aimnova.
DashboardMy LearningPaper MasteryStudy Plan

Aimnova site navigation

Stay in the loop

Get the latest study resources and updates

New features, study tips and exam insights — straight to your inbox.

IB Diploma

  • IB Past Papers
  • IB Study Notes
  • IB Question Bank
  • IB Mock Exams
  • IB Revision

IB Subjects

  • IB Math AA
  • IB Math AI
  • IB Economics
  • IB Business Management
  • IB Physics
  • IB Biology
  • View all IB subjects→

IB Past Papers

  • IB Math AA HL Past Papers
  • IB Math AA SL Past Papers
  • IB Math AI HL Past Papers
  • IB Math AI SL Past Papers
  • IB Economics HL Past Papers
  • IB Economics SL Past Papers
  • IB ESS Past Papers
  • View all past papers→

Study Resources

  • Study Notes
  • Question Bank
  • Mock Exams
  • Flashcards
  • Revision Guide
  • Exam Skills
  • Command Terms
  • Grade Calculator
  • Exam Timetable 2026

Aimnova

  • Features
  • Pricing
  • For Teachers
  • For Schools
  • For Parents
  • About Us
  • Blog
  • Contact
aimnova.

AI-powered study platform for smarter revision, past-paper analysis and examiner-style feedback.

TermsPrivacyCookies·© 2026 Aimnova. All rights reserved.3bebe80

Aimnova is not affiliated with or endorsed by the International Baccalaureate Organization (IB).

NotesPhysicsTopic 2.5Resistance, Ohm's law and resistivity
Back to Physics Topics
2.5.25 min read

Resistance, Ohm's law and resistivity

IB Physics • Unit 2

Smart study tools

Turn reading into results

Move beyond passive notes. Answer real exam questions, get AI feedback, and build the skills that earn top marks.

Get Started Free

Contents

  • What resistance is
  • Ohm's law: V = IR
  • Exam-style question
The big idea: Push current through a thin, poor wire and only a trickle gets through; a fat copper one lets it flow freely. How hard a component makes it to push current through is its resistance.

A bigger resistance needs a bigger voltage (the push) for the same current.

Resistance is voltage ÷ current, and its unit is the ohm (Ω).

Measuring resistance: the ammeter (A) reads the current I through R; the voltmeter (V) reads the voltage across R. Then R = V ÷ I.

Interactive diagram

Explore the labelled diagram, charts and maps for this topic in full study mode.

Claim your free topic
Spot it: More resistance → less current for the same voltage.

To find a component's resistance you measure the voltage across it (with a voltmeter) and the current through it (with an ammeter), then divide.

Free preview

This is the free notes preview

You're reading the free notes. Aimnova Pro unlocks the full study experience — and you can try it with your first topic free to keep:

  • FlashcardsLock in vocabulary and key terms with spaced repetition.
  • Practice questionsAnswer exam-style questions and get instant AI marking.
  • Mock exams & past-paper vaultSit full mocks and see exactly how examiners award marks.
  • Personalised study planA daily plan built around your exam date and weak areas.
Start Studying Free Full access to Aimnova Pro · cancel anytime

Ohm's law links the three quantities. The voltage across a component equals the current through it times its resistance:

Ohm's law. The data booklet gives it as R = V ÷ I; rearranged, V = IR. V in volts, I in amps, R in ohms.
potential difference / voltage (V)
current (A)
resistance (Ω, ohms)

V = I R. Cover the one you want: two letters side by side → multiply (V = I R); one above the other → divide (R = V ÷ I, or I = V ÷ R).

Interactive diagram

Explore the labelled diagram, charts and maps for this topic in full study mode.

Claim your free topic
Reading the I–V graph: An I–V graph plots current against voltage.

For a fixed resistance the points lie on a straight line through the origin, and R = V ÷ I is the same at every point on it.

Animated graph

Watch the graph build step by step in study mode.

Claim your free topic
IB-style questionDetermine[2 marks]

A resistor's current–voltage graph is a straight line through the origin. At a voltage of 6.0 V the current is 1.5 A. Find its resistance.

Model answer plan

See the mark-by-mark plan — for / against / judgement, with marking guidance — in study mode.

Claim your free topic

Never wonder what to study next

Get a personalized daily plan based on your exam date, progress, and weak areas. We'll tell you exactly what to review each day.

Try Free Study PlanYour first topic is free to keep • No credit card required

How this is tested — resistance and Ohm's law are the backbone of the circuit questions:

Paper 1A

  • Read a resistance off an I–V graph (R = V ÷ I at a point).
  • Decide whether a component is ohmic or non-ohmic.

Paper 2

  • Use R = ρL/A to see how resistance changes when a wire's length or thickness changes.
The classic trap: Thinking a curved I–V graph means 'no resistance' — it just means the resistance changes (non-ohmic).
Ohmic vs non-ohmic: Ohmic = obeys Ohm's law: a straight I–V line through the origin, so R stays constant (e.g. a fixed resistor at steady temperature).

Non-ohmic = a curved I–V graph, so R changes with the current (e.g. a filament lamp, whose resistance rises as it heats up).

Animated graph

Watch the graph build step by step in study mode.

Claim your free topic
IB-style questionExplain[4 marks]

Component P has a straight I–V line through the origin; component Q is a filament lamp with a curved I–V graph. (a) State, with a reason, which component is ohmic. (b) Outline how the resistance of Q changes as the current through it increases.

Model answer plan

See the mark-by-mark plan — for / against / judgement, with marking guidance — in study mode.

Claim your free topic

Try an IB Exam Question — Free AI Feedback

Test yourself on Resistance, Ohm's law and resistivity. Write your answer and get instant AI feedback — just like a real IB examiner.

A potential difference of 12 V is applied across a fixed resistor and a current of 2.5 A flows through it.

the resistance of the resistor.
[2 marks]

Related Physics Topics

Continue learning with these related topics from the same unit:

2.1.1Internal energy and the particle model
2.1.2Specific heat capacity
2.1.3Latent heat and calorimetry
2.1.4Conduction, convection and radiation
View all Physics topics

Improve your exam technique

Command terms, paper structure, and mark-scheme tips for Physics

Previous
2.5.1Current, charge and potential difference
Next
Series and parallel circuits2.5.3

10 exam-style questions ready for you

Students who practice on Aimnova improve their scores by 15% on average. Get instant feedback that shows exactly how to improve your answers.

Practice Now — FreeView All Physics Topics