Back to Topic 3.4 — Standing waves and resonance
3.4.2Physics SL12 flashcards

Harmonics, resonance and wavelength from a standing-wave pattern

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Card 1 of 123.4.2
3.4.2
Question

What is a node?

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All 12 Flashcards — Harmonics, resonance and wavelength from a standing-wave pattern

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Card 1definition

Question

What is a node?

Answer

A point on a standing wave that **never moves** (zero amplitude).

Card 2definition

Question

What is an antinode?

Answer

A point on a standing wave that swings with the **largest** amplitude.

Card 3definition

Question

What is the fundamental (1st harmonic)?

Answer

The **lowest** frequency at which a string or air column resonates — the standing-wave pattern with the fewest loops.

Card 4definition

Question

What is resonance?

Answer

When a system is driven at one of its **natural frequencies** and vibrates with a large amplitude — that is what makes a harmonic loud.

Card 5formula

Question

Wavelength condition for a string fixed at both ends (or a pipe open at both ends)?

Answer

**λ = 2L/n** for n = 1, 2, 3, … — n half-wavelengths fit into the length L.

Card 6formula

Question

Wavelength condition for a pipe closed at one end?

Answer

**λ = 4L/n** with **n = 1, 3, 5, …** (odd harmonics only — node at the closed end, antinode at the open end).

Card 7concept

Question

Are λ = 2L/n and λ = 4L/n in the data booklet?

Answer

**No** — you must memorise them. Only the wave equation v = fλ is given.

Card 8concept

Question

Why does a pipe closed at one end have only odd harmonics?

Answer

Its ends are different (node at the closed end, antinode at the open end), so only odd numbers of quarter-wavelengths fit: λ = 4L/n, n = 1, 3, 5, …

Card 9concept

Question

How far apart are two neighbouring nodes (or antinodes)?

Answer

**Half a wavelength.** So λ = 2 × the node-to-node spacing.

Card 10formula

Question

How do you turn a wavelength into a frequency?

Answer

Use the given wave equation **v = fλ**, rearranged to **f = v ÷ λ** (v is the wave speed — the speed of sound for a pipe).

Card 11example

Question

A 0.65 m string fixed both ends, wave speed 260 m s⁻¹ — fundamental frequency?

Answer

λ = 2L = 1.3 m; f = v/λ = 260/1.3 = 200 Hz.

Card 12example

Question

How can melted spots in a microwave give the microwave frequency?

Answer

The spots (antinodes) are half a wavelength apart; double the spacing for λ, then f = c/λ.

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IB Physics Harmonics, resonance and wavelength from a standing-wave pattern Flashcards | 3.4.2 | Aimnova | Aimnova