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NotesPhysics HLTopic 3.3Double-slit interference
Back to Physics HL Topics
3.3.35 min read

Double-slit interference (Physics HL)

IB Physics • Unit 3

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Contents

  • The double-slit pattern
  • The fringe-spacing equation
  • Exam-style question
The big idea: Squint at a distant streetlight through a thin curtain or a fine umbrella and it smears into a little pattern of bright dots. The same thing happens cleanly when you shine one colour of light through two narrow slits that are close together.

The light from the two slits overlaps on a screen and makes a row of equally spaced bright and dark bands — called fringes.

Bright = the two waves arrive in step (add up); dark = they arrive out of step (cancel).
New words: Fringe = one of the bright or dark bands on the screen.

Fringe spacing s = the gap from one bright fringe to the next bright fringe.

Coherent = the two slits give light of the same wavelength with a fixed phase relationship — needed for a steady pattern.

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Spot it: The fringes are evenly spaced and the central one is the brightest. The spacing s is the same gap all the way across.

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The fringe spacing depends on three things: the wavelength of the light, how far away the screen is, and how close the two slits are. They combine into one equation that is given in the data booklet.

Given in the data booklet (double-slit fringe spacing). All four lengths in metres.
fringe spacing — gap between neighbouring bright fringes (m)
wavelength of the light (m)
distance from the slits to the screen (m)
separation of the two slits (m)
Which way each one pushes the fringes: Bigger λ or bigger D → wider fringes (s up).

Bigger slit separation d → narrower fringes (s down), because d is on the bottom.

Memory aid for s = λD ÷ d. Cover the one you want: cover s → λD ÷ d; cover d → λD ÷ s. (Here λD on top, s and d on the bottom.)

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IB-style questionCalculate[2 marks]

Two slits 0.50 mm apart are lit by a laser. On a screen 2.0 m away the bright fringes are 2.4 mm apart. Find the wavelength of the light.

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How this is tested — double-slit questions come in two flavours:

Paper 2

  • Plug into s = λD/d to find a missing quantity.
  • Or find the angular separation of the fringes (an angle in radians, θ ≈ λ/d for small angles).

Paper 1A / short answer

  • A suggest/explain — e.g. why a dark fringe (zero energy) still obeys energy conservation.
The classic trap: Mixing units — get every length into metres (mm = 10⁻³ m, nm = 10⁻⁹ m) before substituting.
Fringe angle in radians: Each bright fringe sits at an angle θ from the slits where d sin θ = nλ.

For the small angles in these experiments, sin θ ≈ θ (in radians), so neighbouring maxima are about λ/d apart, and the nearest minima either side of the centre are also λ/d apart in total.

Small-angle memory aid: θ ≈ λ ÷ d (radians). Cover θ → λ ÷ d. (λ on top, θ and d on the bottom.)

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IB-style questionCalculate[2 marks]

In a double-slit experiment the slit separation is 0.25 mm and the wavelength is 5.0 × 10⁻⁷ m. Calculate, in radians, the angular separation of the two nearest minima either side of the central maximum.

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the equation that relates the fringe spacing in a double-slit pattern to the wavelength of the light, the slit separation and the slit-to-screen distance, defining each symbol you use. [2 marks]

Related Physics HL Topics

Continue learning with these related topics from the same unit:

3.1.1Conditions for simple harmonic motion
3.1.2Period and frequency of SHM oscillators
3.1.3SHM graphs, phase and timing
3.1.4Energy in simple harmonic motion
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3.3.2Interference, path difference and coherence
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