Electrophilic addition to alkenes
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Question
What is an electrophile?
Answer
An **electron-pair acceptor** — an electron-poor (often positive) species attracted to an electron-rich centre such as a C=C. Examples: Br_{2}, HBr, H⁺.
Question
Why is the C=C double bond reactive?
Answer
It is **electron-rich** (two shared pairs / exposed π electrons), so it readily donates electrons and attacks electrophiles.
Question
What is an addition reaction?
Answer
Two molecules join to form **one** product; the C=C opens to a single bond and the reactant adds across it. **Nothing leaves**.
Question
Saturated vs unsaturated?
Answer
Saturated = only **single** bonds (alkane); unsaturated = has a **C=C** (alkene) so more atoms can be **added**.
Question
Describe the two curly arrows in electrophilic addition (Br_{2}).
Answer
Arrow 1: the **C=C π electrons → a bromine** (new bond). Arrow 2: the **Br–Br bond → the other bromine**, which leaves as Br⁻.
Question
Product of ethene + Br_{2}?
Answer
**1,2-dibromoethane, CH_{2}BrCH_{2}Br** — one bromine adds to each carbon.
Question
Product of ethene + HBr?
Answer
**Bromoethane, CH_{3}CH_{2}Br** — H and Br add across the C=C.
Question
Product of ethene + steam (H_{2}O)?
Answer
**Ethanol, CH_{3}CH_{2}OH** — water adds across the C=C with an H_{3}PO_{4} catalyst at high T and P.
Question
Product of ethene + H_{2}?
Answer
**Ethane, CH_{3}CH_{3}** (saturated) — hydrogen adds across the C=C with a Ni catalyst.
Question
What is the test for unsaturation?
Answer
Add **bromine water**: an **alkene decolourises** it (orange → colourless); an **alkane** gives **no change**.
Question
What is Markovnikov's rule?
Answer
For an unsymmetrical alkene + HX, the **H adds to the carbon that already has more hydrogens**, giving the **major** product.
Question
Major product of propene + HBr?
Answer
**2-bromopropane, CH_{3}CHBrCH_{3}** — H goes to the CH_{2} end, Br to the middle carbon (Markovnikov).
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Topic 6.4 hub
Electron-pair sharing reactions
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