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NotesBiology HLTopic 3.8Estimating population size & sampling
Back to Biology HL Topics
3.8.33 min read

Estimating population size & sampling

IB Biology • Unit 3

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Contents

  • Why we estimate, not count
  • The two sampling methods
  • Exam-style question
The big idea: Counting every single organism in a habitat is almost always impossible — there are too many, they hide, and many of them move.

So ecologists estimate the population size by counting a small sample and scaling up to the whole habitat.

The method you choose depends on whether the organism moves: quadrats for still organisms like plants, and capture–mark–release–recapture for animals that move.
Population
All the organisms of the same species living in the same area at the same time.
Population size
The total number of individuals of that species in the area — the value we are trying to estimate.
Sample
A small part of the population that is actually counted, used to estimate the whole.
Random sampling
Choosing sample positions by chance (for example using random numbers as coordinates) so the sample is not biased.
Quadrat
A square frame of known area placed on the ground; the organisms inside it are counted.
Why sampling must be RANDOM: If you place your quadrats where the plants 'look nice' or are easy to reach, your sample is biased and the estimate is wrong.

Choosing positions at random (for example by generating random coordinates) makes the sample representative of the whole habitat.
Moves or not? That decides the method: Plants and other non-moving organisms stay put, so you can count them in fixed areas → use quadrats.

Animals move, so they will not sit still inside a quadrat → use capture–mark–release–recapture instead.

There are two methods on the syllabus. Quadrats handle organisms that stay put; capture–mark–release–recapture handles organisms that move.

Both work the same way underneath — count a sample, then scale up to estimate the whole population.

MethodBest forHow it estimates the population
Quadrat samplingPlants and other organisms that do not move (sessile / slow-moving)Count organisms in several small sample areas (quadrats), find the mean per quadrat, then scale up to the whole habitat
Capture–mark–release–recaptureAnimals that move around (motile), so they cannot be counted in a fixed areaMark a first sample, release them, then see what proportion of a second sample is already marked, and use the Lincoln index to estimate the total
Method 1 — quadrat sampling (for plants): Place several quadrats at random positions in the habitat and count the organisms inside each one.

Find the mean number per quadrat, then scale up: multiply by how many quadrat-sized areas would fit in the whole habitat.

Example: if a 1 m² quadrat holds a mean of 8 daisies and the field is 500 m², the estimate is 8 × 500 = 4000 daisies.
Method 2 — capture–mark–release–recapture (for animals): You cannot count moving animals in a fixed area, so instead you compare two samples:

Capture a first sample and count it (this is M). Mark each one harmlessly and release them.

Later, recapture a second sample (size n) and count how many are already marked (this is m).

The proportion that is marked tells you how big the whole population must be — worked out with the Lincoln index.
StepWhat you doWhat it gives you
1. CaptureCatch a first sample of the animals and count themM = number marked
2. Mark & releaseMark each one harmlessly, then release them back into the habitatmarked animals mix back into the population
3. RecaptureAfter time to mix, catch a second sample and count itn = size of the second sample
4. Count marksCount how many of the second sample are already markedm = number recaptured that were marked
5. CalculateUse the Lincoln index: N = (M × n) ÷ mN = estimated total population size
The Lincoln index: The estimate comes from one short calculation, the Lincoln index:

N = (M × n) ÷ m

where M = number marked in the first sample, n = total caught in the second sample, and m = number in the second sample that were already marked.

The logic: the marked fraction of the second sample (m ÷ n) should match the marked fraction of the whole population (M ÷ N) — rearranging gives N = (M × n) ÷ m.

Quadrat sampling

  • For non-moving organisms (plants)
  • Count organisms in random quadrats
  • Find the mean per quadrat
  • Scale up to the whole habitat area

Capture–mark–recapture

  • For moving animals
  • Mark a first sample, release, then recapture
  • Use the proportion marked in sample 2
  • N = (M × n) ÷ m (Lincoln index)
A memory hook: Sit still → quadrat. Runs away → recapture.

For the Lincoln index, remember the two marked numbers go together: M (marked at the start) on top, m (marked when you come back) on the bottom.

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How this is tested: On Paper 1B / Paper 2 an Explain or Describe question commonly asks how capture–mark–release–recapture could estimate a moving animal's population (for example a tick or insect population) — give the steps in order and name the Lincoln index.

A data-style follow-up gives you values for M, n and m and asks you to Calculate the estimated population — show N = (M × n) ÷ m and the working.

A higher-mark version asks you to state the assumptions that must hold for the estimate to be valid (even mixing, no births/deaths, marks not lost).

IB-style question — describe capture–mark–release–recapture

A student wants to estimate the size of a tick population in a meadow. Describe how the capture–mark–release–recapture method could be used to do this. [3]

How to score all three marks

  1. Capture and mark a first sample. Catch a first sample of ticks, count them and mark each one harmlessly, then release them back into the meadow.
  2. Allow mixing, then recapture. Give the marked ticks time to mix back into the population, then catch a second sample and count how many are already marked.
  3. Use the proportion to estimate the total. The proportion marked in the second sample is used in the Lincoln index, N = (M × n) ÷ m, to estimate the total population size. (Mark 1: capture, mark and release a first sample. Mark 2: recapture a second sample and count the marked ones. Mark 3: use the proportion marked / Lincoln index to estimate the total.)

Final answer

Catch, mark and release a first sample; allow them to mix; recapture a second sample and count how many are marked; then use the proportion marked (Lincoln index, N = (M × n) ÷ m) to estimate the whole population.

✓ Why this scores full marks: The three marks are three distinct stages — mark a first sample, recapture a second, and use the proportion marked to scale up.

Naming the Lincoln index and saying the result is an estimate of the total locks in the final mark.
StepWhat you doWhat it gives you
1. CaptureCatch a first sample of the animals and count themM = number marked
2. Mark & releaseMark each one harmlessly, then release them back into the habitatmarked animals mix back into the population
3. RecaptureAfter time to mix, catch a second sample and count itn = size of the second sample
4. Count marksCount how many of the second sample are already markedm = number recaptured that were marked
5. CalculateUse the Lincoln index: N = (M × n) ÷ mN = estimated total population size

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the sampling method used to estimate the population size of an animal that moves around its habitat. [1 mark]

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