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c059741
NotesPhysicsTopic 5.5
Unit 5 · Nuclear and quantum physics · Topic 5.5

IB Physics — Fusion and stars

Topic 5.5 of IB Physics covers Fusion and stars, which is part of Unit 5: Nuclear and quantum physics. Students explore key concepts including Nuclear fusion and stellar equilibrium, Stellar lifetime and mass loss, Luminosity, apparent brightness and distance, and more. A strong understanding of fusion and stars is essential for IB Physics exams and builds the foundation for connected topics across the syllabus.

Exam technique guidePractice questions

Key concepts in Fusion and stars

Key Idea: This topic is the physics of stars, from the reaction that powers them to how they live, shine and die. It ties together six ideas: fusion releases energy from a mass defect (E = mc²); the outward pressure it creates balances gravity to keep a star stable; a star has a finite lifetime set by its fuel and its luminosity; we measure stars by their brightness and distance; we read their temperature, size and type from their light (Wien, Stefan-Boltzmann, the H-R diagram); and they end their lives — and forge the heavier elements — according to their mass. It is examined on both papers. Paper 1A is quick multiple-choice — which conditions allow fusion, how brightness changes with distance, a parallax distance, where a star sits on the H-R diagram, the order of a life cycle. Paper 2 is longer structured work — calculate the energy released in MeV, 'show that' a lifetime is about N years, estimate a mass lost or a stellar radius, find a radius ratio from L and T, or outline how an element is confirmed in a star.

📋 Key formulas

Five of these carry the data-booklet badge (look for it). The lifetime relation t = E/L is not printed separately — you build it from 'luminosity = energy used each second', so you remember that one. The mass lost Δm = E/c² and the radius ratio are just E = mc² and Stefan-Boltzmann rearranged.

E=mc2E = mc^{2}E=mc2
Mass-energy equivalence (given). Here m is the mass defect Δm — the missing mass when nuclei fuse. In MeV, multiply Δm (in u) by 931.5; use it backwards (Δm = E ÷ c²) for the mass a star loses by radiating.
EEE
energy released by the reaction (J, or MeV)
mmm
mass that disappears — the mass defect Δm (kg, or u)
ccc
speed of light, 3.00 × 10⁸ m s⁻¹ (given constant)
t=ELt = \frac{E}{L}t=LE​
Main-sequence lifetime = energy available ÷ rate of using it. NOT a booklet equation — it comes from luminosity being the energy radiated each second. Convert seconds to years by dividing by 3.16 × 10⁷.
ttt
main-sequence lifetime — how long the star keeps fusing hydrogen (s)
EEE
total energy the fusible hydrogen can release (J)
LLL
luminosity — the energy the star radiates each second (W = J s⁻¹)
b=L4πd2b = \frac{L}{4\pi d^{2}}b=4πd2L​
Apparent brightness — the inverse-square law (given). The star's power L spreads over a sphere of area 4π d², so b falls as 1/d²: twice as far → a quarter as bright.
bbb
apparent brightness — power received per unit area at the observer (W m⁻²)
LLL
luminosity — total power the star radiates in all directions (W)
ddd
distance from the star to the observer (m)
4πd24\pi d^{2}4πd2
surface area of the sphere the light has spread over (m²)
d (parsec)=1p (arc-second)d\,(\text{parsec}) = \frac{1}{p\,(\text{arc-second})}d(parsec)=p(arc-second)1​
Stellar parallax distance (given). Put the parallax angle in arc-seconds and the distance comes straight out in parsecs. A smaller angle means a farther star.
ddd
distance to the star, in parsecs (pc)
ppp
parallax angle — half the star's apparent yearly shift, in arc-seconds (″)
λmax T=2.9×10−3 m K\lambda_{max}\,T = 2.9\times10^{-3}\ \text{m K}λmax​T=2.9×10−3 m K
Wien's displacement law (given). Peak wavelength × absolute temperature is a constant, so they are inversely related — a shorter (bluer) peak means a hotter star. Put λ_{max} in metres.
λmax\lambda_{max}λmax​
peak wavelength — where the star's radiation is most intense (m)
TTT
surface (absolute) temperature of the star (K)
2.9×10−32.9\times10^{-3}2.9×10−3
Wien's constant, 2.9 × 10⁻³ m K (given)
L=σAT4L = \sigma A T^{4}L=σAT4
Stefan-Boltzmann law (given). For a star A = 4πR², so L = σ(4πR²)T⁴ and L ∝ R²T⁴. The T⁴ makes temperature dominate; for two stars take the RATIO so σ and 4π cancel.
LLL
luminosity — total power the star radiates (W)
σ\sigmaσ
Stefan-Boltzmann constant, 5.67 × 10⁻⁸ W m⁻² K⁻⁴ (given)
AAA
surface area of the star; for a sphere A = 4πR² (m²)
TTT
surface (absolute) temperature of the star (K)

