The big idea: Shine one colour of light through two narrow slits that are close together, and you get a row of equally spaced bright and dark bands — called fringes.
You have seen this already: Squint at a distant streetlight through a thin curtain or a fine umbrella and it smears into a little pattern of bright dots. Two slits make the same thing happen cleanly.
How the fringes form
- The light from the two slits overlaps on a screen.
- Bright = the two waves arrive in step (add up).
- Dark = they arrive out of step (cancel).
New words: Fringe = one of the bright or dark bands on the screen.
Fringe spacing s = the gap from one bright fringe to the next bright fringe.
Coherent = the two slits give light of the same wavelength with a fixed phase relationship — needed for a steady pattern.
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Spot it: The fringes are evenly spaced and the central one is the brightest. The spacing s is the same gap all the way across.
The set-up, step by step
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The fringe spacing depends on three things: the wavelength of the light, how far away the screen is, and how close the two slits are. They combine into one equation that is given in the data booklet.
- fringe spacing — gap between neighbouring bright fringes (m)
- wavelength of the light (m)
- distance from the slits to the screen (m)
- separation of the two slits (m)
Which way each one pushes the fringes: Bigger λ or bigger D → wider fringes (s up).
Bigger slit separation d → narrower fringes (s down), because d is on the bottom.
Memory aid for s = λD ÷ d. Cover the one you want: cover s → λD ÷ d; cover d → λD ÷ s. (Here λD on top, s and d on the bottom.)
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Reading s off a picture of fringes: Count the gaps, not the fringes: if 7 bright fringes span 12 cm (centre of the first to centre of the last), there are 6 gaps, so s = 12 ÷ 6 = 2.0 cm.
Counting from the centre, the n-th dark fringe has a path difference of (n − ½)λ.
Two slits 0.50 mm apart are lit by a laser. On a screen 2.0 m away the bright fringes are 2.4 mm apart. Find the wavelength of the light.
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How this is tested — double-slit questions come in two flavours:
Paper 2
- Plug into s = λD/d to find a missing quantity.
- Or find the angular separation of the fringes (an angle in radians, θ ≈ λ/d for small angles).
Paper 1A / short answer
- A suggest/explain — e.g. why a dark fringe (zero energy) still obeys energy conservation.
The classic trap: Mixing units — get every length into metres (mm = 10⁻³ m, nm = 10⁻⁹ m) before substituting.
Fringe angle in radians: Each bright fringe sits at an angle θ from the slits where d sin θ = nλ.
For the small angles in these experiments, sin θ ≈ θ (in radians), so neighbouring maxima are about λ/d apart, and the nearest minima either side of the centre are also λ/d apart in total.
Small-angle memory aid: θ ≈ λ ÷ d (radians). Cover θ → λ ÷ d. (λ on top, θ and d on the bottom.)
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In a double-slit experiment the slit separation is 0.25 mm and the wavelength is 5.0 × 10⁻⁷ m. Calculate, in radians, the angular separation of the two nearest minima either side of the central maximum.
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