Conservation of angular momentum

Answer

Rotation's version of momentum: $L = I\omega$. Unit: **kg m² s⁻¹**.

Answer

When there is **no external torque** on the system.

Answer

$I_1\omega_1 = I_2\omega_2$.

Answer

I decreases, so ω increases to keep **L = Iω** constant.

Answer

$E_k = \tfrac{1}{2}I\omega^{2}$ (the rotational ½mv²).

Answer

$\tfrac{1}{2}mv^{2} + \tfrac{1}{2}I\omega^{2}$ — translational **plus** rotational.

Answer

It **quadruples** (E_k ∝ ω²).

Answer

**No** — angular momentum is conserved, but some kinetic energy is lost.

Answer

$L = I\omega$.

Answer

ω **decreases** (I up, L constant).

Answer

**kg m² s⁻¹** (or equivalently N m s).