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NotesMath AI HLTopic 2.4
Unit 2 · Functions · Topic 2.4

IB Math AI HL — Features of a graph

IB Mathematics AI SL topic covering core concepts and exam-style applications.

Exam technique guidePractice questions

Key concepts in Features of a graph

Key Idea: Topic 2.4 is about describing the shape and behaviour of a graph: where it rises, where it falls, where it peaks or troughs, and how it behaves at its extremes. A local maximum is a peak — the function is higher there than at nearby points. A local minimum is a trough. An asymptote is a line the graph approaches but never reaches.

✅ Graph features and what they tell you

Example: Describe f(x) = x³ − 3x: GDC shows: local max at (−1, 2), local min at (1, −2). Increasing on: x < −1 and x > 1. Decreasing on: −1 < x < 1. Exponential: f(x) = 3⁻ˣ + 1: As x → ∞, 3⁻ˣ → 0, so f(x) → 1. Horizontal asymptote: y = 1 (the graph gets closer and closer but never reaches 1).
When describing increasing/decreasing intervals, use the x-values (not y-values) for the interval. A function can have more than one local maximum or minimum — use the GDC to find all of them within the domain shown.
Paper 2 (GDC allowed): Use the GDC 'maximum' and 'minimum' functions to find turning point coordinates. Then state the intervals of increase/decrease around those points. Paper 1: You may be given a sketch and asked to describe features in words. Use precise vocabulary: 'local maximum at x = 2, f(2) = 5', not just 'it goes up then down'.

IB-style question [6 marks]

The number of active users of an app, N thousand, t months after a redesign is modelled by N(t) = 400 · 0.7ᵗ + 60, for t ≥ 0. (a) Write down the number of active users at the moment of the redesign (t = 0). (b) State whether N is increasing or decreasing, and explain why. (c) Write down the equation of the horizontal asymptote and interpret it in context.

Step by step:

  1. (a) Substitute t = 0. Since 0.7⁰ = 1, the model gives the starting value.

    N(0)=400×1+60=460 thousand usersN(0) = 400 \times 1 + 60 = 460 \text{ thousand users}N(0)=400×1+60=460 thousand users
  2. (b) The base 0.7 is between 0 and 1, so the term 400 · 0.7ᵗ shrinks as t grows. The output falls over time, so N is decreasing.

  3. (c) As t → ∞, the term 400 · 0.7ᵗ → 0, leaving the constant.

    N→60  ⇒  horizontal asymptote N=60N \to 60 \;\Rightarrow\; \text{horizontal asymptote } N = 60N→60⇒horizontal asymptote N=60
  4. Interpret it: in the long run the user base levels off at about 60 thousand active users — the model never drops below this floor.

Final answer:

(a) 460 thousand users. (b) Decreasing — the base 0.7 < 1 makes the curve fall. (c) N = 60; the user base settles at about 60 thousand in the long run.

What you'll learn in Topic 2.4

  • 2.4.1 Local maxima and minima
  • 2.4.2 Increasing and decreasing intervals
  • 2.4.3 Asymptotes and graph behaviour
Suggested study order: Read the notes for each sub-topic below → test yourself with flashcards → attempt practice questions → review exam technique.

Study resources — 2.4 Features of a graph

2.4.1

Local maxima and minima

Notes
2.4.2

Increasing and decreasing intervals

Notes
2.4.3

Asymptotes and graph behaviour

Notes

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Topic 2.4 Features of a graph forms a core part of Unit 2: Functions in IB Math AI HL. Mastering these concepts will strengthen your understanding of connected topics across the syllabus and prepare you for exam questions that require analysis, evaluation, and real-world application.

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