weak acid: HA + OH⁻ → A⁻ + H2O
Because large reserves of both HA and A⁻ are present, the ratio [A⁻]/[HA] barely changes, so the pH barely changes. The buffer is consumed only when one member runs low.
A basic buffer works the same way with the pair NH3 / NH4⁺: NH3 mops up added H⁺ (NH3 + H⁺ → NH4⁺) and NH4⁺ mops up added OH⁻ (NH4⁺ + OH⁻ → NH3 + H2O).
The pH of a buffer is set by the pK_{a} of the weak acid and the ratio of conjugate base to acid. Rearranging the Ka expression and taking −log of both sides gives a tidy equation.
- the pH of the buffer solution
- −log K_{a} of the weak acid
- concentration of the conjugate base (the salt)
- concentration of the weak acid
pH = pKa at the half-equivalence point: Notice what the ratio does:
- if [A⁻] = [HA], the log term is log(1) = 0, so pH = pK_{a} - more conjugate base than acid → log > 0 → pH above pKa - more acid than conjugate base → log < 0 → pH below pKa
This is why a buffer is most effective near pH = pKa, and why the pH at the half-equivalence point of a titration reads off the pKa directly.
- equal amounts of acid and conjugate base
- so pH = pK_{a} exactly
Worked example — pH of an ethanoic acid buffer
A buffer is made by mixing 0.20 mol dm⁻³ ethanoic acid, CH3COOH (Ka = 1.8 × 10⁻⁵ mol dm⁻³), with 0.30 mol dm⁻³ sodium ethanoate, CH3COONa. Calculate the pH of the buffer.
Solution
- First find pKa of the weak acid:
- Formula first — the Henderson–Hasselbalch equation (the salt is the conjugate base A⁻):
- Substitute (conjugate base 0.30, acid 0.20):
- Evaluate the log term and add:
Final answer
pH = 4.92 (slightly above pKa because there is more conjugate base than acid).
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Adding base from a burette into an acid (or vice versa) and plotting pH against volume added gives a titration pH curve. Its shape depends on whether the acid and the base are strong or weak, and three features matter for every curve: the buffer region (a gentle slope), the vertical jump near the endpoint, and the equivalence point (where stoichiometrically equal amounts have reacted).
Equivalence-point pH is NOT always 7: At the equivalence point the salt formed governs the pH:
- strong acid + strong base → neutral salt → equivalence pH = 7 - weak acid + strong base → salt of a weak acid hydrolyses → equivalence pH > 7 (basic) - strong acid + weak base → salt of a weak base hydrolyses → equivalence pH < 7 (acidic) - weak acid + weak base → small, ill-defined jump → equivalence pH ≈ 7 but no sharp vertical (hard to titrate)
The buffer region appears with a weak partner: Whenever a weak acid (or weak base) is being titrated, a buffer region forms in the middle of the curve — the weak acid and the conjugate base it is being turned into coexist, so the pH rises only gently. The midpoint of that buffer region is the half-equivalence point, where pH = pK_{a}. A strong–strong titration has no buffer region (no weak conjugate pair).
Below is the shape of a weak acid titrated with a strong base (e.g. ethanoic acid with sodium hydroxide), read as pH at key volumes — note the buffer plateau, the half-equivalence point where pH = pKa, and the vertical jump up to a basic equivalence point:
| Volume of NaOH added | What is present | Approx. pH | Region |
|---|---|---|---|
| 0 cm³ (start) | weak acid only | ≈ 3 | low start (weak acid, not 1) |
| half-equivalence | [HA] = [A⁻] | = pKa (≈ 4.7) | centre of buffer region |
| just before equivalence | mostly A⁻ | ≈ 6–7 | top of buffer region |
| equivalence point | salt A⁻ only | ≈ 8.7 (> 7) | midpoint of vertical jump |
| just after equivalence | excess OH⁻ | ≈ 11 | vertical jump → levelling |
| large excess | excess strong base | ≈ 12–13 | plateau |
Weak acid titrated with a strong base: a gentle buffer region (pH = pKa at the half-equivalence point), then a vertical jump up to a basic equivalence point (pH > 7).
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An indicator is itself a weak acid: An acid–base indicator is a weak acid, HIn, whose acid form and conjugate base have different colours:
HIn ⇌ H⁺ + In⁻ (one colour ⇌ another colour)
Adding H⁺ pushes it to the coloured HIn form; adding OH⁻ pulls it to the In⁻ form. The colour changes over a narrow pH window — its colour-change range, centred roughly on the indicator's pK_{a}(In).
The selection rule: Choose an indicator whose pK_{a}(In) — i.e. its colour-change range — falls within the vertical jump at the equivalence point of the titration.
The sharp vertical jump means a single drop of titrant sweeps the pH through several units, so any indicator that changes colour inside that jump flips sharply at (essentially) the equivalence point:
- weak acid + strong base (equivalence > 7) → phenolphthalein (8.3–10.0) ✓; methyl orange would change far too early - strong acid + weak base (equivalence < 7) → methyl orange (3.1–4.4) ✓; phenolphthalein would change too late - strong acid + strong base (equivalence 7, huge jump ≈ 3–11) → almost any indicator works - weak acid + weak base → no sharp jump, so no indicator gives a clean endpoint (use a pH meter)
The three common indicators and their colour-change ranges on the pH scale — pick the one whose range sits inside the titration's vertical jump:
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