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NotesPhysicsTopic 6.1Linearizing relationships & testing a law
Back to Physics Topics
6.1.45 min read

Linearizing relationships & testing a law

IB Physics • Unit 6

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Contents

  • Straighten the line, then test the law
  • Choosing what to plot — and reading the gradient
  • Exam-style question
The big idea: A straight line is easy to read — its gradient is a single number.

So when a law is curved (like P getting bigger as V gets smaller), we re-plot it as a straight line: pick what to put on each axis so the graph comes out straight. This is linearizing.

Once it is straight you can do two things: read a physics quantity off the gradient, and test whether the data really obey the law.
What 'directly proportional' looks like: Two quantities are directly proportional when their graph is a straight line that passes through the origin (0, 0).

So to test a 'proportional' claim, you check both: is the line straight, and does it go through the origin?

Here is a curved law made straight. The gas law PV = constant is a curve if you plot P against V — but if you instead plot P against 1/V (one over the volume), the points fall on a straight line through the origin:

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Read it like y = mx + c: Compare your plotted variables to the line equation Y = mX + c:

- the thing on the up axis is Y - the thing on the across axis is X - the gradient m and intercept c are then physics quantities.

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Method: rearrange the law into the form Y = mX + c. Whatever multiplies the variable becomes the gradient. For example, the gas law PV = k rearranges to P = k × (1/V) — so plotting P (up) against 1/V (across) gives a straight line whose gradient is k.

Derived rule
The straight-line form. Match your two plotted quantities to Y and X; the gradient m and intercept c are then physics quantities.
the quantity plotted on the vertical axis (chosen so the graph is straight)
the quantity plotted on the horizontal axis
the gradient — equals a physics constant you are trying to find
the vertical intercept — usually 0 for a 'directly proportional' law
The gradient is a physics quantity: After linearizing, the gradient is never 'just a number' — it equals a constant in the law (a spring constant, a refractive index, a gas constant…). Always say what the gradient represents and give its units.
IB-style questionState[2 marks]

A student measures the time period T of a pendulum for several lengths L. Theory says T = k√L (T is proportional to the square root of L). The student wants a straight-line graph through the origin so they can find k from the gradient. (a) State what to plot on each axis. (b) State what the gradient represents.

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How this is tested: Paper 1B almost always builds a whole question around one experiment, and linearizing is the part that ties it together.

- What they ask: state what to plot to get a straight line · find a missing point's coordinates so you can plot it · explain how the graph decides whether a proposed law holds · show (with two data rows) that two quantities are not directly proportional. - The classic trap: assuming any straight-ish line means 'proportional'. It only counts as proportional if the line also passes through the origin.

An experiment measures how the depth d that a marker sinks depends on the water pressure P pushing on it. Theory predicts d = k√P, so the student plans to plot depth against root-pressure (√P). The graph below is straight and passes through the origin, supporting the law:

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IB-style questionDetermine[2 marks]

One table row reads pressure P = 9.0 kPa and depth d = 4.6 cm. For the depth-versus-root-pressure graph, determine the coordinates of the point this row should be plotted at.

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IB-style questionShow that[2 marks]

Suppose a classmate instead claims depth is directly proportional to pressure itself (d ∝ P). Using these two rows — P = 4.0 kPa with d = 3.1 cm, and P = 9.0 kPa with d = 4.6 cm — show that depth and pressure are not directly proportional.

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In a double-slit experiment the fringe separation s is measured for several screen distances D.

Theory predicts s = (λ/a)·D, where λ is the wavelength and a is the slit separation.

The student plots s on the vertical axis and wants a straight line through the origin so the gradient gives λ.

the quantity that should be plotted on the horizontal axis.
[1 mark]

Related Physics Topics

Continue learning with these related topics from the same unit:

6.1.1Measurement technique & choosing instruments
6.1.2Uncertainties & error propagation
6.1.3Graphing: plotting, best-fit lines & gradients
6.1.5Evaluating method & dimensional analysis
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