🌟 The six ideas at a glance

IdeaKey relationshipWhat to remember
Fusion & equilibriumE = mc² (Δm × 931.5 for MeV)Light nuclei fuse → product lighter → mass defect becomes energy. Needs high T + high density to beat Coulomb repulsion. Outward pressure (radiation + hot gas) balances gravity → stable radius.
Lifetime & mass losst = E ÷ L ; Δm = E ÷ c²Lifetime = fuel's energy ÷ luminosity. Only ~10–12% of mass is core hydrogen, ~0.7% of that becomes energy. Bright stars die young. Mass lost = energy radiated ÷ c².
Brightness & distanceb = L/(4π d²) ; d = 1/pLuminosity L is fixed (total power out); apparent brightness b falls as 1/d². Distance from parallax: d(parsec) = 1/p(arc-second), smaller angle → farther.
Wien's lawλₘₐₓ T = 2.9 × 10⁻³Read the peak wavelength → get the surface temperature. Shorter (bluer) peak = hotter. λₘₐₓ in metres.
Stefan-BoltzmannL = σ(4πR²)T⁴ → L ∝ R²T⁴Links luminosity, radius and temperature. The T⁴ dominates. Radius ratio: RB/RA = √(LB/LA) ÷ (TB/TA)².
H-R diagram & evolutionposition → type ; mass → fateTemperature hot on the LEFT, luminosity up. Type from position: main sequence / red giant / white dwarf. Mass decides the ending; massive stars fuse heavier elements up to iron.

💡 Luminosity vs apparent brightness — the distinction that recurs

Luminosity LApparent brightness b
What it isTotal power the star radiates, in all directionsPower you actually receive, per square metre
Depends on distance?No — a fixed property of the star itselfYes — the same star looks dimmer farther off (b ∝ 1/d²)
Unitwatts (W)watts per square metre (W m⁻²)
Where it appearsThe vertical axis of the H-R diagram; set by R²T⁴What a detector measures; b = L/(4π d²)
Luminosity is the total power the star pours out (fixed). Apparent brightness is what reaches us per m² (it drops with distance). The H-R diagram and Stefan-Boltzmann use luminosity; a detector reads apparent brightness — read which one the question gives you. And the temperature axis runs backwards on the H-R diagram: hot stars are on the LEFT, cool ones on the right.

✏️ Worked exam-style questions

IB-style questionCalculate[2 marks]

Deep in a star's core, light nuclei fuse into a single heavier nucleus. The combined mass of the original nuclei exceeds the mass of the product by a mass defect Δm = 0.022300 u. Calculate the energy released by this reaction, in MeV. (1 u = 931.5 MeV c⁻².)

🔒 Model answer plan

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IB-style questionShow that[4 marks]

A main-sequence star, Vega-B, has mass M = 2.0 × 10³⁰ kg. About 12% of its mass is hydrogen in the core that can fuse, and 0.70% of that fusible mass is released as energy. Its luminosity is L = 6.0 × 10²⁶ W. Show that its main-sequence lifetime is about 8 × 10⁹ years. (c = 3.00 × 10⁸ m s⁻¹; 1 year ≈ 3.16 × 10⁷ s.)

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IB-style questionCalculate[4 marks]

A star has luminosity L = 3.2 × 10²⁸ W and is at a distance d = 5.0 × 10¹⁸ m from Earth. (a) Calculate its apparent brightness as seen from Earth. (b) A second, fainter star has a measured parallax angle of p = 0.020 arc-seconds. Find its distance, in parsecs.

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IB-style questionDetermine[4 marks]

Star X has a black-body peak at λₘₐₓ = 725 nm and Star Y has a peak at λₘₐₓ = 290 nm. (a) Find the surface temperature of each. (b) Star Y is also 9 times as luminous as Star X — find the ratio of Star Y's radius to Star X's radius. (Wien's constant = 2.9 × 10⁻³ m K.)

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IB-style questionIdentify[4 marks]

On an H-R diagram, Star P sits at the bottom-left (hot, very dim) and Star Q sits at the top-right (cool, very bright). (a) State the type of each star and which has the larger radius, with a reason. (b) Star Q has a mass of about fifteen times the Sun's. Identify, in order, the stages it will pass through to the end of its life.

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🧠 Quick self-check

Tap each card to reveal the answer.

