The big idea: A triglyceride is the main kind of fat and oil in living things.
It is built from two kinds of smaller molecule: one glycerol plus three fatty acids.
The name is a clue — tri (three) + glyceride (built on glycerol) = three fatty acids attached to one glycerol.
| Part of a triglyceride | What it is | How many |
|---|---|---|
| Glycerol | A small 3-carbon molecule with three —OH (hydroxyl) groups | 1 — the backbone |
| Fatty acid | A long hydrocarbon chain ending in a —COOH (carboxyl) group | 3 — one per —OH |
| Ester bond | The bond formed where a fatty acid joins the glycerol | 3 — one per fatty acid |
The labelled triglyceride: glycerol backbone on the left, three fatty-acid tails, and the three ester bonds where they join.
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- Triglyceride
- A lipid made of one glycerol joined to three fatty acids. Triglycerides are the fats (solid) and oils (liquid) of living things.
- Glycerol
- A small 3-carbon molecule that forms the backbone of a triglyceride. It has three hydroxyl (—OH) groups, one for each fatty acid.
- Fatty acid
- A long chain of carbon and hydrogen (a hydrocarbon tail) ending in a carboxyl (—COOH) group, which is where it joins the glycerol.
Picture one triglyceride: Think of an E shape: a short glycerol backbone down the side, with three long fatty-acid tails sticking out.
Each tail joins the backbone at one point — so there are three joins in total.
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Glycerol and the fatty acids join by a reaction called condensation.
Each time a fatty acid joins the glycerol, one water molecule (H₂O) is removed and a new bond called an ester bond forms. Because a triglyceride has three fatty acids, three ester bonds form and three water molecules are released in total.
- Condensation
- A reaction that joins two molecules together and removes a molecule of water (H₂O) as it forms the new bond.
- Ester bond
- The bond formed between a fatty acid and glycerol in a triglyceride. It is made by condensation (and broken by hydrolysis).
- Hydrolysis
- The reverse of condensation: a reaction that splits a molecule apart by adding water (H₂O). 'Hydro' = water, 'lysis' = splitting.
A triglyceride: one glycerol backbone joined to three fatty acids by three ester bonds. Building it is condensation (3 H₂O removed); breaking it is hydrolysis (3 H₂O added).
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Condensation builds, hydrolysis breaks: Building a triglyceride = condensation. Three ester bonds form; three H₂O are removed (one per ester bond).
Breaking a triglyceride = hydrolysis. Three H₂O are added back, the three ester bonds break, and you get the original glycerol + three fatty acids again.
So the products of hydrolysing one triglyceride are 1 glycerol and 3 fatty acids.
Saturated vs unsaturated fatty acids: Fatty-acid tails come in two types, depending on the bonds between their carbon atoms.
A saturated fatty acid has only single bonds (C–C) between its carbons — it is 'saturated' with as many hydrogens as it can hold, and the chain is straight.
An unsaturated fatty acid has one or more double bonds (C=C) between carbons. Each double bond puts a kink (bend) in the chain.
Saturated fatty acid (straight chain, single C–C bonds only) vs unsaturated fatty acid (a C=C double bond puts a kink in the chain).
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Saturated fatty acid
- No C=C double bonds — only single C–C bonds
- Holds the maximum number of hydrogen atoms
- Chain is straight — molecules pack closely
- Tends to be solid at room temperature (e.g. butter, animal fat)
Unsaturated fatty acid
- Has one or more C=C double bonds
- Holds fewer hydrogens (not full / not 'saturated')
- Each double bond puts a kink — molecules pack loosely
- Tends to be liquid at room temperature (e.g. olive oil, plant oils)
A memory hook: Saturated = Straight + Solid (think butter).
Unsaturated = the double bond Undoes the straightness — a kinked, usually liquid oil (think olive oil).
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How this is tested: On Paper 2 a labelled triglyceride diagram is common: you identify the ester bond, name the reaction that formed it (condensation), and identify the glycerol backbone.
You also state whether a fatty acid is saturated or unsaturated by looking for a C=C double bond in its chain.
On Paper 1A you may identify the products of hydrolysing a triglyceride (glycerol + 3 fatty acids), or pick which broken-down molecule came from an unsaturated fat (the one with a double bond).
IB-style question — a labelled triglyceride
A diagram shows a triglyceride: a short backbone on the left joined to three long chains, one chain containing a C=C double bond. (a) Name the molecule that forms the backbone. (b) Name the reaction that forms the bonds joining the chains to the backbone. (c) State the type of fatty acid shown by the chain containing the double bond. [3]
How to score all three marks
- (a) Backbone = glycerol. The short 3-carbon molecule that the three chains attach to is glycerol. (It is the part with the three —OH groups before the bonds form.)
- (b) Reaction = condensation. The fatty-acid chains join the glycerol by condensation, which forms an ester bond and removes a water molecule each time. (Naming it 'condensation' scores the mark; 'esterification' is also accepted.)
- (c) Fatty acid type = unsaturated. A chain containing a C=C double bond is an unsaturated fatty acid. (A chain with only single C–C bonds would be saturated.)
Final answer
(a) Glycerol. (b) Condensation (forming ester bonds). (c) Unsaturated, because the chain contains a C=C double bond.
The labelled triglyceride: glycerol backbone on the left, three fatty-acid tails, and the three ester bonds where they join.
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What the diagram should show: Make sure you can point to each part: the glycerol backbone, the three fatty-acid tails, and the three ester bonds where they join.
A straight tail = saturated; a tail with a kink at a C=C = unsaturated.