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NotesMath AITopic 3.1Distance & midpoint in 3D
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3.1.21 min read

Distance & midpoint in 3D

IB Mathematics: Applications and Interpretation • Unit 3

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Contents

  • Distance in 3D space
  • Midpoint in 3D
  • Distance inside a solid
Extending to 3D: In 3D space, points have three coordinates (x, y, z).

The distance formula gains one extra term inside the square root — one for each axis.

The box for the two points: A(1, 0, 2) and B(4, 3, 6) sit at opposite corners, and the coordinate gaps 3, 3, 4 are its edges. The distance AB is the box's space diagonal, √(3² + 3² + 4²) = √34 ≈ 5.83 (not to scale).

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Worked example — distance in 3D

Find the distance between A(1, 0, 2) and B(4, 3, 6).

Step by step

  1. Write the general 3D distance formula. It is the straight-line gap between two points, found by squaring the difference along each axis, adding, then taking the square root.
  2. Substitute A(1, 0, 2) and B(4, 3, 6).
  3. Work out each squared difference and add.
  4. Take the square root.

Final answer

Distance AB ≈ 5.83 units (3 s.f.).

Where 3D distance appears in IB: IB questions often place a solid in a coordinate grid. You may be asked for the length of a space diagonal — the distance between two opposite corners of a cuboid.

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Average all three coordinates: The midpoint in 3D works exactly like 2D — just average the z-coordinates as well as the x and y.

Worked example — midpoint in 3D

Find the midpoint of A(2, −1, 4) and B(6, 3, 10).

Step by step

  1. Write the general 3D midpoint formula. The midpoint is the average of the two points, taken one coordinate at a time.
  2. Substitute A(2, −1, 4) and B(6, 3, 10).
  3. Simplify each coordinate.

Final answer

Midpoint M = (4, 1, 7).

Add then halve: Add the two coordinates and divide by 2 — never subtract (that gives a gap, not the middle). Given the midpoint and one end, the other end is B = 2M − A.

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Put a solid on a grid: A length inside a solid is just a 3D distance. Put one corner at the origin, read off the opposite corner, and apply the formula.

The cuboid from the question (6 × 4 × 3): one corner at the origin, the opposite corner at (6, 4, 3). The space diagonal (corner to opposite corner) is √(6² + 4² + 3²) = √61 ≈ 7.81 cm (not to scale).

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Worked example — space diagonal of a cuboid

A cuboid has length 6 cm, width 4 cm, and height 3 cm.

Find the length of the space diagonal (corner to opposite corner).

Step by step

  1. Write the general 3D distance formula. The space diagonal joins two opposite corners, so it is the distance between them.
  2. Place one corner at A(0, 0, 0) and the opposite corner at B(6, 4, 3), then substitute.
  3. Square each edge and add.
  4. Round to 3 s.f.

Final answer

The space diagonal is √61 ≈ 7.81 cm.

Common mistake: Square each difference separately. A frequent error is √(6+4+3) = √13 instead of √(36+16+9) = √61.

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Find the distance between the points A(2, 3, −1) and B(6, 0, 11). [2 marks]

Related Math AI Topics

Continue learning with these related topics from the same unit:

3.1.1Distance & midpoint in 2D
3.1.3Volume and Surface Area of 3D Solids
3.2.1Right-Angle Trigonometry
3.2.2Sine Rule and Cosine Rule
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