What two conditions let a star's core fuse nuclei, and why? Very high temperature (gives the positive nuclei enough speed to overcome the Coulomb repulsion) AND very high density / pressure (makes those fast collisions frequent enough).

How do you turn a mass defect in u into energy in MeV? Multiply Δm (in u) by 931.5, because 1 u = 931.5 MeV c⁻². (This is just E = mc² with the conversion built in.) For joules, convert Δm to kg first, then × c².

How do you estimate a star's main-sequence lifetime, and the mass it loses? Lifetime t = E ÷ L (fuel's energy ÷ luminosity), then ÷ 3.16 × 10⁷ for years. Only ~10–12% of the mass is core hydrogen and ~0.7% of that becomes energy. Mass lost by radiating: Δm = E ÷ c².

What happens to apparent brightness if a star is three times farther away? It falls to one ninth (b ∝ 1/d², so 1/3² = 1/9). The luminosity is unchanged — only the apparent brightness depends on distance.

Which law gives a star's temperature, and which gives its luminosity/size? Wien (λₘₐₓ T = 2.9 × 10⁻³) turns the peak wavelength into the temperature. Stefan-Boltzmann (L = σ(4πR²)T⁴, so L ∝ R²T⁴) links luminosity, radius and temperature — use the ratio for a radius.

How does a star's mass decide its fate? Low-mass (Sun-like): main sequence → red giant → planetary nebula → white dwarf. High-mass: main sequence → red supergiant → supernova → neutron star or black hole. Only massive stars fuse heavier elements (up to iron).


🎯 Exam tips

Exam Tips

  • Energy released: find the mass defect FIRST (the product is lighter), then E = mc². In MeV, just multiply Δm (in u) by 931.5; for joules, convert Δm to kg then × c².
  • Equilibrium: gravity pulls IN, the PRESSURE from fusion's radiation + hot gas pushes OUT. Say it is the pressure (not the reactions themselves) that balances gravity, and that the balance is self-correcting.
  • Lifetime = fuel's energy ÷ luminosity: t = E ÷ L. Cut the fuel down twice (core fraction, then ~0.7% conversion) before E = mc², and convert seconds to years (÷ 3.16 × 10⁷). Mass lost = E ÷ c².
  • Keep luminosity (total power out, fixed) and apparent brightness (received per m², falls as 1/d²) apart. Inverse-square: twice as far → a quarter as bright. Equal brightness ⇒ d ∝ √L.
  • Parallax: d(parsec) = 1/p, with p in ARC-SECONDS and d straight out in PARSECS. A smaller angle means a farther star.
  • Wien: T = 2.9 × 10⁻³ ÷ λₘₐₓ, with λₘₐₓ in METRES (nm → ×10⁻⁹). Stefan-Boltzmann: L = σ(4πR²)T⁴, so L ∝ R²T⁴. For two stars take the RATIO so σ and 4π cancel: RB/RA = √(LB/LA) ÷ (TB/TA)².
  • H-R diagram: temperature axis runs BACKWARDS (hot on the LEFT), luminosity UP. Read the type from the position; a cool star can still be bright if it is huge (red giant), a hot one dim if it is tiny (white dwarf).
  • Evolution: MASS decides the path — only massive stars go supernova (the Sun ends as a white dwarf). To confirm an element in a star: split its light, find the dark ABSORPTION lines, and match the pattern to that element in the lab.

What you'll learn in Topic 5.5

  • 5.5.1 Nuclear fusion and stellar equilibrium
  • 5.5.2 Stellar lifetime and mass loss
  • 5.5.3 Luminosity, apparent brightness and distance
  • 5.5.4 Stefan-Boltzmann and Wien laws for stars
  • 5.5.5 The Hertzsprung-Russell diagram and stellar classification
  • 5.5.6 Stellar evolution and nucleosynthesis
Suggested study order: Read the notes for each sub-topic below → test yourself with flashcards → attempt practice questions → review exam technique.

Study resources — 5.5 Fusion and stars

5.5.1

Nuclear fusion and stellar equilibrium

Notes
5.5.2

Stellar lifetime and mass loss

Notes
5.5.3

Luminosity, apparent brightness and distance

Notes
5.5.4

Stefan-Boltzmann and Wien laws for stars

Notes
5.5.5

The Hertzsprung-Russell diagram and stellar classification

Notes
5.5.6

Stellar evolution and nucleosynthesis

Notes

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Topic 5.5 Fusion and stars forms a core part of Unit 5: Nuclear and quantum physics in IB Physics. Mastering these concepts will strengthen your understanding of connected topics across the syllabus and prepare you for exam questions that require analysis, evaluation, and real-world application.

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